Bunuel
Is \(xy < 6\) ?
(1) \(x < 3\) and \(-y > -2\)
(2) \(y^2 < 100\), \(\frac{1}{2} < x < \frac{2}{3}\)
(1) \(x < 3\) and \(-y > -2.....y<2\)
If both x and y are positive, xy<6.
If both x and y are negative, say x<-3 and y<-2....x=-4 and y=-10, then xy=40>6
Insuff
(2) \(y^2 < 100......|y|<10\), \(\frac{1}{2} < x < \frac{2}{3}\)
when y=9.9 and x=\(\frac{2}{3}.....xy=9.9*\frac{2}{3}=6.6>6\)
when y=-9 and x=\(\frac{2}{3}.....xy=-9*\frac{2}{3}=-4<6\)
Combined
\(2>y>-10\) and \(\frac{1}{2} < x < \frac{2}{3}\)
(negative y * largest x)<xy<largest y * largest x)
\(-10*\frac{2}{3}<xy<2*\frac{2}{3}...............-6.67<xy<1.33\). Hence xy <6.
The largest value will be when y~2 and x~\(\frac{2}{3}\), so \(xy<2*\frac{2}{3}=\frac{4}{3}<6\)
When y<0, the value of xy will always be negative.
Sufficient
C
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