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Manager  B
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What is the remainder when 11^452 is divided by 6  [#permalink]

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Difficulty:   35% (medium)

Question Stats: 62% (01:11) correct 38% (01:15) wrong based on 352 sessions

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What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Originally posted by sriamlan on 16 Jun 2017, 00:55.
Last edited by Bunuel on 16 Jun 2017, 01:35, edited 1 time in total.
Renamed the topic.
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

11 divided by 6 gives remainder 5.

$$11^2 = 121$$ divided by 6 gives remainder 1.

$$11^3 = 1331$$ divided by 6 gives remainder 5.

$$11^4 = 14641$$ divided by 6 gives remainder 1.

Therefore it has a cycle of 2 with 5 and 1 as remainders.

Even powers of 11 divided by 6 gives remainder 1. And Odd powers of 11 divided by 6 gives remainder 5.

452 divided by 2 = 226.

Therefore $$11^{452}$$ divided by 6 will give remainder 1.

General Discussion
Manager  B
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Experts my doubt here is -
The cyclicity of power of 11 when divided by 6 is 5,4,3,2,1,0

So if we divide 452 by 6 remainder is 2

So as 2 is the remainder as per the cyclicity should not 4 be the answer instead of 1?
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

$$\frac{11}{6}=\frac{5}{6} \implies \frac{11^{452}}{6}=\frac{5^{452}}{6}=\frac{(-1)^{452}}{6}=\frac{1}{6}$$

The answer is A.
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What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

$$\frac{11}{6}$$ = Remainder $$5$$
$$\frac{11^2}{6}$$ = Remainder $$1$$

Now, $$11^{452}$$ = $$11^{2*226}$$

$$\frac{11^{2*226}}{6}$$ will leave a remainder 1

Thus, the correct answer will be (A) 1
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Experts my doubt here is -
The cyclicity of power of 11 when divided by 6 is 5,4,3,2,1,0

So if we divide 452 by 6 remainder is 2

So as 2 is the remainder as per the cyclicity should not 4 be the answer instead of 1?

Not sure if i can clear your doubt. You can look at the problem like when 11/6 then remainder is 5, when 11^2/6 then remainder is 1.
Now you have 11^452 which is 11^even power so remainder will be 1.
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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6 = 3 * 2
11^452 = (11^256)*(11^256)
a^(p-1)/p = 1 mod p

11^(3-1)/3 = 11^2 = 1 mod 3
11^256= 11^(2*128) = 1 mod 3
(11^256)/2 = 1 mod 2

together 1
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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Rem|11^452/6| is equivalent to Rem|5^452/6|

Now rem|5^2/6| = 1

So Rem|5^452/6| = Rem|(5^2)^226/6|

=> 1^226 = 1

Final Remainder = 1
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

the easiest way ever

(12 - 1)^452
___________
6
now as, 12/6 leaves no remainder
(-1)^ 452
________
6

=1/6
leaves remainder 1

cheers through the kudos button if this helps
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Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

This problem is pretty simple. because if we divide 11 with 6 , we get remainder as -1 , final remainder will be (-1)*452 , which is 1. if exponent had been odd say 1999, the remainder would have been -1. you can ask what if dividend doesnt go by divisor without 1 or -1 as remainder, The thing is first we try use the exponent to make the divisor to take form of (divisor*K + 1) or (Divisor*K - 1), easy and medium questions fall to this category. However for hard questions we need to use cyclicity.
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What is the remainder when 11^452 is divided by 6  [#permalink]

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Hello!

Is it possible to do the following?

11-6= -5 Negative R

6-5= 1 R

Kind regards!
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Posts: 7959
Re: What is the remainder when 11^452 is divided by 6  [#permalink]

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sriamlan wrote:
What is the remainder when $$11^{452}$$ is divided by 6.

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Hi..

There are two ways you could do this..

1) cylicity..
11 leaves a remainder of 5.
$$11^2$$ or 121 leaves a remainder of 1.
$$11^3=1331$$ will leave a remainder of 5..
So we have a cylicity of 5,1,5,1...
Thus every odd power will give 5 as remainder and every even power will give 1 as remainder.
452 is even, so remainder is 1.

2) binomial expansion
$$11^{452}=(12-1)^{452}$$
The expansion will have all terms containing 12 except the last that will be $$12^0*(-1)^{452}$$=1..
So remainder will be 1

A
_________________ Re: What is the remainder when 11^452 is divided by 6   [#permalink] 27 Dec 2018, 20:25
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