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What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when

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What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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What is the value of \((\sqrt{a+\sqrt{b}}+\sqrt{a-\sqrt{b}})^2\) when a = 11 and b = 85?


A. 0

B. 22

C. 34

D. \(22+ 2\sqrt{85}\)

E. 242
[Reveal] Spoiler: OA

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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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AbdurRakib wrote:
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


\((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2=(a+b^\frac{1}{2})+2*\sqrt{a+b^\frac{1}{2}}*\sqrt{a-b^\frac{1}{2}} + (a-b^\frac{1}{2})=\)

\(=2a+2\sqrt{a^2-b}=2*11+2*\sqrt{121-85}=22+2*6=34\)

Answer: C.
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What is the value of [m](\sqrt{a + \sqrt{b}} + \sqrt{a - \sqrt{b}})^{ [#permalink]

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What is the value of \((\sqrt{a + \sqrt{b}} + \sqrt{a - \sqrt{b}})^{2}\) when \(a = 11\) and \(b = 85\)?

A. 0

B. 22

C. 34

D. 22 + 2\(\sqrt{85}\)

E. 242
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Re: What is the value of [m](\sqrt{a + \sqrt{b}} + \sqrt{a - \sqrt{b}})^{ [#permalink]

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\((\sqrt{a + \sqrt{b}} + \sqrt{a - \sqrt{b}})^{2}\) when \(a = 11\) and \(b = 85\)?


\((a + \sqrt{b}) + 2 (\sqrt{a + \sqrt{b}} * \sqrt{a - \sqrt{b}}) + (a - \sqrt{b})\)


\(2a + 2 \sqrt{(a + \sqrt{b})(a - \sqrt{b})}\)


\(2a + 2 \sqrt{(a^{2} - b)}\)


\(22 + 2 \sqrt{36} = 22 + 12 = 34\)


Hence, Answer is C
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What is the value of [m](\sqrt{a + \sqrt{b}} + \sqrt{a - \sqrt{b}})^{ [#permalink]

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New post 09 Jul 2017, 11:03
The expression is of the form (x+y)^2 = x^2 + y^2 + 2*x*y
where x =\((\sqrt{a + \sqrt{b}})\) and y = \((\sqrt{a - \sqrt{b}})\)

Here, the expression become \(a + \sqrt{b} + a - \sqrt{b}\) + 2*\((\sqrt{a + \sqrt{b}})\)*\((\sqrt{a - \sqrt{b}})\)

=\(2a + 2\sqrt{(a + \sqrt{b})(a - \sqrt{b})}\) because \(\sqrt{a}*\sqrt{b} = \sqrt{a*b}\)

= \(2a + 2(a^2 - b)\) because \((x+y)(x-y) = x^2 - y^2\)

Substituting values,
The expression becomes \(2*11 + 2*\sqrt{121-85} = 22 + 2*\sqrt{36} = 22 + 2*6 = 34\)(Option C)
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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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Bunuel wrote:
AbdurRakib wrote:
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


We see that the given expression is in the form of (x + y)^2, which equals x^2 + y^2 + 2xy.

We can let x = √(a + √b) and y = √(a - √b); thus:

x^2 = [√(a + √b)]^2 = a + √b

y^2 = [√(a - √b)]^2 = a - √b

2xy = 2√(a + √b)√(a - √b)

2xy = 2√[(a + √b)(a - √b)]

2xy = 2√(a^2 - b)

Thus, x^2 + y^2 + 2xy equals:

a + √b + a - √b + 2√(a^2 - b)

2a + 2√(a^2 - b)

Substituting 11 for a and 85 for b, we have:

2(11) + 2√(11^2 - 85) = 22 + 2√(121 - 85) = 22 + 2√36 = 22 + 12 = 34

Answer: C
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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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New post 12 Aug 2017, 14:31
Bunuel wrote:
AbdurRakib wrote:
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


\((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2=(a+b^\frac{1}{2})+2*\sqrt{a+b^\frac{1}{2}}*\sqrt{a-b^\frac{1}{2}} + (a-b^\frac{1}{2})=\)

\(=2a+2\sqrt{a^2-b}=2*11+2*\sqrt{121-85}=22+2*6=34\)

Answer: C.


when factoring 2xy, how come you distribute the radical across the entire identity; (x+y)(x-y) = x^2 - y^2 ?

i can't understand why we just don't take 2(a - b^1/2). why do we need to also take the square root of (a-b^1/2)?

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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when [#permalink]

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New post 12 Aug 2017, 14:35
ScottTargetTestPrep wrote:
Bunuel wrote:
AbdurRakib wrote:
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


We see that the given expression is in the form of (x + y)^2, which equals x^2 + y^2 + 2xy.

We can let x = √(a + √b) and y = √(a - √b); thus:

x^2 = [√(a + √b)]^2 = a + √b

y^2 = [√(a - √b)]^2 = a - √b

2xy = 2√(a + √b)√(a - √b)

2xy = 2√[(a + √b)(a - √b)]

2xy = 2√(a^2 - b)

Thus, x^2 + y^2 + 2xy equals:

a + √b + a - √b + 2√(a^2 - b)

2a + 2√(a^2 - b)

Substituting 11 for a and 85 for b, we have:

2(11) + 2√(11^2 - 85) = 22 + 2√(121 - 85) = 22 + 2√36 = 22 + 12 = 34

Answer: C


hi - in the second step of factoring 2xy, why do you distribute the root across both "x" and "y" as opposed to just solving as is?

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Re: What is the value of ((a + b^(1/2))(1/2) + (a - b^(1/2))(1/2))^2, when   [#permalink] 12 Aug 2017, 14:35
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