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The expression is of the form (x+y)^2 = x^2 + y^2 + 2*x*y
where x =\((\sqrt{a + \sqrt{b}})\) and y = \((\sqrt{a - \sqrt{b}})\)

Here, the expression become \(a + \sqrt{b} + a - \sqrt{b}\) + 2*\((\sqrt{a + \sqrt{b}})\)*\((\sqrt{a - \sqrt{b}})\)

=\(2a + 2\sqrt{(a + \sqrt{b})(a - \sqrt{b})}\) because \(\sqrt{a}*\sqrt{b} = \sqrt{a*b}\)

= \(2a + 2(a^2 - b)\) because \((x+y)(x-y) = x^2 - y^2\)

Substituting values,
The expression becomes \(2*11 + 2*\sqrt{121-85} = 22 + 2*\sqrt{36} = 22 + 2*6 = 34\)(Option C)
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Bunuel
AbdurRakib
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


We see that the given expression is in the form of (x + y)^2, which equals x^2 + y^2 + 2xy.

We can let x = √(a + √b) and y = √(a - √b); thus:

x^2 = [√(a + √b)]^2 = a + √b

y^2 = [√(a - √b)]^2 = a - √b

2xy = 2√(a + √b)√(a - √b)

2xy = 2√[(a + √b)(a - √b)]

2xy = 2√(a^2 - b)

Thus, x^2 + y^2 + 2xy equals:

a + √b + a - √b + 2√(a^2 - b)

2a + 2√(a^2 - b)

Substituting 11 for a and 85 for b, we have:

2(11) + 2√(11^2 - 85) = 22 + 2√(121 - 85) = 22 + 2√36 = 22 + 12 = 34

Answer: C
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AbdurRakib
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242

\((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2=(a+b^\frac{1}{2})+2*\sqrt{a+b^\frac{1}{2}}*\sqrt{a-b^\frac{1}{2}} + (a-b^\frac{1}{2})=\)

\(=2a+2\sqrt{a^2-b}=2*11+2*\sqrt{121-85}=22+2*6=34\)

Answer: C.

when factoring 2xy, how come you distribute the radical across the entire identity; (x+y)(x-y) = x^2 - y^2 ?

i can't understand why we just don't take 2(a - b^1/2). why do we need to also take the square root of (a-b^1/2)?
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I have the same question as person above me (ak). Can someone please explain?

I believe \sqrt{3} x \sqrt{3} = 3 so I don't understand why the same wouldn't apply to this example.
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I have the same question as person above me (ak). Can someone please explain?

I believe \sqrt{3} x \sqrt{3} = 3 so I don't understand why the same wouldn't apply to this example.

Yes, \(\sqrt{3} * \sqrt{3} = 3\) but do we have the same expressions under the square roots in \(2*\sqrt{a+\sqrt{b}}*\sqrt{a-\sqrt{b}}\) ? NO. Under the first root we have \(a+\sqrt{b}\) (with + sign) and under another we have \(a-\sqrt{b}\) (with - sign).

So, one should do the way it's shown in the solution: \(2*\sqrt{a+\sqrt{b}}*\sqrt{a-\sqrt{b}}=2\sqrt{(a+\sqrt{b})(a-\sqrt{b})}=2\sqrt{a^2-b}\) (by applying \((x+y)(x-y)=x^2-y^2\)).

Hope it's clear.
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Everyone here is a math wizard... but alas, I am not, therefore, I ballparked the entire problem.

I estimated that the square root of 85 was 9 and that the square root of 20 and 2 were 4.5 and 1.4 respectively.

The resulting answer I got was ~36, which was close to 34.

Solved it in about 15 seconds. this method may be useful even if one understands the proper calculations involved.
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destinyawaits
Everyone here is a math wizard... but alas, I am not, therefore, I ballparked the entire problem.

I estimated that the square root of 85 was 9 and that the square root of 20 and 2 were 4.5 and 1.4 respectively.

The resulting answer I got was ~36, which was close to 34.

Solved it in about 15 seconds. this method may be useful even if one understands the proper calculations involved.


I know it's best to solve the problems correctly, but this one really went over my head. I tried doing some "guess-timation" with the numbers like you suggested and it really helped. I'm also sadly not a math wizard, but it's nice to know I can use some kind of strategy to get by. Thanks!!
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Bunuel
AbdurRakib
What is the value of \((\sqrt{a+b^\frac{1}{2}}+\sqrt{a-b^\frac{1}{2}})^2\) when a=11 and b=85?

A. 0

B. 22

C. 34

D. 22+ \(2\sqrt{85}\)

E. 242


We see that the given expression is in the form of (x + y)^2, which equals x^2 + y^2 + 2xy.

We can let x = √(a + √b) and y = √(a - √b); thus:

x^2 = [√(a + √b)]^2 = a + √b

y^2 = [√(a - √b)]^2 = a - √b


What happens when you use the foil method for the above equation? I got stuck. I understand when you square a root the root sign drops. However I'm confused why this does not seem to work the same way when using foil.
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destinyawaits
Everyone here is a math wizard... but alas, I am not, therefore, I ballparked the entire problem.

I estimated that the square root of 85 was 9 and that the square root of 20 and 2 were 4.5 and 1.4 respectively.

The resulting answer I got was ~36, which was close to 34.

Solved it in about 15 seconds. this method may be useful even if one understands the proper calculations involved.


In the same boat here but I don't really understand your logic...understand the estimating square root of 85 is 9, but unsure about the logic after. why are you trying to find the sqr root of 20 and 2? how did you arrive at 36? many thanks!
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Noticing algebraic identities is key in questions like these
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