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Bunuel
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Answer:

A = Y/200,

Done this by taking numbers:

Let 10 (x) be 5% (m) of 2 * 100 (y)

Then m/x*100 = 5/10*100 = 50% or 1/2

50% or 1/2 in terms of Y = 100/200 = Y/200
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I did this by picking number.

2Y = 100
m =20
therefore x=20

20 = 100% of x therefore the answer is 2Y...

Hopefully this approach is the correct one.
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I did this by picking number.

2Y = 100
m =20
therefore x=20

20 = 100% of x therefore the answer is 2Y...

Hopefully this approach is the correct one.

I used a similar approach of picking numbers and have the same answer: 2Y

Picking numbers that make calculating % simple, I choose Y = 50, thus 2Y = 100

Any value for m (such as m=25), therefore, m/2y = x = 25/100 = 25%

And.... to find the solution m/x = 25/25 which is 1 (or 100%). Quickly scanning A through E, I see 2y, which is 2(50) = 100. This matches the value I'm looking for. Final answer: 2y
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Answer is E = 5000/y.

My approach was same as explained by PareshGmat
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It may also be good idea to look at the original question that this is copied from, Official Guide GMAT Review 2015 Question#181.

If m > 0 and x is m percent of y, then, in terms of m, y is what percent of x?

A. 100m
B. 1/100m
C. 1/m
D. 10/m
E. 10000/m


Discussion here: if-m-0-and-x-is-m-percent-of-y-then-in-terms-of-m-y-is-103387.html?fl=similar

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x= m/100 * 2y

m = z/100 * x . You have to find z in terms of y!!

From first equation : m= x/2y * 100

Therefore x/2y * 100 = z/100 * x

So z = 10000/2y
= 5000/y
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x = m% of 2y = m*2y/100

x= my/50

m=50x/y

in terms of %

m= 50*100/y % of x

m= 5000/y % of x
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Bunuel

Tough and Tricky questions: Sequences.



If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?

A. y/200
B. 2y
C. 50y
D. 50/y
E. 5000/y

We are given that x is m percent of 2y. Thus:

x = (m/100)(2y)

We need to determine m as a percentage of x, i.e., (m/x)(100).

Let’s simplify our equation:

x = (m/100)(2y)

x = 2ym/100

100x = 2ym

100/2y = m/x

50/y = m/x

Thus, (m/x)(100) = (50/y)(100) = 5000/y

Answer: E
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Here's my approach.

Given: x= m/100 * 2y

Let m = z% of x

m = z/100 * x
m = z/100 * m/100 * 2y (substituting the value of x)
solving for z, we get:
z = 5000/y

Answer: E
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Bunuel

Tough and Tricky questions: Sequences.



If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?

A. y/200
B. 2y
C. 50y
D. 50/y
E. 5000/y

Kudos for a correct solution.


If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?

from the statement

X= (m/100) * 2y

we need to find m / X * 100 (m is what percent of x)

interchange x and 2y on either side, we get

1 / 2y = (m/100) * (1 / X)

multiply both sides by 100 * 100

(100 * 100) / 2y = (100 * 100) * (m/100) * (1 / X)

5000 / 2y = 100 * m / X (= m percent of X)

answer is E.
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If m > 0, y > 0, and x is m percent of 2y, then, in terms of y, m is what percent of x?

I. m > 0, y > 0
II. x = m/100 * 2y
III. Eliminate x and m
IV. m = z/100 * x

IV. => m/x = z/100
III. => m/x = 100/2y

=> z/100 = 100/2y

=> z = 100*100/2y = 5000/y
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Y = 100

M= 50% of 2*100

X = 100

in terms of y, m is what percent of x?

M is 50 percent of X.

lets check the answers:
A. y/200 = 1/2
B. 2y = 200
C. 50y = 5000
D. 50/y = 1/2
E. 5000/y = 50
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Given: x is m% of 2y
x = m/100 × 2y
x = 2my/100
Find: m is what % of x
(m/x) × 100
= (m ÷ 2my/100) × 100
= 5000/y

Answer: E
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