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TheMechanic
Joined: 19 Oct 2012
Last visit: 05 Jul 2018
Posts: 220
Given Kudos: 103
Location: India
Concentration: General Management, Operations
Schools: Anderson '16 Tepper '16 Kelley '16 Jones '16 (S) Carlson '16 ISB '18 (II) Duke '20 (S) McCombs '20 (II)
GMAT 1: 660 Q47 V35
GMAT 2: 710 Q50 V38
GPA: 3.81
WE:Information Technology (Computer Software)
Schools: Anderson '16 Tepper '16 Kelley '16 Jones '16 (S) Carlson '16 ISB '18 (II) Duke '20 (S) McCombs '20 (II)
GMAT 2: 710 Q50 V38
Posts: 220
Updated on: 14 Oct 2013, 10:21
Originally posted by TheMechanic on 14 Oct 2013, 10:15.
Last edited by Bunuel on 14 Oct 2013, 10:21, edited 1 time in total.
Last edited by Bunuel on 14 Oct 2013, 10:21, edited 1 time in total.
Renamed the topic and edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
50% (01:44) correct
50%
(01:43)
wrong
based on 461
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Which of the following describes all the values of y for which y < y^2 ?
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
14 Oct 2013, 10:23
Kudos
Bookmarks
vabhs192003
Which of the following describes all the values of y for which y < y^2 ?
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
From y < y^2, it follows that y is not 0, thus y^2>0. Divide both parts by it: y/y^2 < 1 --> 1/y < 1.
Answer: D.
General Discussion
15 Oct 2013, 08:56
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mahendru1992
Bunuel
vabhs192003
Which of the following describes all the values of y for which y < y^2 ?
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
A. 1 < y
B. −1 < y < 0
C. y < −1
D. 1/y < 1
E. 0 < y < 1
I wanted an algebraic approach to solve this question. Any pointers are welcomed.
Kudos if you like the question.
From y < y^2, it follows that y is not 0, thus y^2>0. Divide both parts by it: y/y^2 < 1 --> 1/y < 1.
Answer: D.
\(y<y^2\)
\(y^2-y>0\)
\(y(y-1)>0\)
Two cases arise:-
Case I: When both are positive
either\(y>0\) or \(Y>1\), Thus \(y>1\)
Case II: When both are negative
\(Y<0\) and \(y<1\) thus \(Y<0\)
From the above two cases\(Y<0\) and \(Y>1\).
Where am I going wrong????
Yes, y < y^2 means that either y < 0 or y > 1.
If y < 0, then 1/y = negative < 0 < 1.
If y > 1, then 1/y < 1.
So, D is correct.
