Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

74% (02:55) correct 26% (02:45) wrong based on 240 sessions

HideShow timer Statistics

While driving from A-ville to B-town, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town?

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

19 Feb 2015, 10:27

3

This post received KUDOS

Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

19 Feb 2015, 11:49

1

This post received KUDOS

Celestial09 wrote:

Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks

Kudos please if my solution is correct!

Hello,

I have struggles coming from (D/115) + (D/135) = 5 to D = 621

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

19 Feb 2015, 12:06

1

This post received KUDOS

Hello! Thanks for addressing your doubt. here it goes: (d/115) + (d/135) = 5 kindly note.. its addition of two fractions... so I kindly take 5 common from both denominators... hence you will be left with d/23 + d/27 and that 5 will cross multiply to other side of equation.. resulting d/23 + d/27 = 25 then kindly solve it ... 27d +23 d = 25*23*27 d will come down to 310.5 which i particularly took as total distance 310.5*2 = 621 km hope it makes sense. thanks

LaxAvenger wrote:

Celestial09 wrote:

Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks

Kudos please if my solution is correct!

Hello,

I have struggles coming from (D/115) + (D/135) = 5 to D = 621

While driving from A-ville to B-town, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town?

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

19 Jul 2015, 10:00

Hi everyone,

I don't see why we divide the distance 625 by 250 and not 115, while Harriet drives from A to B at 115mph... Does not make sense to me.

But at the same time, dividing 625 by 115 gives us a time of 5+ hours, which is also impossible because the whole trip A --> B --> A takes 5 hours. Can someone please give some insights?

While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

04 Sep 2016, 12:17

5hr = 300min. If harriet spend equal hrs on each leg she will spend 150min on each. Since speed A-B is less than speed B-A and distance on each leg is the same, time spent on A-B is more than 150min, which mean we can eliminate ans. A, B and C.

Now let plug in ans. D or E and verify which one give same distance on each leg.

D. t= 162min * leg A-B ---> d = 115.162/60 = 18630/60 * leg B-A ----> d = 135*138/60 = 18630/60

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

13 Nov 2016, 09:35

Rates and Distance: Q: Find t on the way in? When you are given the same distance on the way in and back. ex: d and you are given the rates for back and forth. ex: 115 and 135 and you are given the total time. ex: 5

step1: organize the formulas like below. Use 5-t for the time on the way back = very important.

rt=d 115 (t) = d 135 (5-t) = d

step2: Make the two equations equal and solve for t

115(t) = 135 (5-t) t= 27/10 hours

step3: check the convention of time that the question wants you to answer and convert if needed

In this question, you are asked for minutes, so you need to do one more thing before jumping into the answers

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

13 Nov 2016, 09:49

2

This post received KUDOS

Distance taken = speed*time Let Harriet took x hrs to go from A to B and y hrs to come from B to A. Distance=115*x=135*y x+y=5 (total time=5 hrs.) we need to find x. y=5-x Substituting in Distance equation. 115*x=135(5-x) Solve to get x=2.7hrs 2.7*60=162mins. Answer=D.

While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

13 Nov 2016, 11:54

Bunuel wrote:

While driving from A-ville to B-town, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town?

A. 138 B. 148 C. 150 D. 162 E. 168

Kudos for a correct solution.

average speed for round trip≈125 kph 125*5=625 round trip miles 625/2=312.5 one way miles 312.5/115=2.72 hours 2.72*60=163.2 minutes closest to 162 D

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

22 Nov 2016, 01:53

Bunuel wrote:

While driving from A-ville to B-town, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in B-town, Harriet immediately turned and drove back to A-ville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from A-ville to B-town?

A. 138 B. 148 C. 150 D. 162 E. 168

Kudos for a correct solution.

distance travelled is the same in each direction thus time is inversely proportional to speed , total time = 5 , let first leg time t and 2nd leg time = 5-t

115/135 = 5-t / t thus , t in hours = 5*27/50 , in minutes = 300*27/50 = 6*27 = 162..........D

Re: While driving from A-ville to B-town, Harriet drove at a constant spee [#permalink]

Show Tags

03 Dec 2017, 12:54

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________