January 17, 2019 January 17, 2019 08:00 AM PST 09:00 AM PST Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL. January 19, 2019 January 19, 2019 07:00 AM PST 09:00 AM PST Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
Author 
Message 
TAGS:

Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 52130

While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Feb 2015, 08:55
Question Stats:
73% (02:59) correct 27% (02:46) wrong based on 392 sessions
HideShow timer Statistics




Math Expert
Joined: 02 Sep 2009
Posts: 52130

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
22 Feb 2015, 11:37




Intern
Joined: 19 Feb 2015
Posts: 14

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Feb 2015, 10:00
X = Time from A to B Y = Time from B to A X+Y=5 hrs total travel time 115X=135Y since the distances are the same
X+Y=5 => 135X+135Y=675 115X=135Y => 115X135Y=0 Combined you get 250X=675 hrs X=2.7 hrs * 60 mins/hr= 162



Retired Moderator
Status: I Declare War!!!
Joined: 02 Apr 2014
Posts: 237
Location: United States
Concentration: Finance, Economics
GMAT Date: 03182015
WE: Asset Management (Investment Banking)

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Feb 2015, 10:27
Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks
Kudos please if my solution is correct!



Manager
Joined: 18 Aug 2014
Posts: 119
Location: Hong Kong

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Feb 2015, 11:49
Celestial09 wrote: Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks
Kudos please if my solution is correct! Hello, I have struggles coming from (D/115) + (D/135) = 5 to D = 621 could you explain the calculation steps ?



Retired Moderator
Status: I Declare War!!!
Joined: 02 Apr 2014
Posts: 237
Location: United States
Concentration: Finance, Economics
GMAT Date: 03182015
WE: Asset Management (Investment Banking)

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Feb 2015, 12:06
Hello! Thanks for addressing your doubt. here it goes: (d/115) + (d/135) = 5 kindly note.. its addition of two fractions... so I kindly take 5 common from both denominators... hence you will be left with d/23 + d/27 and that 5 will cross multiply to other side of equation.. resulting d/23 + d/27 = 25 then kindly solve it ... 27d +23 d = 25*23*27 d will come down to 310.5 which i particularly took as total distance 310.5*2 = 621 km hope it makes sense. thanks LaxAvenger wrote: Celestial09 wrote: Its D. Here it goes: Distance will be same both sides... hence total distance will D+D= 2D Total time given+ 5hrs Speed per side also given.. 115km/ph and 135 km/ph Speed= Distanct/Time D/s1 + D/s2= total time (d/115) + (d/135) = 5 solving it D comes to 621 km Hence each side is D/2 : 621/2 = 310.5 km Time for first journey is 310.5/115 which is 162 mins Thanks
Kudos please if my solution is correct! Hello, I have struggles coming from (D/115) + (D/135) = 5 to D = 621 could you explain the calculation steps ?



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1823
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
11 Mar 2015, 20:07
Answer = D = 162 Let distance between A & B = d Setting up the time equation \(\frac{d}{115} + \frac{d}{135}= 5\) \(d = \frac{23 * 27}{2}\) (Need not have to solve) Time required in minutes from A to B \(= \frac{23*27}{2*115} * 60 = 162\)
_________________
Kindly press "+1 Kudos" to appreciate



Intern
Joined: 16 Mar 2015
Posts: 9

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
23 Mar 2015, 07:48
Distance from A to B is the same as distance from B to A. Hence
115x=135y x/y=135/115 => x/y=27/23 so x= 27/50 of the total time (50=27+23). total time x+y=5h= 300minutes,
x= 300m*(27/50)= 162m
Answer. D



Intern
Joined: 30 Jun 2015
Posts: 1
Concentration: Finance, Entrepreneurship
GPA: 3.94

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
19 Jul 2015, 10:00
Hi everyone,
I don't see why we divide the distance 625 by 250 and not 115, while Harriet drives from A to B at 115mph... Does not make sense to me.
But at the same time, dividing 625 by 115 gives us a time of 5+ hours, which is also impossible because the whole trip A > B > A takes 5 hours. Can someone please give some insights?
Many thanks in advance



Intern
Joined: 12 Jul 2015
Posts: 11
Location: Canada
Concentration: Strategy, Finance
GPA: 3.62
WE: Project Management (Energy and Utilities)

While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
04 Sep 2016, 12:17
5hr = 300min. If harriet spend equal hrs on each leg she will spend 150min on each. Since speed AB is less than speed BA and distance on each leg is the same, time spent on AB is more than 150min, which mean we can eliminate ans. A, B and C.
Now let plug in ans. D or E and verify which one give same distance on each leg.
D. t= 162min * leg AB > d = 115.162/60 = 18630/60 * leg BA > d = 135*138/60 = 18630/60
so the correct ans. is D



Manager
Joined: 17 Nov 2013
Posts: 88

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
13 Nov 2016, 09:35
Rates and Distance: Q: Find t on the way in? When you are given the same distance on the way in and back. ex: d and you are given the rates for back and forth. ex: 115 and 135 and you are given the total time. ex: 5
step1: organize the formulas like below. Use 5t for the time on the way back = very important.
rt=d 115 (t) = d 135 (5t) = d
step2: Make the two equations equal and solve for t
115(t) = 135 (5t) t= 27/10 hours
step3: check the convention of time that the question wants you to answer and convert if needed
In this question, you are asked for minutes, so you need to do one more thing before jumping into the answers
27/10 hours * 60minutes = 162 minutes



Intern
Joined: 22 Mar 2016
Posts: 2
Location: India
Concentration: International Business, Finance
GPA: 3.8

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
13 Nov 2016, 09:49
Distance taken = speed*time Let Harriet took x hrs to go from A to B and y hrs to come from B to A. Distance=115*x=135*y x+y=5 (total time=5 hrs.) we need to find x. y=5x Substituting in Distance equation. 115*x=135(5x) Solve to get x=2.7hrs 2.7*60=162mins. Answer=D.
Thanks. Please give KUDOS if correct.



VP
Joined: 07 Dec 2014
Posts: 1150

While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
13 Nov 2016, 11:54
Bunuel wrote: While driving from Aville to Btown, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in Btown, Harriet immediately turned and drove back to Aville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from Aville to Btown?
A. 138 B. 148 C. 150 D. 162 E. 168
Kudos for a correct solution. average speed for round trip≈125 kph 125*5=625 round trip miles 625/2=312.5 one way miles 312.5/115=2.72 hours 2.72*60=163.2 minutes closest to 162 D



Retired Moderator
Joined: 05 Jul 2006
Posts: 1722

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
22 Nov 2016, 01:53
Bunuel wrote: While driving from Aville to Btown, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in Btown, Harriet immediately turned and drove back to Aville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from Aville to Btown?
A. 138 B. 148 C. 150 D. 162 E. 168
Kudos for a correct solution. distance travelled is the same in each direction thus time is inversely proportional to speed , total time = 5 , let first leg time t and 2nd leg time = 5t 115/135 = 5t / t thus , t in hours = 5*27/50 , in minutes = 300*27/50 = 6*27 = 162..........D



Retired Moderator
Status: The best is yet to come.....
Joined: 10 Mar 2013
Posts: 497

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
02 Feb 2018, 22:32
I solved in following way; Rate of driving from Aville to Btown is 115 kmph Rate of driving from Btown to Aville is 135 kmph Therefore, the ratio of rate is 115:135 Since the distance is same, the ratio of time would be reciprocal of ratio of rate.So, ratio of time would be \(135:115=27:23; 27x:23x\) Total time taken is 5 hours=300 minutes \(27x+23x=50x\) Given, \(50x=300\) \(x=6\) So, time taken to drive from Aville to Btown would be \(27x=27*6=162\)
_________________
Hasan Mahmud



Director
Joined: 31 Jul 2017
Posts: 516
Location: Malaysia
GPA: 3.95
WE: Consulting (Energy and Utilities)

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
03 Feb 2018, 06:27
Bunuel wrote: While driving from Aville to Btown, Harriet drove at a constant speed of 115 kilometers per hour. Upon arriving in Btown, Harriet immediately turned and drove back to Aville at a constant speed of 135 kilometers per hour. If the entire trip took 5 hours, how many minutes did it take Harriet to drive from Aville to Btown?
A. 138 B. 148 C. 150 D. 162 E. 168
Kudos for a correct solution. Let the time from A to B be t1 and time from B to A be t2. \(t1 + t2 = 5\) \(115*t1 = 135*t2\) > \(t2 = \frac{23}{27}t1\) \(t1 = 2.7 Hours.\)
_________________
If my Post helps you in Gaining Knowledge, Help me with KUDOS.. !!



Manager
Joined: 29 Jul 2018
Posts: 107
Concentration: Finance, Statistics

Re: While driving from Aville to Btown, Harriet drove at a constant spee
[#permalink]
Show Tags
30 Sep 2018, 02:13
why make equations since distance is same speed will be inversely propotional to time s1 : s2 115: 135 t1:t2 135:115 27:23 27/50(5*60) = 162 mins




Re: While driving from Aville to Btown, Harriet drove at a constant spee &nbs
[#permalink]
30 Sep 2018, 02:13






