pravinpillai2015 wrote:
Working at constant rate, pump X pumped out half of the water in a flooded basement in 4 hours. The pump Y was started and the two pumps, working independently at their respective constant rates, pumped out rest of the water in 3 hours. How many hours would it have taken pump Y , operating alone at its own constant rate, to pump out all of the water that was pumped out of the basement?
a. 10
b. 12
c. 14
d. 18
e. 24
If the pump X pumped out half the water in 4 hours, it will pump out the entire water in 8 hours.
Similarly, the pump Y was started and the two pumps operating together are able to pump out
the entire water in 3 hours.
Assume the total capacity of the pump to be 96 units.
So, the pump X must be pumping out 12 units/hour. Since, both the pumps working together
pump out the remainder of the water in 3 hours, their combined capacity will be 16 units/hour.
Hence, pump Y must be pumping out 4 units/hour.
Therefore, Pump Y alone will take \(\frac{96}{4}\) =
24 hours(Option E) _________________
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