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y = x(x + 1)(x + 2) where x is an even integer. Which of the following

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y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 08 Jul 2017, 05:34
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\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above

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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 08 Jul 2017, 05:41
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above




Hi
Numbers are even * odd * even. So following properties
1) one even will be multiple of 2 and one of 4... ATLEAST
2) ATLEAST one will be multiple of 3..
3) so the product will be multiple of ATLEAST 2*4*3=24

Now 6 and 12 are factors of 24, so I and II MUST be true.
18 is NOT a factor of 24... So not a MUST

B
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 08 Jul 2017, 05:50
1
chetan2u wrote:
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above




Hi
Numbers are even * odd * even. So following properties
1) one even will be multiple of 2 and one of 4... ATLEAST
2) ATLEAST one will be multiple of 3..
3) so the product will be multiple of ATLEAST 2*4*3=24

Now 6 and 12 are factors of 24, so I and II MUST be true.
18 is NOT a factor of 24... So not a MUST

B

Although it does not make any difference, just want to highlight that since it is mentioned that x is an even integer which includes 0 as well and the value of y can be 0 which is considered divisible by all integers but none of the integers are considered divisible by "0"
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 08 Jul 2017, 05:54
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above


Let's plug in some numbers and check -

Let x = 2 ; So, \(y = 2*3*4\) ( Divisible by 6 & 12 )
Let x = 4 ; So, \(y = 4*5*6\) ( Divisible by 6 & 12 )
Let x = 6 ; So, \(y = 6*7*8\) ( Divisible by 6 & 12 )

Thus, in each case y is divisible by 6 & 12, so the correct answer must be (B)
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y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 08 Jul 2017, 06:19
1
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above


\(y = x(x + 1)(x + 2)\)

\(y\) is product of \(3\) consecutive integers. Hence \(y\) must be divisible by \(6\).

Given \(x\) is even integer. Hence \(y\) must be divisible by \(12\).

Let \(x = 2\)

\(y = 2(2+1)(2+2) = 2*3*4 = 24\)

\(24\) is divisible by \(6\) and \(12\)

\(24\) is not divisible by \(18\)

I and II only . Answer (B)...
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 29 Mar 2018, 08:43
0 is even and an integer too. IF x=0 option E becomes the answer. please clear the doubtBunuel
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 29 Mar 2018, 08:48
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 29 Mar 2018, 09:00
Thanks bunuel , but if x =0, y will become zero and option d should be the answer. But b is the OA. Why is that ? Bunuel
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y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 29 Mar 2018, 09:04
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shahul. wrote:
Thanks bunuel , but if x =0, y will become zero and option d should be the answer. But b is the OA. Why is that ? Bunuel


Notice that the question asks "which of the following statements must be true", not "which of the following statements could be true". While y could be divisible by any integer, it must be divisible only by some of the numbers.
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Collection of Questions:
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 29 Mar 2018, 09:45
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above


The only reason I marked (E) is that x can be "0". Point noted, 0 is divisible by every number except "0".
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following  [#permalink]

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New post 01 Apr 2018, 23:05
Bunuel wrote:
\(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?

I. y is divisible by 6

II. y is divisible by 12

III. y is divisible by 18


A. I only
B. I and II only
C. I and III only
D. I, II, and III
E. None of the above

IMOB By plug in numbers we know these are 3 consecutive integers where middle no. is odd and 1st and last no. is even so take any example 2,3,4 or 4,5,6 or 14,15,16 we can say only I and II situation is true.
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following &nbs [#permalink] 01 Apr 2018, 23:05
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