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y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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08 Jul 2017, 04:34
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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08 Jul 2017, 04:41
Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above Hi Numbers are even * odd * even. So following properties1) one even will be multiple of 2 and one of 4... ATLEAST 2) ATLEAST one will be multiple of 3.. 3) so the product will be multiple of ATLEAST 2*4*3=24 Now 6 and 12 are factors of 24, so I and II MUST be true. 18 is NOT a factor of 24... So not a MUST B
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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08 Jul 2017, 04:50
chetan2u wrote: Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above Hi Numbers are even * odd * even. So following properties1) one even will be multiple of 2 and one of 4... ATLEAST 2) ATLEAST one will be multiple of 3.. 3) so the product will be multiple of ATLEAST 2*4*3=24 Now 6 and 12 are factors of 24, so I and II MUST be true. 18 is NOT a factor of 24... So not a MUST B Although it does not make any difference, just want to highlight that since it is mentioned that x is an even integer which includes 0 as well and the value of y can be 0 which is considered divisible by all integers but none of the integers are considered divisible by "0"
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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08 Jul 2017, 04:54
Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above Let's plug in some numbers and check  Let x = 2 ; So, \(y = 2*3*4\) ( Divisible by 6 & 12 ) Let x = 4 ; So, \(y = 4*5*6\) ( Divisible by 6 & 12 ) Let x = 6 ; So, \(y = 6*7*8\) ( Divisible by 6 & 12 ) Thus, in each case y is divisible by 6 & 12, so the correct answer must be (B)
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y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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08 Jul 2017, 05:19
Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above \(y = x(x + 1)(x + 2)\)
\(y\) is product of \(3\) consecutive integers. Hence \(y\) must be divisible by \(6\).
Given \(x\) is even integer. Hence \(y\) must be divisible by \(12\).
Let \(x = 2\)
\(y = 2(2+1)(2+2) = 2*3*4 = 24\)
\(24\) is divisible by \(6\) and \(12\)
\(24\) is not divisible by \(18\)
I and II only . Answer (B)...



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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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29 Mar 2018, 07:43
0 is even and an integer too. IF x=0 option E becomes the answer. please clear the doubt Bunuel



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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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29 Mar 2018, 07:48



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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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29 Mar 2018, 08:00
Thanks bunuel , but if x =0, y will become zero and option d should be the answer. But b is the OA. Why is that ? Bunuel



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y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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29 Mar 2018, 08:04



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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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29 Mar 2018, 08:45
Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above The only reason I marked (E) is that x can be "0". Point noted, 0 is divisible by every number except "0".
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Re: y = x(x + 1)(x + 2) where x is an even integer. Which of the following
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01 Apr 2018, 22:05
Bunuel wrote: \(y = x(x + 1)(x + 2)\) where x is an even integer. Which of the following must be true?
I. y is divisible by 6
II. y is divisible by 12
III. y is divisible by 18
A. I only B. I and II only C. I and III only D. I, II, and III E. None of the above IMO B By plug in numbers we know these are 3 consecutive integers where middle no. is odd and 1st and last no. is even so take any example 2,3,4 or 4,5,6 or 14,15,16 we can say only I and II situation is true.




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