Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

67% (01:46) correct
33% (02:24) wrong based on 299 sessions

HideShow timer Statistics

16 horses can haul a load of lumber in 24 minutes. 12 horses started hauling a load and after 14 minutes, 12 mules joined the horses. Will it take less than a quarter-hour for all of them together to finish hauling the load?

(1) Mules work more slowly than horses. (2) 48 mules can haul the same load of lumber in 16 minutes.

ans B.. statement 2 is sufficient statement 1 .. if mules work as efficiently as horses, it will take atleast 9 min so depending on the % of being slow would give ans >15min or <15 min.. statement gives speed of mules too sufficient
_________________

Re: 16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

26 Jan 2015, 12:29

Answer D (Not sure if that's right) The problem tells us that 16 horses need 24 min's to do the job - thus one horse would need 16x24 min's to do the same job alone. 12 horses would need (16x24)/12 = 32 minutes to do the full job. A quarter of an hour is 15 minutes. After 14 minutes 12 mules join the horses. If the mules work faster than the horses it might be possible that they could finish the job in fewer than 15 minutes - but if they work at an equal or slower rate it is not possible (24 mules/horses with the same speed would need 32/2=16 minutes). Statement (1) is sufficient as it tells us that the mules work at a slower rate. Statement (2) tells us that the 12 mules need (48x16)/12 = 64 minutes to do the full job. As 64 minutes > 24 minutes the work rate of the mules is slower than that of the horses. Sufficient

Re: 16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

26 Jan 2015, 13:14

1

This post received KUDOS

we know that 16*(1/x)=1/24 so -> for 1 horse its 384(=x) minutes. for 12 horses its 12/384=1/32 -> 32 minutes. after 14 minutes they still ned 18 minutes to finish the job. we add some mule power to finish this job faster, but we need to determine if we can save 4 minutes so that the time(rest)<15 minutes.

(1) -> mules are slower, but are they just slighty slower, then we COULD finish the job under 15 minutes, or are they hardcore slow. we dont know, but in this case both is possible and lead to 2 different answer -> not sufficient.

(2) -> we got an number which we could use to calculate if we can save 4 minutes or not. this leads us to 1 answer -> suff. B i did not calculate anything in part 2, because I needed 1.5 minutes to calculate the beginning. (its already late in Germany)

Answer D (Not sure if that's right) The problem tells us that 16 horses need 24 min's to do the job - thus one horse would need 16x24 min's to do the same job alone. 12 horses would need (16x24)/12 = 32 minutes to do the full job. A quarter of an hour is 15 minutes. After 14 minutes 12 mules join the horses. If the mules work faster than the horses it might be possible that they could finish the job in fewer than 15 minutes - but if they work at an equal or slower rate it is not possible (24 mules/horses with the same speed would need 32/2=16 minutes). Statement (1) is sufficient as it tells us that the mules work at a slower rate. Statement (2) tells us that the 12 mules need (48x16)/12 = 64 minutes to do the full job. As 64 minutes > 24 minutes the work rate of the mules is slower than that of the horses. Sufficient

hi... the point you are missing is that the amount of work left which is not full but 18/32=9/16.... so if both are equally or mules are just slightly slower, they will take 9/16*16=9 mins... therefore if they are slightly slow it may take <15 min.. or >15 if very slow...
_________________

Re: 16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

27 Jan 2015, 13:54

2

This post received KUDOS

1

This post was BOOKMARKED

Bunuel wrote:

16 horses can haul a load of lumber in 24 minutes. 12 horses started hauling a load and after 14 minutes, 12 mules joined the horses. Will it take less than a quarter-hour for all of them together to finish hauling the load?

(1) Mules work more slowly than horses. (2) 48 mules can haul the same load of lumber in 16 minutes.

Kudos for a correct solution.

I think B is the answer:

Approach is as follows; from stem

Horses........minutes............total work 16..............24....................16*24 = 384 units 12..............14....................12*14 = 168 units --> work left = 384 - 168 = 216 units of work is left.

from 1: mules work slower than horses and 216 units of work is completed by horses and mules together. In 15 mins horses do 12*15 = 180 units of work. Mules do less than 180 units in 15 mins from this statement. together, they can do more than or less than 216 units in 15 mins ---> if mules are too slow.

from 2: 48 mules can do 384 units of work in 16 mins. 12 mules can do 384 units of work in 16*4 = 64 mins 12 mules can do 216 unis of work in 64*216/384 = 36 mins 12 horses can do 216 units of work in 24*(16/12)*(216/384) = 18 mins (equation is from stem as 16 horses take 24 mins for 384 units of work)

as 12 horses and 12 mules do the work simultaneously: and horses take 18 mins and mules take 36 mins, combined they take (36*18)/(36+18) mins = 12 mins

16 horses can haul a load of lumber in 24 minutes. 12 horses started hauling a load and after 14 minutes, 12 mules joined the horses. Will it take less than a quarter-hour for all of them together to finish hauling the load?

(1) Mules work more slowly than horses. (2) 48 mules can haul the same load of lumber in 16 minutes.

The answer is always “yes.” Let’s consider how “big” this lumber-haul job is first. To load the lumber, it took 16 horses x 24 minutes = 384 horse-minutes of work. If mules do it, it takes 48 mules x 16 minutes = 768 mule-minutes of work. Notice that 384 is half of 768! That means that one horse can do the work of two mules.

In 14 minutes, 12 horses will do 12 x 14 = 168 horse-minutes of work. That leaves 384 – 168 = 216 horse-minutes of work left to do.

To complete the job, we have 12 horses and 12 mules. The 12 mules do the work of 6 horses, so 12 horses and 12 mules will do the work at the same rate 18 horses would:

18 horses x ___ minutes =216 horse-minutes of work

216/18 = 12 minutes to complete the remaining work.

If you chose (A), this information is not sufficient. Without knowing how much slower mules work than horses, we cannot answer the question.

If you chose (C), the second statement alone is sufficient.

If you chose (D), the first statement doesn’t tell us anything about the mule’s work-rate.

If you chose (E), the second statement is sufficient because we are given the rates of both animals. You may want to get more practice on challenging work-and-rate word problems to review this difficult concept in more detail.
_________________

Re: 16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

02 Feb 2015, 06:09

Hi,

Would the following logic be ok during the test or no :

without even computing anything, statement A doesnt give any real info, only 'slower' but it can be much slower, or a lot slower. statement B does give the rate of the mule, and thus can allow us to make some computation and answer the question (but we wont since we don't need the actual answer). thus, only statement B is helpful. done in 20seconds.

would this be correct or can there be a case where only statement A is helpful ? such as a situation where the only fact of knowing that the mule are slower can tell us the answer?

Would the following logic be ok during the test or no :

without even computing anything, statement A doesnt give any real info, only 'slower' but it can be much slower, or a lot slower. statement B does give the rate of the mule, and thus can allow us to make some computation and answer the question (but we wont since we don't need the actual answer). thus, only statement B is helpful. done in 20seconds.

would this be correct or can there be a case where only statement A is helpful ? such as a situation where the only fact of knowing that the mule are slower can tell us the answer?

thank you !

hi, .... you cannot take this as a routine. It may not have mattered here with the kind of numbers we have... but it will not be true if i change only one value in the original question ..

16 horses can haul a load of lumber in 24 minutes. 12 horses started hauling a load and after 1 minute, 12 mules joined the horses. Will it take less than a quarter-hour for all of them together to finish hauling the load?

(1) Mules work more slowly than horses. (2) 48 mules can haul the same load of lumber in 16 minutes.

Re: 16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

08 Jul 2017, 05:16

Cuco wrote:

chetan2u wrote:

hycday wrote:

Hi,

Would the following logic be ok during the test or no :

without even computing anything, statement A doesnt give any real info, only 'slower' but it can be much slower, or a lot slower. statement B does give the rate of the mule, and thus can allow us to make some computation and answer the question (but we wont since we don't need the actual answer). thus, only statement B is helpful. done in 20seconds.

would this be correct or can there be a case where only statement A is helpful ? such as a situation where the only fact of knowing that the mule are slower can tell us the answer?

thank you !

hi, .... you cannot take this as a routine. It may not have mattered here with the kind of numbers we have... but it will not be true if i change only one value in the original question ..

16 horses can haul a load of lumber in 24 minutes. 12 horses started hauling a load and after 1 minute, 12 mules joined the horses. Will it take less than a quarter-hour for all of them together to finish hauling the load?

(1) Mules work more slowly than horses. (2) 48 mules can haul the same load of lumber in 16 minutes.

please find answer for this

Actually, hycday's logic still works with the changes you made to the original question.... With the given information we can still calculate the time it would take 12 horses and 12 mules working together to finish the job, hence B is sufficient. Whether it takes more, or less, than 15 min is indifferent, the fact is that with the information provided in B we can calculate the time it would take the animals to finish the job, so B is sufficient.

16 horses can haul a load of lumber in 24 minutes. 12 horses started h [#permalink]

Show Tags

19 Oct 2017, 06:37

Answer is B.

Let h - time taken by single horse to load (in minutes) m - time taken by single mule to load (in minutes)

Given: 16 horses -> 24 mins => time taken by single horse is (16 * 24) = 384 minutes so amount of job completed by 1 horse in 1 min => 1/384 amount of job completed by 12 horse in 1 min => 12/384 amount of job completed by 12 horses in 14 min => (14 * 12/384) = 9/16

So before mules join (7/16) of work completed,

now , amount of job completed by 1 mule in 1 min => 1/m amount of job completed by 12 mules in 1 min => 12/m

now the question is remaining job, (9/16) will be completed less than 15 mins?

now if considering hypothetical situation, mules at same speed as horse., them m = 384(time taken by single horse to complete full job) Eqn --- (1) becomes , (9/16) / ((12/384) + (12/384)) = 9 minutes (which is less than 15 mins) so, if mules work at same speed as horses, remaining job will be completed in 9 minutes, but given mules work slower than horses, we don't know how slow, so time taken could be < 15 or >= 15 minutes, we can't say -> Insufficient.

Statement 2: 48 mules can haul the same load of lumber in 16 minutes. so time taken by single mule to do whole job = (16 * 48) minutes (which is the value of "m")

We can substitute the value of "m" in equation --- -(1) and can find remaining job time taken, and accordingly we will be able to say <15 or >= 15