Bunuel wrote:
Tough and Tricky questions: Mixture Problems.
A bartender mixes drink A with drink B. If drink A contains 24 percent alcohol, what percentage of the mixture of drink A and B is alcohol?
(1) The ratio of drink A and drink B is 1:4
(2) The alcohol concentration of drink B is 1.5 times greater than the alcohol concentration of drink A.
Kudos for a correct solution.Statement-1 : If Ratio is 1:4. Then we have total of 5 parts in the mixture. Then 1/5th of the mixture is A and 4/5 of mixture is B. No other information. SO Insufficient.
Statement-2 : B= 1.5 times of A in the concentration of alcohol. We can get the value by multiplying 1.5 with 0.24. But still this statement alone not sufficient to solve.
Combining.
We know the alcohol concentration of A from the question and alcohol concentration of B from Statement-2. And we know how many A and B are present in the mixture from Statement A. So we can find the alcohol percentage in the mixture.
So answer is C.
And I hope it is correct.
Bunuel please post your version of explanation
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