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01 Dec 2018, 10:07
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34% (02:16) correct
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A box contains balls of two sizes – big and small – and different colors. When one ball is chosen at random from the box, the probability that the ball is blue is 1/4. What is the probability that the chosen ball is neither blue nor small?
(1) The probability that the chosen ball is not small is 5/8
(2) The probability that the chosen ball is small but not blue is 9/40
(1) The probability that the chosen ball is not small is 5/8
(2) The probability that the chosen ball is small but not blue is 9/40
01 Dec 2018, 10:34
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harshsaini
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01 Dec 2018, 12:00
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P( blue ball)= 1/ 4 P ( not a blue ball) = 3/4
to find = P ( neither a blue nor a small ball)
statement 1
P ( big ball) = 5/8
P ( not a blue ball)=3/4
p = 3/4 * 5/8
statement is suficient
statement 2
P(small)* P(not blue )=9/40
P(small)= 3/10 P (big)= 7/10
P(big)*P(not blue)
statement 2 sufficient
answer is d option
to find = P ( neither a blue nor a small ball)
statement 1
P ( big ball) = 5/8
P ( not a blue ball)=3/4
p = 3/4 * 5/8
statement is suficient
statement 2
P(small)* P(not blue )=9/40
P(small)= 3/10 P (big)= 7/10
P(big)*P(not blue)
statement 2 sufficient
answer is d option
