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23 Jul 2019, 08:00
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Difficulty:
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Question Stats:
62% (02:06) correct
38%
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wrong
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A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?
(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.
(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.
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23 Jul 2019, 08:31
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A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?
This is an easy question.
Let's analyze the stem first.
Lets LABEL
2 room Lowest X
2 room Highest Y
3 room Lowest Z
3 room Highest T
Its is given to use that the range combined is 1000
and T-Z = 600 ....1
We are looking for Y - X
Let's analyze the statements now.
(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
This gives us Z = Y +200 ....2
This tells us that the highest of the 2 room is still lower than the lowest of the 3 room. Which helps us establish that T - X = 1000 ....3
Y - X = (Puting 2 & 3 here ) Z-200 - T+ 1000 = Z-T +800 . Now put 1 here =T- 600- T + 800 = 200 is the answer.
Hence this statement is correct.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.
This statement is insufficient.
Hence the answer is A.
This is an easy question.
Let's analyze the stem first.
Lets LABEL
2 room Lowest X
2 room Highest Y
3 room Lowest Z
3 room Highest T
Its is given to use that the range combined is 1000
and T-Z = 600 ....1
We are looking for Y - X
Let's analyze the statements now.
(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
This gives us Z = Y +200 ....2
This tells us that the highest of the 2 room is still lower than the lowest of the 3 room. Which helps us establish that T - X = 1000 ....3
Y - X = (Puting 2 & 3 here ) Z-200 - T+ 1000 = Z-T +800 . Now put 1 here =T- 600- T + 800 = 200 is the answer.
Hence this statement is correct.
(2) The lowest rental fee for a 2-room apartment is $800 in the building.
This statement is insufficient.
Hence the answer is A.
From the statement we have the following:
Range is Max - Min = 1000
Range for 3 - room = Max3 - Min3 =600
From (1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building, we have that:
Min3 - Max2 = 200, then the range will have to be Max3 - Min2 =1000
but since we have Max3 - Min3 =600, Min3-Max2 = 200, the difference between Max2 - Min 2 must be 200 in order to complete the range.
So, sufficient.
From (2) The lowest rental fee for a 2-room apartment is $800 in the building, we have that:
We have the lowest rental fee for a 2 room but we do not anything about the max value of 2, so clearly insufficient.
(A) is our answer
Range is Max - Min = 1000
Range for 3 - room = Max3 - Min3 =600
From (1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building, we have that:
Min3 - Max2 = 200, then the range will have to be Max3 - Min2 =1000
but since we have Max3 - Min3 =600, Min3-Max2 = 200, the difference between Max2 - Min 2 must be 200 in order to complete the range.
So, sufficient.
From (2) The lowest rental fee for a 2-room apartment is $800 in the building, we have that:
We have the lowest rental fee for a 2 room but we do not anything about the max value of 2, so clearly insufficient.
(A) is our answer
