A certain building has only 2-room and 3-room apartments to rent. If

A certain building has only 2-room and 3-room apartments to rent. If the range of the rental fees of all the apartments in the building is $1,000 and the range of the rental fees for 3-room apartments is $600, what is the range of the rental fees for 2-room apartments?

This is an easy question.
Let's analyze the stem first.
Lets LABEL
2 room Lowest X
2 room Highest Y
3 room Lowest Z
3 room Highest T

Its is given to use that the range combined is 1000
and T-Z = 600 ....1

We are looking for Y - X

Let's analyze the statements now.

(1) The lowest rental fee for a 3-room apartment in the building is $200 more than the highest rental fee for a 2-room apartment in the building.
This gives us Z = Y +200 ....2
This tells us that the highest of the 2 room is still lower than the lowest of the 3 room. Which helps us establish that T - X = 1000 ....3
Y - X = (Puting 2 & 3 here ) Z-200 - T+ 1000 = Z-T +800 . Now put 1 here =T- 600- T + 800 = 200 is the answer.

Hence this statement is correct.


(2) The lowest rental fee for a 2-room apartment is $800 in the building.
This statement is insufficient.

Hence the answer is A.