It is currently 28 Jun 2017, 19:39

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A certain junior class has 1,000 students and a certain

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Intern
Joined: 16 Jan 2013
Posts: 33
Concentration: Finance, Entrepreneurship
GMAT Date: 08-25-2013
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

12 Jul 2013, 23:12
eschn3am wrote:
$formdata=\frac{60*1}{1000*800}+=+\frac{60}{800000}=\frac{3}{40000}$

Let's say you're picking out of the Junior class first and the senior class second (although the order doesn't make any difference). There are 1000 juniors and 60 of them have a sibling in the senior class, so you have a $formdata=\frac{60}{1000}$ shot of choosing one of the siblings. Then you move onto the senior class. There are 800 seniors and only one sibling of the person you chose from the junior class. Thus, you have a $formdata=\frac{1}{800}$ chance of choosing the sibling.

Multiply the two equations together and simplify...and there's your answer.

Hi ,

Don't we need to consider the case where we pick the senior class first and then the junior class.

Plz clarify.

Math Expert
Joined: 02 Sep 2009
Posts: 39753
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

13 Jul 2013, 00:16
Countdown wrote:
eschn3am wrote:
$formdata=\frac{60*1}{1000*800}+=+\frac{60}{800000}=\frac{3}{40000}$

Let's say you're picking out of the Junior class first and the senior class second (although the order doesn't make any difference). There are 1000 juniors and 60 of them have a sibling in the senior class, so you have a $formdata=\frac{60}{1000}$ shot of choosing one of the siblings. Then you move onto the senior class. There are 800 seniors and only one sibling of the person you chose from the junior class. Thus, you have a $formdata=\frac{1}{800}$ chance of choosing the sibling.

Multiply the two equations together and simplify...and there's your answer.

Hi ,

Don't we need to consider the case where we pick the senior class first and then the junior class.

Plz clarify.

These posts might help:
a-certain-junior-class-has-1-000-students-and-a-certain-58914.html#p778756
a-certain-junior-class-has-1-000-students-and-a-certain-58914.html#p812392
_________________
Intern
Joined: 07 Jan 2013
Posts: 43
Location: India
Concentration: Finance, Strategy
GMAT 1: 570 Q46 V23
GMAT 2: 710 Q49 V38
GPA: 2.9
WE: Information Technology (Computer Software)
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

23 Jul 2013, 19:22
i just wanted to validate this answer the other way around i,e to find the no. of ways at least one sibling or no sibling is present in the chosen 2 members and then subtracting from 1 i.e

Req prob =1- (prob of one sibling chosen from either class) + no sibling chosen from either class
= 1-(prob of one sibling from junior) + (prob of one siblng from senior ) + (no sibling)
= 1-$$(\frac{60}{1000}*\frac{799}{800})+(\frac{60}{800}*\frac{999}{1000})+(\frac{740}{800}*\frac{940}{1000})$$

which is coming out to be -ve which obviously is wrong ,, i want to know as to what i am adding extra as a result the answer is -ve
_________________

Help with Kudos if I add to your knowledge realm.

Math Expert
Joined: 02 Sep 2009
Posts: 39753
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

23 Jul 2013, 23:04
1
KUDOS
Expert's post
i just wanted to validate this answer the other way around i,e to find the no. of ways at least one sibling or no sibling is present in the chosen 2 members and then subtracting from 1 i.e

Req prob =1- (prob of one sibling chosen from either class) + no sibling chosen from either class
= 1-(prob of one sibling from junior) + (prob of one siblng from senior ) + (no sibling)
= 1-$$(\frac{60}{1000}*\frac{799}{800})+(\frac{60}{800}*\frac{999}{1000})+(\frac{740}{800}*\frac{940}{1000})$$

which is coming out to be -ve which obviously is wrong ,, i want to know as to what i am adding extra as a result the answer is -ve

It should be: $$1-(\frac{60}{1000}*\frac{799}{800}+\frac{940}{1000}*1)=\frac{3}{40000}$$

$$\frac{60}{1000}*\frac{799}{800}$$ --> p(sibling)*p(any but sibling pair)
$$\frac{940}{1000}*1$$ --> p(not sibling)*p(any)

Hope it's clear.
_________________
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7449
Location: Pune, India
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

30 Sep 2013, 02:35
2
KUDOS
Expert's post
blog wrote:
A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs, each consisting of 1 junior and 1 senior. If i student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?

A. 3/40,000
B. 1/3,600
C. 9/2,000
D. 1/60
E. 1/15

Quote:
Responding to a pm: Why doesn't order matter here?

Check out this post: http://www.veritasprep.com/blog/2013/08 ... er-matter/
It discusses a very similar situation.

Also, whether order matter or not depends on how you perceive it. In probability, you calculate P(A) = P(Favorable Outcomes)/P(Total Outcomes)

Where applicable, you can make the order matter in both numerator and denominator or not make it matter in both numerator and denominator. The answer will be the same.

This Question:

Order Matters:
Favorable outcomes = 60*1 + 60*1
Total outcomes = 1000*800 + 800*1000
P(A) = 3/40,000

Order doesn't matter:
Favorable outcomes = 60*1
Total outcomes = 1000*800
P(A) = 3/40,000

Another case: A bag has 4 balls - red, green, blue, pink (Equal probability of selecting each ball)
What is the probability that you pick two balls and they are red and green?

Order Matters:
Favorable outcomes = 2 (RG, GR)
Total outcomes = 4*3
P(A) = 1/6

Order doesn't matter:
Favorable outcomes = 1 (a red and a green)
Total outcomes = 4C2 = 6
P(A) = 1/6

Previous case: 2 red and 3 white balls. What is the probability that you pick two balls such that one is red and other is white?
In how many ways can you pick a red and a white ball? Here the probability of picking each ball is different. So we cannot cannot use our previous method. Here the probability of picking 2 red balls is not the same as that of picking a red and a white. Hence you have to consider the order to find the complete probability of picking a red and a white.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for \$199

Veritas Prep Reviews

Manager
Joined: 11 Jan 2011
Posts: 69
GMAT 1: 680 Q44 V39
GMAT 2: 710 Q48 V40
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

11 Nov 2013, 19:44
Bunuel wrote:
blog wrote:
A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs , each consisting of 1 junior and 1 senior. If i student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?

A. 3/40,000
B. 1/3,600
C. 9/2,000
D. 1/60
E. 1/15

There are 60 siblings in junior class and 60 their pair siblings in the senior class. We want to determine probability of choosing one sibling from junior class and its pair from senior.

What is the probability of choosing ANY sibling from junior class? $$\frac{60}{1000}$$ (as there are 60 of them).

What is the probability of choosing PAIR OF CHOSEN SIBLING in senior class? As in senior class there is only one pair of chosen sibling it would be $$\frac{1}{800}$$ (as there is only one sibling pair of chosen one).

So the probability of that the 2 students selected will be a sibling pair is: $$\frac{60}{1000}*\frac{1}{800}=\frac{3}{40000}$$

This problem can be solved in another way:

In how many ways we can choose 1 person from 1000: $$C^1_{1000}=1000$$;
In how many ways we can choose 1 person from 800: $$C^1_{800}=800$$;
So total # of ways of choosing 1 from 1000 and 1 from 800 is $$C^1_{1000}*C^1_{800}=1000*800$$ --> this is total # of outcomes.

Let’s count favorable outcomes: 1 from 60 - $$C^1_{60}=60$$;
The pair of the one chosen: $$C^1_1=1$$
So total # of favorable outcomes is $$C^1_{60}*C^1_1=60$$

$$Probability=\frac{# \ of \ favorable \ outcomes}{Total \ # \ of \ outcomes}=\frac{60}{1000*800}=\frac{3}{40000}$$.

Let’s consider another example:
A certain junior class has 1000 students and a certain senior class has 800 students. Among these students, there are 60 siblings of four children, each consisting of 2 junior and 2 senior (I’m not sure whether it’s clear, I mean there are 60 brother and sister groups, total 60*4=240, two of each group is in the junior class and two in the senior). If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?

The same way here:

What is the probability of choosing ANY sibling from junior class? 120/1000 (as there are 120 of them).
What is the probability of choosing PAIR OF CHOSEN SIBLING in senior class? As in senior class there is only two pair of chosen sibling it would be 2/800 (as there is only one sibling pair of chosen one).

So the probability of that the 2 students selected will be a sibling pair is: 120/1000*2/800=3/10000

Another way:
In how many ways we can choose 1 person from 1000=1C1000=1000
In how many ways we can choose 1 person from 800=1C800=800
So total # of ways of choosing 1 from 1000 and 1 from 800=1C1000*1C800=1000*800 --> this is our total # of outcomes.

Favorable outcomes:
1 from 120=120C1=120
The pair of the one chosen=1C2=2
So total favorable outcomes=120C1*1C2=240

Probability=Favorable outcomes/Total # of outcomes=240/(1000*800)=3/10000

Also discussed at: probability-85523.html?hilit=certain%20junior%20class#p641153

Hi Bunuel,

In your second example, how is it possible to have the equation bolded above: 1c2?

Thanks,
Rich
Intern
Joined: 05 Dec 2013
Posts: 2
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

12 Dec 2013, 05:58
jeeteshsingh wrote:
blog wrote:
A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs , each consisting of 1 junior and 1 senior. If i student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?

A. 3/40,000
B. 1/3,600
C. 9/2,000
D. 1/60
E. 1/15

No of ways of choosing 1 sibling pair out of 60 pairs = 60c1
No of ways of choosing 1 student from each class = 1000c1 x 800c1

Therefore probability of having 2 students choosen as a sibling pair = 60c1 / (1000c1 x 800c1) = 60 / (1000 x 800) = 3 / 40000 = A

This was What I thought when I solved this question
Intern
Status: Researching for Schools
Joined: 21 Apr 2013
Posts: 20
Location: United States
Concentration: Leadership, General Management
GMAT 1: 640 Q45 V34
GMAT 2: 730 Q49 V40
WE: Project Management (Computer Software)
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

31 Jan 2014, 14:18
Archit143 wrote:
Can anyone clear my doubt i a m struggling
TOtal number of outcome = 1000*800
Sibbling with Juniors = 60
so 60 out of 1000

Sibling with Senior = 60
so 60 out of 800
we have to find probability of 2 sibbling 1 from each
60 C 1= Selection from Senior
60 C 1 = From Junior
total fav = 1000*800
Prob ={ 60 C 1 *60 C 1}/1000*800
=9/2000

pls tell me where i am wrong in my approach and what correction needed

For the selection from Junior we would have only 1 and not 60 C 1. This is because since we have chosen someone from the senior class and now the only choice we have is the sibling of the senior student we chose.
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16026
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

07 Feb 2015, 03:51
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Intern
Joined: 22 Sep 2014
Posts: 38
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

30 Jul 2015, 00:04
Archit143 wrote:
Can anyone clear my doubt i a m struggling
TOtal number of outcome = 1000*800
Sibbling with Juniors = 60
so 60 out of 1000

Sibling with Senior = 60
so 60 out of 800
we have to find probability of 2 sibbling 1 from each
60 C 1= Selection from Senior
60 C 1 = From Junior
total fav = 1000*800
Prob ={ 60 C 1 *60 C 1}/1000*800
=9/2000

pls tell me where i am wrong in my approach and what correction needed

Mistake that you are doing is that you considering 60 sibling pairs are present in each junior and senior class. But the question says 60 sibling pairs are present and out of these pair one is present in junior and its corresponding sibling in senior. That means 30 in junior and its opposite pair 30 in senior.
_________________

Thanks & Regards,
Vikash Alex
(Do like the below link on FB and join us in contributing towards education to under-privilege children.)

Manager
Joined: 04 Apr 2015
Posts: 87
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

16 Apr 2016, 00:45
another easy understanding
total ways to select the= 1000 X 800 (as each of 1000 juniors can be selected with 800 options)
now
selecting a sibling = 60 ways X 1 way (as there are 60 siblings so we have 60 ways of selecting on student from junior group and as soon as we select one we are left with only one way to select from senior group as that person has only one sibling in the senior group )

req prob=(desired)/total =60x1/1000x800=3/40000 ...(A)

hope this helps
Intern
Joined: 23 Sep 2016
Posts: 8
Re: A certain junior class has 1,000 students and a certain [#permalink]

### Show Tags

06 Nov 2016, 23:21
Bunuel wrote:
blog wrote:
A certain junior class has 1,000 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs , each consisting of 1 junior and 1 senior. If i student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?

A. 3/40,000
B. 1/3,600
C. 9/2,000
D. 1/60
E. 1/15

There are 60 siblings in junior class and 60 their pair siblings in the senior class. We want to determine probability of choosing one sibling from junior class and its pair from senior.

What is the probability of choosing ANY sibling from junior class? $$\frac{60}{1000}$$ (as there are 60 of them).

What is the probability of choosing PAIR OF CHOSEN SIBLING in senior class? As in senior class there is only one pair of chosen sibling it would be $$\frac{1}{800}$$ (as there is only one sibling pair of chosen one).

So the probability of that the 2 students selected will be a sibling pair is: $$\frac{60}{1000}*\frac{1}{800}=\frac{3}{40000}$$

This problem can be solved in another way:

In how many ways we can choose 1 person from 1000: $$C^1_{1000}=1000$$;
In how many ways we can choose 1 person from 800: $$C^1_{800}=800$$;
So total # of ways of choosing 1 from 1000 and 1 from 800 is $$C^1_{1000}*C^1_{800}=1000*800$$ --> this is total # of outcomes.

Let’s count favorable outcomes: 1 from 60 - $$C^1_{60}=60$$;
The pair of the one chosen: $$C^1_1=1$$
So total # of favorable outcomes is $$C^1_{60}*C^1_1=60$$

$$Probability=\frac{# \ of \ favorable \ outcomes}{Total \ # \ of \ outcomes}=\frac{60}{1000*800}=\frac{3}{40000}$$.

Let’s consider another example:
A certain junior class has 1000 students and a certain senior class has 800 students. Among these students, there are 60 siblings of four children, each consisting of 2 junior and 2 senior (I’m not sure whether it’s clear, I mean there are 60 brother and sister groups, total 60*4=240, two of each group is in the junior class and two in the senior). If 1 student is to be selected at random from each class, what is the probability that the 2 students selected will be a sibling pair?

The same way here:

What is the probability of choosing ANY sibling from junior class? 120/1000 (as there are 120 of them).
What is the probability of choosing PAIR OF CHOSEN SIBLING in senior class? As in senior class there is only two pair of chosen sibling it would be 2/800 (as there is only one sibling pair of chosen one).

So the probability of that the 2 students selected will be a sibling pair is: 120/1000*2/800=3/10000

Another way:
In how many ways we can choose 1 person from 1000=1C1000=1000
In how many ways we can choose 1 person from 800=1C800=800
So total # of ways of choosing 1 from 1000 and 1 from 800=1C1000*1C800=1000*800 --> this is our total # of outcomes.

Favorable outcomes:
1 from 120=120C1=120
The pair of the one chosen=1C2=2
So total favorable outcomes=120C1*1C2=240

Probability=Favorable outcomes/Total # of outcomes=240/(1000*800)=3/10000

Bunuel

Is my approach correct?

There are 60 sibling pairs. Probability of Selecting One Junior AND their corresponding Senior sibling OR another Junior and their corresponding sibling and so on:
Probability of Selecting John is: 1/1000
Probability of Selecting John's brother: 1/800
Number of Pairs: 60

So,

1/1000 x 1/800 x 60 = 30/40000 ways to select any one particular Junior and their corresponding Senior Sibling

[ With the breakdown being: P(John and his sibling) + P (Mary and her sibling) + P(Tom and his sibling) + .....
= (1/1000 x 1/800) + (1/1000 x 1/800) + (1/1000 x 1/800) + ..... and so on, until you add the 60 different possibilities ]
Re: A certain junior class has 1,000 students and a certain   [#permalink] 06 Nov 2016, 23:21

Go to page   Previous    1   2   [ 32 posts ]

Similar topics Replies Last post
Similar
Topics:
9 For each student in a certain class, a teacher adjusted the student’s 2 12 Jun 2017, 21:10
3 At a certain high school, the junior class is twice the size 6 06 Dec 2016, 11:05
7 A certain freshman class has 600 students and a certain sophomore 18 02 Jan 2017, 05:10
24 A certain junior class has 1000 students and a certain 18 26 Jun 2016, 11:05
12 A certain junior class has 1000 students and a certain 9 31 May 2017, 22:46
Display posts from previous: Sort by

# A certain junior class has 1,000 students and a certain

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.