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# A computer programmer needs to print 148 documents. The documents have

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A computer programmer needs to print 148 documents. The documents have  [#permalink]

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12 Nov 2015, 02:07
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Difficulty:

15% (low)

Question Stats:

81% (01:34) correct 19% (01:45) wrong based on 198 sessions

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A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr
(B) 2 hr
(C) 2 1/2 hr
(D) 6 hr
(E) 24 hr

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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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12 Nov 2015, 02:45
148 documents with an average of 10 pages each
we therefore have 1480 as the total no of pages
time taken =1480*15/60*60 in hours
6.04 hours
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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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12 Nov 2015, 02:48
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Bunuel wrote:
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr
(B) 2 hr
(C) 2 1/2 hr
(D) 6 hr
(E) 24 hr

Total number of documents = 148
Average length of a document = 148 *10 = 1480

Time taken to print 1 page = 15 sec
Pages printed in 1 min = 4
Pages printed in an hour = 4*60 = 240

Time taken = 1480/ 240= 6 hours 10 mins

If the number of document were 144 then total pages would have been 1440 . That would have given us 6 hours .
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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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12 Nov 2015, 07:35
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Bunuel wrote:
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr
(B) 2 hr
(C) 2 1/2 hr
(D) 6 hr
(E) 24 hr

CONCEPT: $$\frac{(Machine_Power * Time)}{Work} = Constant$$
i.e. $$\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}$$

Work ($$W_2$$) = 148 Documents = 1480 Pages
Time ($$T_2$$) = ?

$$\frac{(1 * 15)}{1} = \frac{(1 * T_2)}{1480}$$

$$T_2 = 1480*15 secs = 1480*15/3600 Hours = 6.16 Hours$$

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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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15 Nov 2015, 10:34
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Number of Documents = 148.
Avg. Number of pages per document = 10.
Total Pages = 148 * 10 = 1480.

Speed of Printer = 15 Seconds Per Page.
so , 1 Page = 15 Seconds.
1480 Pages = 15 * 1480 = 22200 Seconds.
Value in Hours = 22200 / (60*60) = ~6 Hours.
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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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15 Nov 2015, 12:23
Bunuel wrote:
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages

Total number of pages required to be printed is 148*10 = 1480 pages.

Bunuel wrote:
The printer takes 15 seconds to print each page.

So, in 1 minute 4 pages will be printed.
In 1 Hour 240 pages will be printed.

Bunuel wrote:
Approximately how many hours will it take to print all the documents if they are printed without interruptions?

Time taken to print 1480 pages is 1480/240=>6.17 hours ~ 6 Hours.

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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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31 Jan 2017, 18:44
Simple

148*10 = 1480 ---> # of total pages
4 pages/ min (15 secs each to print 4 pages)
1480/4 = # number of minutes
360 = min
360/6 = num of hours
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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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15 May 2018, 16:13
Bunuel wrote:
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr
(B) 2 hr
(C) 2 1/2 hr
(D) 6 hr
(E) 24 hr

It will take (148 x 10) x 15 = 1480 x 15 seconds to complete printing all the documents. We convert seconds to hours (3600 seconds in one hour), obtaining:

(1480 x 15)/3600 = (148 x 15)/360 = 148/24 ≈ 6 hours.

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Re: A computer programmer needs to print 148 documents. The documents have  [#permalink]

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29 Sep 2018, 08:04
Top Contributor
Bunuel wrote:
A computer programmer needs to print 148 documents. The documents have an average (arithmetic mean) length of 10 pages and the printer takes 15 seconds to print each page. Approximately how many hours will it take to print all the documents if they are printed without interruptions?

(A) 1/2 hr
(B) 2 hr
(C) 2 1/2 hr
(D) 6 hr
(E) 24 hr

We can also answer this question using a step-by-step approach based on number sense.

IMPORTANT: The word approximately typically suggests that we can be somewhat aggressive with our estimation

There are 148 documents and the documents have an average length of 10 pages
So, the TOTAL number of pages to print = (148)(10) = 1480 ≈ 1500

The printer takes 15 seconds to print 1 page
This means the printer takes 60 seconds to print 4 pages
In other words, the printer takes 1 MINUTE to print 4 pages
So, the printer takes 60 MINUTES to print 250 pages
In other words, the printer takes 1 HOUR to print 250 pages
So, the printer takes 2 HOURS to print 500 pages
So, the printer takes 6 HOURS to print 1500 pages

Cheers,
Brent
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Re: A computer programmer needs to print 148 documents. The documents have &nbs [#permalink] 29 Sep 2018, 08:04
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