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Initially, base (Point E) of 25 feet long ladder (AE) is 7 meter away from the base of wall (Point B).
height of the top point (A) can be found using Pythagoras Theorem
AB = sqrt(AE^2-BE^2)
= sqrt (25^2-7^2) = sqrt (625-49) = sqrt(576) =24
When the top of the ladder slips 4 meter, height of top point reduces by 4 meter.
Now, as per diagram, DC is ladder and BD is height of top point and BC is the distance of base of ladder from wall.
we have , DC = 25, BD = 24-4 = 20,
By Pythagoras theorem, BC = sqrt (DC^2-BD^2) = sqrt (25^2-20^2) = sqrt(625-400)=sqrt (225) = 15
base point has slipped by a distance EC which can be found by subtracting BE from BC
EC = BC-BE = 15-7 = 8 .
Hence option C is the answer.
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