Dear Kanusha,
I'm happy to respond to your p.m.

First of all, let's think about this --- the perfect squares greater than 1 are 4, 9, 16, 25, 36, 49, etc. Any numbers divisible by these would not be square-free, and any number that doesn't not happen to be a multiple of these would be square-free. Notice, in particular, all prime numbers are automatically square-free. The first few square-free numbers would be

1, 2, 3, 5, 6, 7, 10, 11, 13, 14 ,15, 17, 19, 21, 22, 23, 26, 29, 30, ....

The problem tells us that n is an even square-free numbers, so candidate could include 2, 6, 10, 14, 22, 26, 30 --- all of these are even numbers that are NOT divisible by 4, so they are the odd multiples of 2, and not even all of those, because some (such as 18) are divisible by other squares (18 is divisible by 9).

Let's think about these .....
(A) n/2 --- using our example even square-free numbers above, this leads to 1, 3, 5, 7, 11, 13, 15 --- all square free --- hmmmm, this is promising
(B) Any even number time 2 is divisible by 4 --- this always leads to a number divisible by a square, i.e. NOT square-free. This is incorrect.
(C) Any odd multiple of 2, plus two, will equal an even multiple of two --- i.e. a multiple of 4, a number that is NOT square-free. This is incorrect.
(D) n^2 would be even times even, which is always divisible by four, i.e. NOT square-free. This is incorrect.
(E) hmmm.

It's very easy to eliminate (B) & (C) & (D). In order to choose (A) over (E), we have to be sure that (A) works, not just for some examples that we pick, but for all possible even square-free numbers. Here's an argument, involving factors.

Suppose n is an even square-free number. As we have seen, it must be an odd multiple of two. This means n = 2*q, where q is some odd number. Because n has no factors that are squares, this necessarily means that q has no factors that are squares. (If P = R*Q, then any factor of Q or R must be a factor of P.) Now, n/2 = q, and q has no square factors, so if n is square-free, then n/2 = q must be square-free. That's why (A) must be the correct answer.

Does all this make sense?
Mike
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Per definition a square-free integer has primes in power of 1. For example 5^3 is NOT square-free because it's a multiple of 5^2.

We are told that n=2k, since n itself is square-free, then k also must be square-free --> n/2=k.

Answer: A.

Or just pick some number for n. Say n=2, then among A, B, C, and D, only A (n/2=1) will be square free.

Hope it's clear.
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These definition questions tend to be tricky. I usually get thrown off by such questions... do you have any questions for practice?

Similar questions:

A "square-free"integer: a-positive-integer-is-called-square-free-if-it-has-no-fact-159462.html

A “Sophie Germain” prime: a-sophie-germain-prime-is-any-positive-prime-number-p-for-132650.html

A Farey sequence: a-farey-sequence-of-order-n-is-the-sequence-of-fractions-129825.html

A “coprime sequence: an-infi-nite-sequence-of-positive-integers-is-called-a-127496.html

A perfect sequence: an-infinite-sequence-of-positive-integers-is-called-a-127696.html

Twin primes: twin-primes-are-defined-as-prime-numbers-that-can-be-express-128433.html

Length of an integer: for-any-positive-integer-n-n-1-the-length-of-n-is-the-126368.html, for-any-integer-k-1-the-term-length-of-an-integer-108124.html, for-any-positive-integer-n-the-length-of-n-is-defined-as-126740.html

"Rhyming" primes: two-different-primes-may-be-said-to-rhyme-128903.html

The “connection” between integers: the-connection-between-any-two-positive-integers-a-and-b-128360.html
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Found two more questions:
"Rhyming" primes: two-different-primes-may-be-said-to-rhyme-128903.html
The “connection” between integers: the-connection-between-any-two-positive-integers-a-and-b-128360.html
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Will not pop into too much:

We will do it by hit and trial:

Since 'n' is an even-square free integers.

Then check values of 'n'

n=2 ..... Can be square free
n=4 ... Cannot be since 4 is a factor of 4
n=6.... Can be square free since 6=3*2*1
n=8... Cannot be


Try n=2,6 in answer options and hence (A) it is

Another way to solve this is to take n = 6
Now A is the answer

If the Number is a "Square-Free" Number and it is ALSO Even ---


this Means that whatever the Number is, it must ONLY Contain 1 Prime Base = 2

For ex: N = 2 * 3 * 5 = 30, would be an EVEN Square Free Number, because NONE of the Prime Bases are Raised to a Power > 1 (thus, we will not have any Factors that are Perfect Squares) and it has 1 Prime Base of 2

If we divide this Even Square Free Number by 2, it will remove the 1 Prime Base of 2, leaving only the other Prime Bases which already can NOT "create" a Number with a Perfect Square as a Factor.

The remaining Number N after dividing by 2 will be an ODD "Square Free" Number.

Answer -A- N/2

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