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# A Trussian's weight, in keils, can be calculated by taking

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Manager
Joined: 19 Aug 2006
Posts: 198
A Trussian's weight, in keils, can be calculated by taking  [#permalink]

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30 May 2007, 21:25
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Question Stats:

100% (00:00) correct 0% (00:00) wrong based on 10 sessions

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A Trussian's weight, in keils, can be calculated by taking the square root of his age in years. A Trussian teenager now weighs three keils less than he will seventeen years after he is twice as old as he is now. How old is he now?

(A) 14
(B) 15
(C) 16
(D) 17
(E) 18

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Director
Joined: 26 Feb 2006
Posts: 823
Re: PS-Trussian's weight  [#permalink]

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30 May 2007, 21:50
johnycute wrote:
A Trussian's weight, in keils, can be calculated by taking the square root of his age in years. A Trussian teenager now weighs three keils less than he will seventeen years after he is twice as old as he is now. How old is he now?

(A) 14
(B) 15
(C) 16
(D) 17
(E) 18

i am not sure how good is the question.

is it D?
Senior Manager
Joined: 04 Mar 2007
Posts: 390

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30 May 2007, 23:40
My equation is
sqrt(x) = sqrt(2x+17)-3
Is it right?

If yes, then the answer is C

sqrt(16)=sqrt(32+17)-3
16=49+9-2*3*sqrt(49)
16=16

Please check my equation. I am not sure about it
Manager
Joined: 25 May 2007
Posts: 209
Schools: Cornell
Re: PS-Trussian's weight  [#permalink]

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31 May 2007, 01:10
2
C.

Word Translation:

"weight = square root of age": W = V(A)

"seventeen years after he is twice as old as he is now": [2A + 17]

His weight is then V[2A + 17]

"now weighs three keils less than...": W = V[2A + 17] - 3; or W + 3 = V[2A + 17]

Recall that W = V(A),

Therefore: V(A) + 3 = V[2A + 17]

[V(A) + 3]^2 = 2A + 17
A +6V(A) + 9 = 2A + 17
[V(A) - 2] * [V(A) - 4 ] = 0

A = 4 or A = 16, while Answer Choice C is 16, which matches.
Manager
Joined: 19 Aug 2006
Posts: 198
Re: PS-Trussian's weight  [#permalink]

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31 May 2007, 02:09
solidcolor wrote:
C.

Word Translation:

"weight = square root of age": W = V(A)

"seventeen years after he is twice as old as he is now": [2A + 17]

His weight is then V[2A + 17]

"now weighs three keils less than...": W = V[2A + 17] - 3; or W + 3 = V[2A + 17]

Recall that W = V(A),

Therefore: V(A) + 3 = V[2A + 17]

[V(A) + 3]^2 = 2A + 17
A +6V(A) + 9 = 2A + 17
[V(A) - 2] * [V(A) - 4 ] = 0

A = 4 or A = 16, while Answer Choice C is 16, which matches.

Ya Its correct....

Answer is 16.....

Now think if the chioces have both 4 and 16 then what could be the answer? .....
Director
Joined: 26 Feb 2006
Posts: 823

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31 May 2007, 08:35
Caas wrote:
My equation is
sqrt(x) = sqrt(2x+17)-3
Is it right?

If yes, then the answer is C

sqrt(16)=sqrt(32+17)-3
16=49+9-2*3*sqrt(49)
16=16

Please check my equation. I am not sure about it

oh i did not get the question.
you are right. good job.
Manager
Joined: 11 Jun 2006
Posts: 243

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31 May 2007, 09:29
I had no idea how to set up this problem... the "now weighs three keils less than..." part threw me off, however I did get the right answer...

I realized that the part of the equation that gave years now was V(17+2Y)

Plugging in numbers, I realized quickly that only 16 would yield an integer.

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This discussion does not meet community quality standards. It has been retired.

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Non-Human User
Joined: 09 Sep 2013
Posts: 11016
Re: A Trussian's weight, in keils, can be calculated by taking  [#permalink]

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06 Apr 2019, 02:16
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Re: A Trussian's weight, in keils, can be calculated by taking   [#permalink] 06 Apr 2019, 02:16
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# A Trussian's weight, in keils, can be calculated by taking

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