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# Data Insights Question of the Day

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Re: Data Insights Question of the Day [#permalink]
Each of the coins in a collection is distinct and is either silver or gold. In how many
different ways could all of the coins be displayed in a row, if no 2 coins of the same color
(1) The display contains an equal number of gold and silver coins.
(2) If only the silver coins were displayed, 5,040 different arrangements of the silver coins
would be possible.

I was wondering how to actually find the possible ways of arrangement. Is it 7! * 8?
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Re: Data Insights Question of the Day [#permalink]
When combining the statements, we find that there are 7 distinct gold coins and 7 distinct silver coins in the collection. They can be arranged in a row such that no two coins of the same color are adjacent in 7! * 7! * 2 ways. Consider the following two scenarios:

GSGSGSGSGSGSGS
SGSGSGSGSGSGSG

For each of these scenarios, the number of ways to arrange the coins is 7! * 7!. Therefore, the total number of ways is 7! * 7! * 2.
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Re: Data Insights Question of the Day [#permalink]
Thank you
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Re: Data Insights Question of the Day [#permalink]
Hey, are you able to solve those questions without a time constraint?

And if so, how much time are you taking per question?
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Re: Data Insights Question of the Day [#permalink]
Bunuel wrote:
When combining the statements, we find that there are 7 distinct gold coins and 7 distinct silver coins in the collection. They can be arranged in a row such that no two coins of the same color are adjacent in 7! * 7! * 2 ways. Consider the following two scenarios:

GSGSGSGSGSGSGS
SGSGSGSGSGSGSG

For each of these scenarios, the number of ways to arrange the coins is 7! * 7!. Therefore, the total number of ways is 7! * 7! * 2.

Why did you multiply by 2 ?

Is it because theyll always be one of 2 scenarios just that the individual coin will be different accounted for by the 7! ?
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Re: Data Insights Question of the Day [#permalink]
 Data Sufficiency Butler: June 2024 June 19 DS 1 DS 2
­
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Re: Data Insights Question of the Day [#permalink]
 Data Sufficiency Butler: June 2024 June 20 DS 1 DS 2
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Re: Data Insights Question of the Day [#permalink]
 Problem Solving Butler: June 2024 June 20 PS 1 PS 2
­
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Re: Data Insights Question of the Day [#permalink]
 Data Sufficiency Butler: June 2024 June 21 DS 1 DS 2
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Re: Data Insights Question of the Day [#permalink]
Can someone help with this

A milk vendor mixes water with milk and sells the mixture at the same price per liter as if it were undiluted milk. The selling price per liter of the mixture is the vendor’s cost per liter of the milk plus a markup of x %. The water costs the vendor nothing. If the vendor gets a 50% profit on the sale of the mixture, what is the value of x ?

(1) If the vendor mixes half the intended quantity of water and sells every liter of the mixture at the cost price per liter of the undiluted milk, the vendor will get a 10% profit.

(2) The concentration of milk in the mixture after adding water is 5/6.
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Re: Data Insights Question of the Day [#permalink]
ribbons wrote:
Can someone help with this

A milk vendor mixes water with milk and sells the mixture at the same price per liter as if it were undiluted milk. The selling price per liter of the mixture is the vendor’s cost per liter of the milk plus a markup of x %. The water costs the vendor nothing. If the vendor gets a 50% profit on the sale of the mixture, what is the value of x ?

(1) If the vendor mixes half the intended quantity of water and sells every liter of the mixture at the cost price per liter of the undiluted milk, the vendor will get a 10% profit.

(2) The concentration of milk in the mixture after adding water is 5/6.

­Check here:

https://gmatclub.com/forum/a-milk-vendo ... 30880.html
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Re: Data Insights Question of the Day [#permalink]
I got this question from there only, the explanations dont make sense to me, would appreciate further help
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Re: Data Insights Question of the Day [#permalink]
Hello all,
can anyone explain me the below question:

especially the last q3
why can we not select option b?
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Re: Data Insights Question of the Day [#permalink]
when-the-kj-reservoir-kjr-was-built-a-single-well-known-species-of-327842.html
for question one how are we calculating 1200? in the answer below it mentions put the data in the equation, but what data are they talking about? where is it mentioned in the passage? i am not sure what am i missing here?
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Re: Data Insights Question of the Day [#permalink]
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Re: Data Insights Question of the Day [#permalink]
Astha_shri wrote:
https://gmatclub.com/forum/when-the-kj- ... 27842.html
for question one how are we calculating 1200? in the answer below it mentions put the data in the equation, but what data are they talking about? where is it mentioned in the passage? i am not sure what am i missing here?

Common in both / N = M / Total fish

Sorry Total Animals*

if you check 3rd tab it says "On May 1 last year, KJR’s wildlife management team marked the 60 fish comprising the capture group. The recapture group had 100 fish, including exactly 5 from the capture group."

Common in both = 5, M = (M) of individual animals of the species (the capture group) = 60, N = A number (N) of individual animals are then captured in a second group (the recapture group) = 100 put these values in above equation and calculate Total animals as per the given formula from 2nd tab.
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Re: Data Insights Question of the Day [#permalink]
BineetaRath wrote: