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I have doubt in the first question:
the-following-graph-shows-the-results-of-a-survey-taken-in-14-markets-421058.html#p3292609

On increasing x by 1% equation becomes y’=mx(1+0.01)+c=y+mx/100
Also mx=y-c
hence %change = (y’ - y)100/y = (y-c)/y
Now here c=(-17.6)
So %change=1 + 17.6/y
All I know is >1% increase
how did we conclude it should be 1.1% and not 1.7%?
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Rahul885
I have doubt in the first question:
the-followin ... l#p3292609

On increasing x by 1% equation becomes y’=mx(1+0.01)+c=y+mx/100
Also mx=y-c
hence %change = (y’ - y)100/y = (y-c)/y
Now here c=(-17.6)
So %change=1 + 17.6/y
All I know is >1% increase
how did we conclude it should be 1.1% and not 1.7%?
Yes, the percentage change in value of Y(Percentage of women) will vary from 1.18% to infinite.... {depending on the value of X, in which 1% is increased}
I think the question should have been... "The line of best fit suggests that a 1% increase in the number of men who read the daily paper corresponds to a minimum ________ in the number of women who read the daily paper."
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KuldeepKatiyar
Yes, the percentage change in value of Y(Percentage of women) will vary from 1.18% to infinite.... {depending on the value of X, in which 1% is increased}
I think the question should have been... "The line of best fit suggests that a 1% increase in the number of men who read the daily paper corresponds to a minimum ________ in the number of women who read the daily paper."
Bunuel, your opinion...?
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starting DI prep as beginner, any post or set of questions i shud start with?
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Can anybody share the link of tpa data insight official review questions

official-guide-data-insight-review-graphs-question-directory-426922.html#p3363680

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This would help you.......................
list-of-questions-426631.html#p3359836
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thanks . Kindly share the same for tables , graph also
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