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Family seating - MGMAT

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Manager
Manager
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Joined: 11 Apr 2009
Posts: 159

Kudos [?]: 122 [0], given: 5

Family seating - MGMAT [#permalink]

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New post 20 May 2009, 15:41
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A family consisting of one mother, one father, two daughters and a son is taking a road trip in a sedan. The sedan has two front seats and three back seats. If one of the parents must drive and the two daughters refuse to sit next to each other, how many possible seating arrangements are there?
28
32
48
60
120

Kudos [?]: 122 [0], given: 5

Senior Manager
Senior Manager
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Joined: 08 Jan 2009
Posts: 324

Kudos [?]: 191 [0], given: 5

Re: Family seating - MGMAT [#permalink]

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New post 20 May 2009, 22:47
I got the answer as 32.

I just puttin all the seat in straight row. Front + Back

the diff combinations are

2 *D1 * 3 * 2 * 1 = 12
2 *D2 * 3 * 2 * 1 = 12
2 *M/F * 2 * 1 * 1 = 4
2 *S *2 * 1 * 1 = 4

So 12 + 12 + 4 + 4 = 32.

Not so confident on probability.

Kudos [?]: 191 [0], given: 5

Re: Family seating - MGMAT   [#permalink] 20 May 2009, 22:47
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Family seating - MGMAT

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