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Here is an official explanation how to solve this problem:

Let x kg dry grapes be obtained. Then, solid part in fresh grapes = solid part in dry grapes
0.1*20=0.8x*x
x=2,5

I do not find this explanation an approriate one because something must be wrong with 0.8x*x.

Can somebody suggest an alternative way of solution?
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feruz77
Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 20 kg of fresh grapes?
a) 2 kg
b) 2.4 kg
c) 2.5 kg
d) 10 kg
e) none of these


another attempt to make this question easier to understand

question is asking what amount of dry grapes will yield mass of 2 kg

or
80 % of what = 2 kg

answer 2.5
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10% of 20 kg = 2kg is without water, there is no water at all in these 2 kg but we need weight with 20% of water and 80% without water. Let X be the weight with 20% water. Therefore X will have the same 2 kg without water, that means these 2kg will be 80% of X, therefore:

80% of X = 2kg
=> X = 2.5kg

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Since the grape content will remain the same
For 20 Kg fresh water grapes if water=90%, grape content= 10%
so 10% of 20= 2 Kg
So in the dry grape, grape content = 2kg
Here water: grape content= 20:80= 1:4 so for 2 kg grape content, water= 0.5: 2
Hence total weight= 2.5 Kg
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Since,
Dry grapes+Water = Fresh grapes
One can also do this problem by alligating water.
DRY GRAPES(water)______WATER
________20_________________100
________'________90_________'
________10_________________70
Ratio=> 10 : 70 = 1:7
The weight of Dry grapes
= 1/8×20 = 2.5kgs


I hope this method will help to solve such questions quickly.

Thank you!

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Please find solution in the attached image.
Attachments

IMG_20201013_191228.jpg
IMG_20201013_191228.jpg [ 1.68 MiB | Viewed 21815 times ]

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20 kg fresh grapes contains 18 kg (90%) water and remaining 2 kg (20-18 kg) pulp.

When grapes is dried, pulp content remains same (2 kg), whereas water gets dried to lets say x kg.

x kg is 20 % of the entire weight (x+2) kg {water + pulp content}

Therefore, x=0.2(x+2). Hence x=0.5 kg.

Weight of dried grapes = 2 kg (pulp) + 0.5 kg (water) = 2.5 Kg
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Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 20 kg of fresh grapes?

It's given that fresh grapes contain 90% water by weight , that means non-water content in fresh grapes will be 10% by weight.
Similarly, dried grapes contain 20% water by weight, so we can also say that non-water content in dried grapes will be 80% by weight.


Here we need to find the weight of dry grapes available from 20 kg of fresh grapes.

Assume that weight of dried grapes available would be X.

So, the non- water content of 20 kg of fresh grapes will be equal to non-water content of X kg of dried grapes available from that.

10% of 20 = 80 % of X

X= 10* 20 / 80 = 20/8 = 2.5 kg

Option C is the answer.

Thanks,
Clifin J Francis,
GMAT SME
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feruz77
Fresh grapes contain 90% water by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 20 kg of fresh grapes?

A. 2 kg
B. 2.4 kg
C. 2.5 kg
D. 10 kg
E. none of these


Pulp from fresh grapes = 10% of 20 = 2 kg
Pulp from dried grapes = 80% of x = 0.8x kg
Thus: 0.8x = 2
=> x = 2.5 kg

Answer C
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