GMAT Club Around The World!!! In a certain country, m farmers each own

Question

In a certain country, m farmers each own n cows, each cow produces p gallons of milk per day. If r percent of the cows suddenly drop production by s percent each, then what is the new daily total production of milk in gallons for all farmers?

A. mnp - rs

B. mnp (1 - (rs/10000))

C. mnp (1 - (rs/100))

D. mnp + mnprs

E. mnp - mnprs

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zhanbo · Answer

My answer is  B. mnp (1 - (rs/10000))

Before the sudden drop. Total output is : mnp

If r percent of the cows suddenly drop production by s percent each, total drop is
(mn)*(r/100)*(s/100)*p

ANS = mnp - (mn)*(r/100)*(s/100)*p

RajatJ79 · Answer

Solution  -

m farmers each own n cows, each cow produces p gallons of milk per day.

Total milk produced is = m*n*p

r percent of the cows suddenly drop production by s percent each

Reduction in production is by 
 \frac{r *s}{100*100}

Production remaining would be -
  m*n*p (1 - \frac{r *s}{100*100})

Answer should be Option B .

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Deepakjhamb · Answer

B. mnp (1 - (rs/10000))

answer is b

cows producing less milk production = mn r/100 p (1-s/100)

cows producing same milk = mn (1-r/100) p we add both to get b as answer

ananya3 · Answer

IMO B

farmers = m
cows owned by each farmer = n
milk produced by each cow per day = p gallons

total cows = mn
total milk production before the reductions = mnp

r percent of the cows =  \frac{r}{100} * mn 
drop in milk production by each cow =  \frac{s}{100} * p 
drop in production overall =  \frac{r}{100} * mn * \frac{s}{100} * p

new production = original - drop 
=  mnp - \frac{r}{100} * mn * \frac{s}{100} * p 
= mnp (1- rs/10000)

rocky620 · Answer

Total Cows = m*n
Initial total production = m*n*p

Reduction in output = m*n*(r/100)*(ps/100), as r% of cows reduced the production p by s% each

New output = mnp - mnprs/10000 =  mnp(1-(rs/10000))

IMO Option B

Green2k1 · Answer

Correct Answer B

In a certain country, m farmers each own n cows, each cow produces p gallons of milk per day. If r percent of the cows suddenly drop production by s percent each, then what is the new daily total production of milk in gallons for all farmers?

------------no. of Farmer ---------------- No. of Cows-------------gallon of Milk 
Initial: .... m-------------------------------n--------------------------- p
Later reduction:m------------------------r% of n---------------------s%ofp

New Daily production: mnp - m*rn/100*sp/100
 : mnp (1- rs/10000)

TarunKumar1234 · Answer

Given, farmers=m, each own cows=n, each cow produces gallons of milk per day=p
Total Milk production = m*n*p

cows suddenly drop production =r%, milk production reduced= s% each
Reduction in milk = m*n*r/100 *p*s/100

Total production after reduction= m*n*p- m*n*r/100 *p*s/100= m*n*p (1-rs/10000)
So, I think B.

manasi05 · Answer

m farmers own each n cows so total number of cows = mn
each cow produces p gallons of milk per day so total milk produced by mn cows = mnp
r percent of cows drop production by s percent each
So mnr/100 cows are producing p(1- s/100) gallons each
Total milk production by mnr/100 cows will be (mnr/100)*p(1-s/100) = mnpr/100(1-s/100)
Rest of the cows are producing p gallons as before 
Rest of cows = mn(1-r/100)
Milk produced by rest of the cows= p*mn(1-r/100) = mnp(1-r/100)
Total production= 
mnpr/100(1-s/100) +mnp(1-r/100)
=mnp( r/100(1-s/100) + (1-r/100))
= mnp (r/100 - rs/10000 +1 -r/100)
= mnp (1-(rs/10000))

So the answer will be B

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GMAT Club Around The World!!! In a certain country, m farmers each own

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