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Is x^2 less than or equal to 10y^2? or Is x^2 > 10y^2?

(1) 0 < x < 2
No information about y.

Insufficient

(2) 1 < y < 2
No information about x.

Insufficient

Combining 1 & 2
0 < x < 2
so, 1<\(x^2\)<4. Minimum value of \(x^2\) can be 0 and maximum value can be 4

1 < y < 2
1<\(y^2\)<4.

Multiply by 10

10<10\(y^2\)<40. Minimum value of 10\(y^2\) can be 10 and maximum value can be 40

In both the cases the minimum value of 10\(y^2\) is greater than maximum value of \(x^2\)

so 10y^2>x^2.

Sufficient

IMO Option C
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By combining the 2 conditions, we see that y is always bigger than 1. So 10*y^2 is more than 10 and x^2 will be under 4.


We need these two conditions to be certain about the answer.

PUSH C
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IMO C

Que: \(x^2 <= 10y^2\)?

(1) 0 < x < 2
case 1: if \(x = 1, y = \frac{1}{5}\)
\(x^2 = 1\)
\(10 * y^2 = \frac{10}{25} = \frac{2}{5}\)
=>\( 1 > \frac{2}{5}\)

case 2: if x = 1, y = 2
\(x^2 = 1\)
\(10 * y^2 = 10 * 4 = 40\)
=> 1 < 40
NOT SUFFICIENT


(2) 1 < y < 2
case1: if \(x = 1, y = \frac{3}{2}\)
\(x^2 = 1\)
\(10 * y^2 = 10 * \frac{9}{4} = \frac{90}{4}\)
=> 1 < 90/4

case 2: if \(x = 5, y=\frac{3}{2}\)
\(x^2 = 25\)
\(10 * y^2 = \frac{90}{4}\)
\(25>\frac{90}{4}\)
NOT SUFFICIENT

combining 1 and 2
\(0 < x < 2 => 0 < x^2 < 4\)
\(1 < y < 2 => 10 < 10* y^2 < 40\)
=> \(x^2 < 10*y^2\)
SUFFICIENT
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Is x^2 less than or equal to 10y^2?

Stat1: 0 < x < 2, not sufficient, as we need value of y
Stat2: 1 < y < 2, not sufficient, as we need value of x

Combining both, 0 < x < 2 & 1 < y < 2
Between 0<x<1, x^2 less than 10y^2, and between 1<=x<2, x^2 less than than 10y^2.

So, It is C. :)
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Is x^2 less than or equal to 10y^2?

(1) 0 < x < 2
(2) 1 < y < 2

Individual statements are not sufficient because they talk about either x or y, but not both.
Combine:
Let us assume maximum value of x and minimum value of y.
Let x = 2 and y = 1 (These values are out of range, but will suffice)
Is \(x^2 <= 10 y^2\)?
4 <= 10 (yes)
So the value of \(x^2\) will always be less than 10\(y^2\)
Combining is sufficient.

Answer C.
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Correct Answer C

Is x^2 less than or equal to 10y^2?
x^2 <= 10y^2
-root (10y^2) <= x <= root (10y^2)
Approx -3y <= x <= 3y


(1) 0 < x < 2
- do not know anything about y range
- Not Sufficient


(2) 1 < y < 2
- don't know anything about x range
- Not Sufficient

Together
when y= 1
-3y <= x <= 3y
-3 < x<3
y=2
-6<x<6

Given 0<x<2 - it is well within the range
Sufficient
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x^2 <= 10 y^2 ?
To find the answer we will need the information about x and y both

Statement 1
0 < x < 2
Gives no information about y hence not sufficient

Statement 2
1 < y < 2
Gives no information about x hence not sufficient

Combining statement 1 and 2 we have
0 < x < 2 from this we can find the range for x^2
0 < x^2 < 4
1 < y < 2 from this we can find the range for y^2
1 < y^2 < 4
The range for 10y^2 will be
10 < 10y^2 < 40
The range for 10y^2 is bigger than x^2 hence x^2 < 10y^2 — Hence Sufficient

So the answer will be C
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Bunuel
Is x^2 less than or equal to 10y^2?

(1) 0 < x < 2
(2) 1 < y < 2




Happy New Year Myanmar!

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IMO option C is correct.

From each statement alone, no conclusion can be made.

when both sentences are taken together, 10y^2 is always greater than x^2 in the defined range of each variable.
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