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First, let's understand the pricing structure. For a trip of x miles:
- If x≤ 5 miles, the charge is p dollars
- If x> 5 miles, the charge is p + 0.1p(x - 5) = p + 0.1p(x-5) = p(1 + 01(x - 5)) dollars
For a trip of exactly 30 miles, the charge would be:
p + 0.1p(30 - 5) = p + 01p(25) = p + 2.5p = 3.5p dollars
So the trip is more than 30 miles long if the charge exceeds 3.5p dollars.
Statement (1): The moving service charged a total of 3.3p dollars for the trip.
Using our formula: 3.3p = p + 0.1p(x - 5)
33p - p= 0.1p(x - 5)
2.3p = 0.1p(x - 5)
23 =x-5
x= 28 miles
Since x= 28 miles, which is less than 30 miles, the answer is "No, the trip was not more than 30 miles long." Statement (1) is sufficient.
Statement (2): The moving service charged a total of $132 for the trip.
We know the charge is $132, but we don't know the value of p. We only know p > 30.
If p= 40, then a 30-mile trip would cost 3.5p = 3.5(40) = $140, which means a $132 trip would be less than 30 miles.
If p = 33, then a 30-mile trip would cost 3.5p = 3.5(33) = $115.50, which means a $132 trip would be more than 30 miles.
ince we get different answers depending on the value of p, Statement (2) alone is not sufficient.
The answer is A) Statement 1 alone is sufficient, but statement 2 alone is not.
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Statement (1):
We can compute how many miles this corresponds to.
Let’s denote the number of additional miles (beyond the first 5) as x.
So:
Total cost = p +0.1*p*x = 3.3p
x = 2.3/0.1 = 23 miles
Total trip distance = 5 miles+23 miles=28 miles
So the trip was not more than 30 miles.
Statement (1) alone: Sufficient

Statement (2):
We don’t know the value of p, only that p > 30
There are multiples values of p with which trip distance can be > 30 miles or < 30 miles
Statement (1) alone: Not Sufficient

Answer A.
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Ans: A

A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?
p + x * 0.1*p = charges (x here is miles addition to 5 miles)
We need to find if 5 + x > 30

(1) The moving service charged a total of 3.3p dollars for the trip.
so p + x * 0.1p = 3.3p
x = 2.3/0.1 = 23
5 + x = 28 which is less than 30 [Sufficient to answer if 5+ x>30]

(2) The moving service charged a total of $132 for the trip.
p>30
so lets put p = 31
31 +x * 0.1(31) = 132
x * 3.1 =101
x = 101/31 = 32.x (here 32+5 > 30)

lets put p =100
100 + x * 100*.1 = 132
x = 32/100 = 3.2 (here 32+5 < 30)
so statement 2 [Not Sufficient]


 


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Let D be the total length of the trip in miles.

The cost structure is:

First 5 miles = p dollars

Each additional mile (or fraction) = 0.1p dollars

So, if D≤5, the cost is p.
If D>5, the cost is p+0.1p(D−5).

We want to determine if D>30.

Statement (1): The moving service charged a total of 3.3p dollars for the trip.

Let's set up an equation for the cost:
p+0.1p(D−5)=3.3p

Since p>30, we know p !=0, so we can divide by p:
1+0.1(D−5)=3.3
0.1(D−5)=3.3−1
0.1(D−5)=2.3
D−5= 2.3/0.1
D−5=23
D=23+5
D=28

From this statement, we find that the trip was exactly 28 miles long.
Since 28 is not greater than 30, the answer to the question "was a particular trip more than 30 miles long?" is NO.
Since we have a definitive answer, Statement (1) is sufficient.

Statement (2): The moving service charged a total of $132 for the trip.

We know the cost is $132.
So, p+0.1p(D−5)=132

From this equation, we have two unknowns (p and D). We also know p>30.
Let's test some values.

If D=30:
Cost = p+0.1p(30−5)=p+0.1p(25)=p+2.5p=3.5p.
If 3.5p=132, then p= 1320/35 ≈37.71. This value of p is greater than 30.
In this case, D=30, so the trip was not more than 30 miles.

If D=31:
Cost = p+0.1p(31−5)=p+0.1p(26)=p+2.6p=3.6p.
If 3.6p=132, then p= 132/3.6 = 330/9 =110/3 ≈36.67. This value of p is greater than 30.
In this case, D=31, so the trip was more than 30 miles.

Since we can get both a "NO" (when D=30) and a "YES" (when D=31) depending on the value of p, Statement (2) is not sufficient.

Therefore, Statement (1) alone is sufficient.
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went with A

Since p>30, we know that the total cost is

p+0.1p*m, where m is the additional number of miles after 5

Taking the 1st statement,

p+0.1p*m=3.3p

m=23, and p=40, which satisfies the condition and is valid thus

statement 2 is insufficient since we dont know the value of p and m. for different values of m, p could be greater than 30 or less than 30. Hence, insufficient.
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1)
For a 30 mile trip one will pay
P+25*.1P=P+2.5P=3.5P minimum.

So we can certainly say. NO it wasn't a 30 mile trip or longer.

Sufficient.

2)
if P is in the range of 30 to 40 then yes 132 could mean a 30 mile trip. with the minimum value being 108.000001 for a 30.10 mile trip.
If P=110 then it's a 7 mile trip.

Insufficient.
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip. =>
so 3.3p > p

so we will use. p + (miles-5) * 0.1p = 3.3p
1+ (mile-5) * 0.1 = 3.3
(miles-5) = 2.3
miles = 23 +5 => 28
So 28<30 so we get ans No This is Sufficient

(2) The moving service charged a total of $132 for the trip. =>
now if p = 132 dollars then 5 < 30 so No
but if p is 2
2 + (m-5)2 = 132
m-5 = 61
m= 66 then ans will be Yes so this is Not Sufficient

Hence ans A
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?
Let, total distance = d
Total Charge= p+0.1*p*(d-5)
Is d>30 miles?

(1) The moving service charged a total of 3.3p dollars for the trip.
3.3p=p+0.1*p*(d-5) ......Solve it and we get, d=28 miles
Sufficient

(2) The moving service charged a total of $132 for the trip.
132= p+0.1p(d-5) .....we have 2 variables here
Insufficient

A
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

we are given
p+(0.1p*(x-5) )
where x is distance in miles and p is dollar value
p>30 is x >30 ?

#1
The moving service charged a total of 3.3p dollars for the trip.
3.3p = p+(0.1p*(28-5))
x is 28 which is less than 30 miles
sufficient
#2
The moving service charged a total of $132 for the trip.
let 140/3.3 =p;40
at p = 40 & x = 28
we get
40+(0.1*40 *23 ) = 132
sufficient
OPTION D is correct
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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The first option gave us 3.3p dollars.
So for the first 5 miles its p dollar,then 2.3p dollars left.
Then for each mile its 0.1*p,so the miles taken after is 2.3p/0.1p=23.So total miles traveled is 28 miles.We can answer the question with this.

Second option gives us 132 dollars.
so p+0.1*p*x=132 (x is the miles after the first 5 miles)
p=132/1+0.x
132/1+0.x>30(given p>30)
0.1x<3.4
x<34

The total miles it might have travelled would be <34+5 which is <39,so we are not sure if it traveled more than 30 or not,because according to this inequality it could have traveled for only 20 or maybe 37.

Hence answer is A.
Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Cost Structure:

First 5 miles: p dollars

Each additional mile (or fraction): 0.1p dollars

The Question: Is d > 30? This is a "Yes/No" question.

Let's express the total cost, C, in terms of d:

If d <= 5: C = p

If d > 5: C = p + (d - 5) * 0.1p

We are given that p > 30. This is important context for the cost values.

Statement (1): The moving service charged a total of 3.3p dollars for the trip.
So, C = 3.3p.

Let's use this in our cost formula:
3.3p = p + (d - 5) * 0.1p

Since p > 30, we know p is not zero, so we can divide both sides by p:
3.3 = 1 + (d - 5) * 0.1

Now, solve for d:
2.3 = (d - 5) * 0.1
Divide by 0.1:
23 = d - 5
d = 23 + 5
d = 28

From Statement (1), we definitively find that the trip was 28 miles long.
Now we answer the question: Is d > 30?
Is 28 > 30? No.

Since we can definitively answer "No" based on Statement (1) alone, Statement (1) is sufficient.

Statement (2): The moving service charged a total of $132 for the trip.
So, C = 132.

From this statement, we know the actual dollar amount of the charge, but we don't know the value of p.
Let's consider two cases based on different values of p (keeping p > 30).

Case 1: Let p = 40 (This satisfies p > 30)
Cost for first 5 miles = 40 dollars.
Cost per additional mile = 0.1 * 40 = 4 dollars.
Total cost = 132 dollars.

Since 132 > 40, the trip must be longer than 5 miles.
132 = 40 + (d - 5) * 4
92 = (d - 5) * 4
23 = d - 5
d = 28 miles.
In this case, d = 28, which means d is NOT greater than 30. (Answer: No)

Case 2: Let p = 32 (This satisfies p > 30)
Cost for first 5 miles = 32 dollars.
Cost per additional mile = 0.1 * 32 = 3.2 dollars.
Total cost = 132 dollars.

Since 132 > 32, the trip must be longer than 5 miles.
132 = 32 + (d - 5) * 3.2
100 = (d - 5) * 3.2
100 / 3.2 = d - 5
1000 / 32 = d - 5
31.25 = d - 5
d = 31.25 + 5
d = 36.25 miles.
In this case, d = 36.25, which means d IS greater than 30. (Answer: Yes)

Since we can get both "No" (d=28) and "Yes" (d=36.25) depending on the value of p, Statement (2) alone is not sufficient.

Conclusion:
Statement (1) alone is sufficient to answer the question definitively ("No").
Statement (2) alone is not sufficient.

The final answer is A
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Let total distance be x
Total charge = p+(x-5)*0.1*p
p > 30

Was a particular trip more than 30 miles long?
Is x>30?

S1
The moving service charged a total of 3.3p dollars for the trip.
3.3p = p+(x-5)*0.1*p
3.3 = 1+0.1x-0.5
0.1x=2.8
x=28
Sufficient

S2
The moving service charged a total of $132 for the trip.
Let the total charges be np
np=132
np = p+(x-5)*0.1*p
n= 1+(x-5)*0.1
n-1=0.1x-0.5
0.1x=n-0.5
x=10n-5

p> 30
np>30n
np/3>10n
x+5<np/3
x+5<132/3
x+5<44
x<39
We don't know if x>30
Insufficient

Answer A

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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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The information provided is enough to arrive at a conclusion .ie p dollars for 5miles ,0.1*25 miles is equal to 2.5p dollars total 3.5p dollars therefore 3.3p dollars as in moving service 1 and $132 as in moving service 2.letting p=30 3.5*30=$91.5. Therefore conclusion is distance is less than 30 miles
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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Given: cost = p + 0.1*p (for additional miles to first 5)

Let x be the miles.

asked: is x>30 miles?

Statement 1: 3.3p = p + 0.1 * p(x-5)
Solving for x we get x = 27. So sufficient. Hence A,D

Statement 2: 132 = p + 0.1 * p(x-5) and p >30

Case 1: p = 31 => 132/31 = 1 + 0.1*(x-5) => 4..something = 1 + 0.1(x-5) => 30 something + 5 = x which is more than 30

Case 2: p = 64 => 132/64 = 1 + 0.1*(x-5) => 2. something = 1 + 0.1(x-5) => 20 something + 5 = x which is less than 30
Hnece not sufficient. So answer is Option A
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile.
If p > 30, was a particular trip more than 30 miles long?

Moving service charge =
$p if distance travelled <= 5 miles
$p + $.1p(m-5) ; if distance travelled m > 5 miles

(1) The moving service charged a total of 3.3p dollars for the trip.
3.3p = p + .1p(m-5)
2.3p = .1p(m-5)
m-5 = 23
m = 28 miles < 30 miles
SUFFICIENT

(2) The moving service charged a total of $132 for the trip.
132 = p + .1p(m-5)
m = (132 - p)/.1p + 5 = 1320/p - 10+ 5 = 1320/p - 5
Since p>30
m < 1320/30 - 5 = 44 - 5 = 39
m may or may not be greater than 30.
NOT SUFFICIENT

IMO A
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The moving service charges a flat rate p dollars for the first 5 miles and 0.1p dollars for each additional mile or fraction thereof. From statement (1), the total charge is 3.3p, which means the extra miles cost 2.3p. Since each extra mile costs 0.1p, the number of extra miles rounded up is 23, so the trip length is between 28 and 29 miles—less than 30 miles. Thus, statement (1) alone is sufficient to answer the question. From statement (2), the total charge is $132, but since p is unknown (only that p > 30), the trip length could vary widely depending on p. For example, if p = 33, the trip is over 30 miles, but if p = 44, the trip is under 30 miles. Therefore, statement (2) alone is not sufficient. Overall, only statement (1) alone suffices to determine whether the trip was more than 30 miles.
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for trip more than 30 mile:
0-5 mile=p
5-30=25*0.1p=2.5p
so minimum 3.5p

1. total is 3.3p (<3.5p)..NO...SUFFICIENT
2. if p=31.. 3.5p=108.5..so distance>30
but if p=55..3.5p=192.5..distance<30....NOT SUFFICIENT

Ans A
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