We are given that for the first 5 miles, the cost is $p
For any mile (whole or fraction) above 5 miles, the cost is $0.1p per mile
Let "m" be the total miles. We have 2 cases:
Case 1: m<=5
In this case, the total cost is $p
Case 2: m>5
In this case we have total cost = (cost for frist 5 miles)+(cost for the "m-5" miles)
Total cost = p + (m-5)*(0.1p)
Simplifying, we get total cost = 0.5p + 0.1pm
We are to find if m>30, given that p>30
Statement 1:
(1) The moving service charged a total of 3.3p dollars for the trip.
We can say that, 0.5p + 0.1pm = 3.3p
Solving, we get, m=28
Since this is m<30, this is sufficient.
Statement 2:
(2) The moving service charged a total of $132 for the trip.
We use the same equation,
0.5p + 0.1pm = 132
Taking "p" common, we get,
p*(0.5+0.1m) = 132
Now, we know that p>30
If p=30.1 -----> we get m=38.8 (so, in this case m>30)
If p=100 ------> we get m=8.2 (so, in this case m<30)
Since we get 2 different answers, this is insufficient.
Answer is A.