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Let distance travelled be D

Given: Total cost = p+0.1*p*(D-5)
Question: Is D>30?

Statement 1: The moving service charged a total of 3.3p dollars for the trip.
p+0.1*p*(D-5) = 3.3p
So only D is variable and we have 1 equation. Hence sufficient to answer

D =28

Statement 2:
The moving service charged a total of $132 for the trip.
p+0.1*p*(D-5) = 132
We have 2 variables and one equation.
Hence insufficient to answer

So A is correct
Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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We are given that for the first 5 miles, the cost is $p
For any mile (whole or fraction) above 5 miles, the cost is $0.1p per mile

Let "m" be the total miles. We have 2 cases:

Case 1: m<=5

In this case, the total cost is $p

Case 2: m>5

In this case we have total cost = (cost for frist 5 miles)+(cost for the "m-5" miles)
Total cost = p + (m-5)*(0.1p)
Simplifying, we get total cost = 0.5p + 0.1pm

We are to find if m>30, given that p>30

Statement 1:
(1) The moving service charged a total of 3.3p dollars for the trip.

We can say that, 0.5p + 0.1pm = 3.3p
Solving, we get, m=28

Since this is m<30, this is sufficient.

Statement 2:
(2) The moving service charged a total of $132 for the trip.

We use the same equation,

0.5p + 0.1pm = 132
Taking "p" common, we get,

p*(0.5+0.1m) = 132

Now, we know that p>30

If p=30.1 -----> we get m=38.8 (so, in this case m>30)
If p=100 ------> we get m=8.2 (so, in this case m<30)

Since we get 2 different answers, this is insufficient.

Answer is A.
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?
Assume n as the number miles above 5 miles. We are asked if n >25
Total charge = p + 0.1p x n = p ( 1+ 0.1n)

(1) only: The moving service charged a total of 3.3p dollars for the trip.
3.3p = p (1 +0.1n)
n = 23 <25

Answer: NO

(2) only: The moving service charged a total of $132 for the trip.
132 = p (1+ 0.1n)
As p>30, 1 + 0.1n < 132/30 = 4.4
n < 34
Answer: we don't know if n >25

Final answer: A
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Answer is A

(1) The moving service charged a total of 3.3p dollars for the trip.
We can write this as 2.3p + p
Given that 0.1p is charged for any additional mile above 5miles
Thus, total distance was 23 +5 = 28
This alone is sufficient

(2) The moving service charged a total of $132 for the trip.
Let's say total additional distance above 5mile was n
Total charge algebraically = p + 0.1p*n = p(1 + 0.1*n) = 132
p = 132/(p(1+0.1*n))
We are given p > 30

132/(1+0.1*n) > 30
4.3/(1+0.1n) > 1
After solving, we get n < 33
Total distance = n + 5 < 38
This can be greater or lesser than 30, hence, this alone is not sufficient

Hence, answer is A
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Let total number of miles be 'x'. Given that
Total trip cost = p+(x-5)*0.1p

Target question ---> If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
Implies, 3.3p=p+(x-5)0.1p, solving for x , we get x=28. Sufficient

(2) The moving service charged a total of $132 for the trip.
Implies, 132=p+(x-5)0.1p, solving for x in terms to p we get,
x= (1320/p) - 5
provided that p>30, value of x<39. Hence Insufficient


Correct answer would be A.
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Let distance be D
total cost= p + 0.1*(x-5)*p
given p>30
A. Total cost=3.3p
=> 3.3p=p+0.1*p*(x-5)
=>x=28
So ,D<30 Sufficient

B. Total cost=132$
132=p(1+0.1(x-5)
Since we have two unknowns this is not enough

IMO:A
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
Total = p + 0.1p (x -5)
3.3p = 1p + 0.1p(x-5)
2.3p = 0.1p(x-5)
23p = p(x-5)
23 = x-5
28 = x

Is it sufficient? Yes, it is. Eliminate answer choices B, C, and E.


(2) The moving service charged a total of $132 for the trip.

132 = p + 0.1p(x-5)

If p = 31:
101 = 0.1*31*(x-5)
1010/31 = x - 5
32,58 = x greater than 30 miles

If p = 66:
132 = 66 + 0.1*66(x-5)
66 = 0.1*66(x-5)
1 = 0.1(x-5)
10 = x - 5
15 = x smaller than 30

Is it sufficient? No, it’s not. Eliminate choice D.


Answer = A
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Given p dollars charged for first 5 miles and 0.1 dollars for each mile further.
And p>30. Is trip >30kms

I) moving service charged 3.3 p for trip. It means for p dollars 5 miles travelled. Remaining 2.3 p => 22+ - 23 kms => total kms <30
Sufficient
II)total amount is 132. If p=132 trip<=5 kms. If p = 1 trip>30 kms
Insufficient

Option A
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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Let m = total miles in the trip
Total charge = p + 0.1*p* [m-5]
Statement (1): The moving service charged a total of 3.3p3.3p3.3p dollars for the trip.
=> p + 0.1*p*[m-5] = 3.3*p => [m-5] = 23 => m ∈ (27;28] => m < 30
=> Sufficient

Statement (2): The moving service charged a total of $132 for the trip
=> p + 0.1*p*[m-5] = 132 > 30 + 0.1*30*[m-5] => [m-5] < 34 => m < 39
=> Insufficient
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Given information:-

Cost for first 5 miles = $p
Cost for x additional miles = $0.1px

Equation for total cost = p + 0.1px

p>30

(1) The moving service charged a total of 3.3p dollars for the trip.

3.3p=p+0.1px
2.3=0.1x
x=23

Total distance travelled is 23 + 5= 28. Sufficinet



(2)132=p+0.1px

assume p=31

132= 31(1+0.1x)
4.2-1=0.1x
x=32.5

assume p=40

132= 40(1+0.1x)
x=23

Therefore, not sufficient

Correct answer is (A)

Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Given is,
\(p>30\) and the Service charge \(C= p + 0.1*p*(x-5)\)

(1) The moving service charged a total of 3.3p dollars for the trip. i.e C = 3.3p
Therefore,
\(3.3p= p + 0.1*p*(x-5)\)
\(3.3= 1 + 0.1*(x-5)\)
\(x = 28\).
So no. Hence Sufficient.

(2) The moving service charged a total of $132 for the trip.
\(132= p + 0.1*p*(x-5)\)
Substitute p = 33,
\(132= 33 + 0.1*33*(x-5)\)
\(4 = 1 + 0.1*(x-5)\)
\( x = 35\)

substitute p = 120,
\(132= 120 + 0.1*131*(x-5)\)
\(12= 0.1*120*(x-5)\)
\(x=6\)

So we can't say with 2, Hence insufficient.

SO answer is Option A.
Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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Let the moving service charge for the first 5 mile = p dollars.

The moving service charge for the remaining (m-5) mile = 0.1*p dollars per mile or per fraction of mile.

If P > 30, was a particular trip m > 30 miles ??

Statement 1:

(1) The moving service charged a total of 3.3p dollars for the trip.

P + (m-5)*0.1*p = 3.3 p

(m-5)*0.1*p = 2.3 p

m = 28

Hence, Sufficient.

Statement 2:

(2) The moving service charged a total of $132 for the trip.

p + (m-5)*0.1*p = 132

if P = 31, we get m = 37.58 we can say m>30? Yes

if P = 50, we get m = 21.4 we can say m>30? No

if P = 37.71 , we get m = 30, is m >30? No

Hence, Sufficient

Option D
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Statement 1 , 3.3p= p+0.1p(x), x is additional miles
0.1xp = 2.3p
x = 2.3/(0.1) = 23, then the total distance is 5+23 = 28, which is less than 30, so we have our answer
Sufficient

Statement 2, 132 = p+0.1p(x)
p = 132/(1+0.1x)
given p>30, if x = 24, then p = 132/(3.4) = 38>30, yes and total distance = 29 < 30
if x = 26, then p = 132/(3.6) = 36>30, yes and total distance = 31 > 30

Not sufficient
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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


This question was provided by Experts' Global
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(1) The moving service charged a total of 3.3p dollars for the trip.

Assume that the number of miles travelled= m

Total charges =

p + 0.1p(m-5)

p + 0.1pm - 0.5p

0.5p + 0.1pm

We know that this charge = 3.3p

0.5p + 0.1pm = 3.3p

As p > 30, we can cancel p

0.1m = 2.8

m = 28

m < 30

Hence this statement alone is sufficient

(2) The moving service charged a total of $132 for the trip.

The statement alone is not sufficient as we are only given the minimum value of p.

Depending on the value of p we can have the number of miles travelled greater or under 30 miles.

Option A
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Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


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It seems to me you can solve with just the question and without the additional information. lets just set distance = 30 and p=30 well p for the first 5 and .1 for the next 25 which is 2.5 so 3.5P=30 miles. Which means that we already know if p>30 than the distance is greater than 30 miles. So D both are sufficient.
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A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.

push the question:

Assume the trip was exactly 30 miles.

first 5 miles = p
remaining 25 miles= 0.1p*25

Total cost for 30 miles= p+0.1*p*25 --> 3.5p

(1) 3.3p<3.5p the trip must have been less than 30 miles --> SUFFICENT

(2) to test the limit i assumed p=31
3.5*3.1=108.5 $

So for p=31 the total is less than $132.
But obviously, for a bigger value of p, the total would be more than $132, so this is not a definitive answer --> NOT SUFFICENT


ANSWER A
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We assign D for the distance and C for the total charge. We can calculate the charge as follows:

  1. \( C=p \) if \( D<5 \)
  2. \( C=p+\frac{ P}{10 }(D-5) \) if \( D>5 \)


Statement 1: If \( C=3.3p \), we know that D must have been more than 5, so we use the second equation for C:

\( C=p+\frac{ P}{10 }(D-5)=3.3p \)
\( \frac{ P}{10 }(D-5)=2.3p \)
\(D-5=23\), then \(D=28\)
So statement 1 is sufficient.

Statement 2: We know that C=132 and \(p>30\), but we don't have more information.

p could be 132, and D could be 5 miles or less.
p could be 33, then D would be 35. (from the second equation for C)
So, statement 2 is not sufficient.

The answer is A.


Bunuel
A moving service charges p dollars for the first 5 miles of any trip plus 0.1*p dollars for each additional mile or fraction of a mile. If p > 30, was a particular trip more than 30 miles long?

(1) The moving service charged a total of 3.3p dollars for the trip.
(2) The moving service charged a total of $132 for the trip.


 


This question was provided by Experts' Global
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