Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
04 Jul 2025, 14:41
Kudos
Bookmarks
Correct answer should be D.
Statement I:
3.3p can also be written as p + 2p +0.1p + 0.1p + 0.1p
p is charged for first 5 miles
2p can be charged for maximum of 20 miles
0.1p can be charged for a maximum of 1 mile
Maximum miles for a particular trip can be = 5 + 20 + 1 + 1 + 1 = 28. Sufficient.
Statement II:
Let total distance be x miles
132 = p + [x-5] * 0.1p, [x-5] is the nearest integer greater than or equal to x-5.
[x-5] = (132 - p) / 0.1p
Let's test values of p > 30
If p = 40
[x-5] = 23
which implies,
22 < x-5 <= 23
27 < x <= 28
If p = 60
[x-5] = 12
16 < x <=17
Similarly, other values of p greater than 30 can also be checked. Therefore sufficient.
Statement I:
3.3p can also be written as p + 2p +0.1p + 0.1p + 0.1p
p is charged for first 5 miles
2p can be charged for maximum of 20 miles
0.1p can be charged for a maximum of 1 mile
Maximum miles for a particular trip can be = 5 + 20 + 1 + 1 + 1 = 28. Sufficient.
Statement II:
Let total distance be x miles
132 = p + [x-5] * 0.1p, [x-5] is the nearest integer greater than or equal to x-5.
[x-5] = (132 - p) / 0.1p
Let's test values of p > 30
If p = 40
[x-5] = 23
which implies,
22 < x-5 <= 23
27 < x <= 28
If p = 60
[x-5] = 12
16 < x <=17
Similarly, other values of p greater than 30 can also be checked. Therefore sufficient.
Bunuel
04 Jul 2025, 17:23
Kudos
Bookmarks
Topic(s)- Revenue, Max/Min
Strategy: Algebra, Max/Min Testing
Variable(s)- Miles = "x"; Revenue = "R(x)"
0. Pre-Work
R(x) = (p) + (p/10)*(x - 5)
Rephrase the Question: Is x > 30 miles?
(1) R(x) = 3.3p
i. Is x affected by the value of p?
3.3p = p + (p/10)*(x-5) -> Who cares what p is??
Multiply both sides by (10/p)
[3.3*(p) = (p) + (p/10)*(x-5)] * (10/p)
33 = 10 + (x - 5)
x = 28, regardless of p [Eliminate B,C,E]
(2) R(x) = $132
i. 132 = p + (p/10)*(x-5)
ii. Isolate x
1320 = 10p + (px) - 5p
1320 - 5p = px
x = (1320 - 5p)/p
iii. Max/Min Testing
for p(min) = 30.00000001 = 30
x = (1320 - 5*(30)) / (30) > 30 miles [Question is a YES]
for p("max") = 300
x = (1320 - 5*(300) / (300) < 30 miles [Question is a NO]
-> Conflicting Results [Eliminate B, D]
Answer: A
Strategy: Algebra, Max/Min Testing
Variable(s)- Miles = "x"; Revenue = "R(x)"
0. Pre-Work
R(x) = (p) + (p/10)*(x - 5)
Rephrase the Question: Is x > 30 miles?
(1) R(x) = 3.3p
i. Is x affected by the value of p?
3.3p = p + (p/10)*(x-5) -> Who cares what p is??
Multiply both sides by (10/p)
[3.3*(p) = (p) + (p/10)*(x-5)] * (10/p)
33 = 10 + (x - 5)
x = 28, regardless of p [Eliminate B,C,E]
(2) R(x) = $132
i. 132 = p + (p/10)*(x-5)
ii. Isolate x
1320 = 10p + (px) - 5p
1320 - 5p = px
x = (1320 - 5p)/p
iii. Max/Min Testing
for p(min) = 30.00000001 = 30
x = (1320 - 5*(30)) / (30) > 30 miles [Question is a YES]
for p("max") = 300
x = (1320 - 5*(300) / (300) < 30 miles [Question is a NO]
-> Conflicting Results [Eliminate B, D]
Answer: A
04 Jul 2025, 17:53
Kudos
Bookmarks
A moving service charges p dollars for the first 5 miles of any trip, plus 0.1*p dollars for each additional mile or fraction of a mile.
If p > 30, was a particular trip more than 30 miles long?
Consider boundary condition P = 30; Then total cost would be P + 0.1P * 25 = 3.5 P;
(1) The moving service charged a total of 3.3p dollars for the trip.
From this, we can say that the total charges were less than 3.5 p, hence the trip length was less than 30 miles.
(2) The moving service charged a total of $132 for the trip.
We don't know the exact distance, hence we can't say what was total cost is in terms of p, and hence can't calculate the distance. Not Sufficient.
If p > 30, was a particular trip more than 30 miles long?
Consider boundary condition P = 30; Then total cost would be P + 0.1P * 25 = 3.5 P;
(1) The moving service charged a total of 3.3p dollars for the trip.
From this, we can say that the total charges were less than 3.5 p, hence the trip length was less than 30 miles.
(2) The moving service charged a total of $132 for the trip.
We don't know the exact distance, hence we can't say what was total cost is in terms of p, and hence can't calculate the distance. Not Sufficient.
