During a science experiment, each measurement result was affected by the same calibration error and had to be adjusted.
· The corrected result m for each result was calculated as m = -0.5n + 10,
where n was the original recorded value.
· Average (arithmetic mean) of the original measurements, Am = 7.3
· Standard deviation of the original measurements, Sd = 2.9.
To find· Corrected Mean
· Corrected Standard Deviation
Solution:If m = a*n + b
Then, Average corrected mean, Acm = a * Am +b
Acm = -0.5* 7.3 + 10
Acm = 6.35For standard deviation, only multiplication factor, a will affect, not the conatant part, b:
Corrected standard deviation, CSd = |a| *Sd
CSd = |-0.5| * 2.9
Csd = 1.45Answer:· Corrected Mean =
6.35· Corrected Standard Deviation =
1.45 Bunuel
During a science experiment, each measurement result was affected by the same calibration error and had to be adjusted. The corrected result m for each result was calculated as m = -0.5n + 10, where n was the original recorded value. The average (arithmetic mean) of the original measurements was 7.3 and the standard deviation of the original measurements was 2.9.
Select for
Corrected Mean the average (arithmetic mean) of the corrected results, and select for
Corrected Standard Deviation the standard deviation of the corrected results. Make only two selections, one in each column.