Let n be the original recorded value. The corrected result m is given by the equation: m = -0.5n + 10
We are given:
1)Average (arithmetic mean) of the original measurements,\(\mu_n\) = 7.3
2)Standard deviation of the original measurements,\(\sigma_n\) = 2.9
We need to find the Corrected Mean (\(\mu_m\)) and the Corrected Standard Deviation (\(\sigma_m\)).
1. Corrected Mean (\(\mu_m\))
For a linear transformation m = an + b, the new mean is given by \(\mu_m\) = a\(\mu_n\) + b. In this case, a = -0.5 and b = 10.
On substituting the values:
\(\mu_m\) =
6.352. Corrected Standard Deviation (\(\sigma_m\))
For a linear transformation m = an + b, the new standard deviation is given by \(\sigma_m\) = |a|\(\sigma_n\).
The constant 'b' (the shift) does not affect the spread (standard deviation) of the data.
\(\sigma_m\) = |-0.5|(2.9)
\(\sigma_m\) = (0.5)(2.9)
\(\sigma_m\) = 1.45
Therefore, the Corrected Mean is
6.35 and the Corrected Standard Deviation is
1.45.