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There are 6 pets & 6 treats (2 identical apples, 4 distinct fruits)
-> 2 pets for the apples = 6C2 = 15 ways
-> assign the other 4 fruits in 4! = 24 ways
-> Total ways = 15*24 = 360

Now, let's adjust for restriction cases.
-> Rabbit gets mango : 5C2 (apples) * 3! (other fruits) = 10 * 6 = 60
-> Parrot gets banana : same logic = 60
-> Both happen : 4C2 * 2! = 6 * 2 = 12

Final number of ways = 360 - 60 - 60 +12 = 252

Answer : C
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2x apple slices
1x banana
1x carrot
1x mango
1x pear

total permutations = 6!/2! = 360

rabbit refuses to eat the mango, then we have to subtract 1/6 of 360 = 60
parrot refuses to eat the banana, then we have to subtract 1/6 of 360 = 60
but we have subtracted twice when mango and banana are fixed, then we have to add 4!/2! = 12

360-60-60+12=252

IMO C
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6 Pets, 6 treats (2 identical)
Condition: Rabbit - No mango (A), Parrot - No banana (B)

We will calculate no of ways (without condition) - Condition (A) - Condition (B) + Condition (A+B) since it will be counted twice once in condition A and once in Condition B

Step 1:
No of ways to distribute 6 treat among 6 pets = 6!/ 2! (2! for identical treats)

Step 2: No of ways to distribute 5 treat among 5 pets (as rabbit got mango) = 5!/ 2!

Step 3: No of ways to distribute 5 treat among 5 pets (as parrot got banana) = 5!/ 2!

Step 4: No of ways to distribute 4 treat among 4 pets (as parrot got banana and rabbit got mango)= 5!/ 2!

Answer => 6!/2! - 5!/ 2! - 5!/ 2! + 4!/ 2! = 252 (C)
Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


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Option C is the correct answer.

Lets try to understand the question before we trying solving it out.

So the question starts by telling us that Anna has six pets and plants to give each a single treat. Then it further tells us what she has in treats: two identical apple slices, along with one banana, one carrot, one mango, and one pear. The question then tells us that Anna's rabbit refuses to eat mango and parrot refuses to eat banana. Now the question asks us "In how many distinct ways can she distribute the treats among the pets".

Now we have two ways of solving this type question: First is to subtract the Total number of Unfavorable Outcomes from Total Outcomes, Second by adding all the possible cases of Favorable Outcomes.

We will be using the first approach for this question because it is more convenient and in this approach the chances of calculation mistake is very low.

So, as discussed earlier in this approach we will be subtracting the total number of Unfavorable Cases from the Total number of Cases.

Total number of combination = 6!/2! = 360 Cases

So the for the Total number of Unfavorable cases we have calculate the cases in which either Rabbit eats the mango, Parrot eats banana or both.

The number of cases in which Rabbit gets mango = 4*4!/2! = 48 Cases, Lets understand why we did this so as we were finding the cases in which Rabbit gets mango so Rabbit is fixed with mango, which leaves Parrot with 4 choices i.e. two apples, one pear or one carrot post which the rest of the pets and plants can have any of the leftover treats in 4! ways.

The number of cases in which Parrot gets banana = 4*4!/2! = 48 Cases, the reasoning for this scenario is the same as for the scenario above.

The number of cases in which Parrot gets banana and Rabbit gets mango = 4!/2! = 12 Cases, in this we fixed Rabbit with mango and Parrot with banana which leaves 4 treats for the rest.

Now to the main answer, Total number of Favorable Cases = Total number of cases - Total number of Unfavorable cases
Total number of Favorable Cases = 360 - (48+48+12)
Total number of Favorable Cases = 360 - 108
Total number of Favorable Cases = 252 (Option C)

From here we can say that 252 (Option C) are the total number of distinct ways in which Anna can distribute the treat among her pets.
Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


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B.
2 A, 1 B, 1c, 1 M, 1 P.
P can be filled in 5 ways, R-4, The rest in 4!. =480. Now we have 2 identical apples, divide by 2!. = 240
Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


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for the GMAT Club Olympics Competition

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To answer this, let’s try the complement method

No. of distinct ways Anna can distribute the treats among the pets = No. of ways to assign 6 distinct treats (without restrictions) – [No. of ways in which Rabbit gets mango + No. of ways in which Parrot gets banana – Both]
No. of ways to assign 6 distinct treats 6!/2! (dividing by 2! since we have identical apples) = 720/2 = 360
To get the no. of ways in which Rabbit gets mango, provide mango to rabbit and the other 5 can be distributed in 5!/2! = 60
Similarly, to get the no. of ways in which Parrot gets banana, provide banana to parrot and the other 5 can be distributed in 5!/2! = 60
Don’t forget to calculate the no. of ways in which both Parrot gets banana and Rabbit gets mango; the other 4 fruits can be distributed in 4!/2! = 12 ways
Therefore, No. of distinct ways Anna can distribute the treats among the pets = 360 – (60+60-12)
= 360 – 108 = 252

Option C

Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


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for the GMAT Club Olympics Competition

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Treats: 2A, 1B, 1C, 1M and 1P
Rabbit wont have M
Parrot wont have B
The 2 apples are identical.

p1 (rabbit): 5 options
p2 (parrot): 4 options
p3: 4 options
p4: 3 options
p5: 2 options
p6: 1 options

Total ways: 5*4*4*3*2*1. However, this includes arrangements of the 2 identical apples which would essentially be duplicates.
Distinct ways: 5*4*4*3*2*1/2 = 240.

Answer is B.
Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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Anna has six pets and plans to give each one a treat
Treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear
Rabbit refuses to eat the mango
Parrot refuses to eat the banana

Total number of possible ways without any restrictions = 6! = 720 (6 treats)
Total number of possible ways with 2 identical apple slices = 6!/2! = 360

Lets consider the invalid cases,

Total number of possible ways with 2 identical apple slices with rabbit getting mango I1 = 5!/2! = 60
Total number of possible ways with 2 identical apple slices with parrot getting banana I2 = 5!/2! = 60
Total number of possible ways with 2 identical apple slices with parrot getting banana and rabbit getting mango I3 = 4!/2! = 12
So, to eliminate double counting and get the total invalid cases = I1 + I2 - I3 = 60 + 60 - 12 = 108

Total number of ways possible for the requirement = Total number of possible ways with 2 identical apple slices - Total invalid cases = 360 - 108 = 252

C. 252
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First find the total possible outcomes of treats (apple, apple, banana, carrot, mango, pear)
Treat= 6 options with two similar options hence 6!/2= 360
Restrictions 1. Rabbit refuses mango so 5!/2= 60
Restriction 2: Parrot refuses banana so 5!/2= 60
Both rabbit and parrot get mango and banana 4!/2= 12
Ans 300-(60+60-12) =252
Bunuel
Anna has six pets and plans to give each one a treat. The treats consist of two identical apple slices, along with one banana, one carrot, one mango, and one pear. Her rabbit refuses to eat the mango, and her parrot refuses to eat the banana. In how many distinct ways can she distribute the treats among the pets?

(A) 96
(B) 240
(C) 252
(D) 288
(E) 300


 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 

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Ways to 6 fruits with identical apple slice to 6 pets is 6!/2! = 360.

Now lets subtract the case were parrot gets the banana:

First give banana to parrot now we can give remaining 5 fruits with identical apple slice to 5 pets in

5!/2! = 60 ways and same when rabbit gets the mango, So we have total 60 + 60 = 120 invalid ways.

But we also have to add double counted ways were rabbit gets mango and parrot gets banana

which is remaining 4 pets getting 4 fruits with identical apple slice in 4!/2! ways = 12

Hence final answer is 360 - 120 + 12 = 252; Hence option C
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Given:
Total treats: 6 (2 identical apple slices, 1 banana, 1 carrot, and 1 pear) & Total pets: 6

Total ways without restriction:
6! / 2!=360

Invalid cases = (Rabbit gets mango) + (Parrot gets banana) − (Both)
  • Rabbit gets mango → 5!/2!=60
  • Parrot gets banana → 5!/2!=60
  • Both → 4!/2!=12
Valid ways:
360−(60+60−12)=360−108=252

So, the correct answer option choice is C..
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