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09 Jul 2025, 04:32
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Ordered pets (rabbit, parrot, pet3, pet4, pet5, pet6)
Apple slices are identical: 6!/2!=360 permutations
These permutations include when mango is assigned to rabbit and banana is assigned to parrot.
As all is simetrical, there will be 360/6=60 permutations where mango is assigned to rabbit and 360/6=60 permutations where banana is assigned to parrot.
360-120 = 240
It is required to add when mango is assigned to rabbit and banana is assigned to parrot because it has been removed two times (4!/2!=12)
240+12=252
Correct answer is C
Apple slices are identical: 6!/2!=360 permutations
These permutations include when mango is assigned to rabbit and banana is assigned to parrot.
As all is simetrical, there will be 360/6=60 permutations where mango is assigned to rabbit and 360/6=60 permutations where banana is assigned to parrot.
360-120 = 240
It is required to add when mango is assigned to rabbit and banana is assigned to parrot because it has been removed two times (4!/2!=12)
240+12=252
Correct answer is C
09 Jul 2025, 04:40
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We have 6 distinct pets, and we need to distribute 6 treats:
2 identical apples,
1 banana,
1 carrot,
1 mango,
1 pear.
Constraints:
Rabbit cannot get mango.
Parrot cannot get banana.
Step 1: Total number of ways without restriction
Total permutations of 6 treats with 2 identical apples:(6!/2!)= 360
Now, Subtract invalid cases
Case 1: Rabbit gets mango
Choose 1 pet for mango = 1 (fixed to rabbit)
Remaining 5 treats to 5 pets:(5!/2!)= 60
Case 2: Parrot gets banana
Same:(5!/2!)= 60
Case 3: Both rabbit gets mango AND parrot gets banana
Remaining 4 treats to 4 pets:(4!/2!)= 12
Final= 360-60-60+12= 252
Correct answer Option(C)
2 identical apples,
1 banana,
1 carrot,
1 mango,
1 pear.
Constraints:
Rabbit cannot get mango.
Parrot cannot get banana.
Step 1: Total number of ways without restriction
Total permutations of 6 treats with 2 identical apples:(6!/2!)= 360
Now, Subtract invalid cases
Case 1: Rabbit gets mango
Choose 1 pet for mango = 1 (fixed to rabbit)
Remaining 5 treats to 5 pets:(5!/2!)= 60
Case 2: Parrot gets banana
Same:(5!/2!)= 60
Case 3: Both rabbit gets mango AND parrot gets banana
Remaining 4 treats to 4 pets:(4!/2!)= 12
Final= 360-60-60+12= 252
Correct answer Option(C)
09 Jul 2025, 04:40
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Bookmarks
Treats must be ordered (each one is assigned to one pet)
As apple is repeated, 6!/2!=360 is the total of permutations without additional conditions.
But we have to eliminate rabbit-mango (5!/2!=60) or parrot-banana (5!/2!=60).
As we have eliminated twice rabbit-mango and parrot-banana, it's necessary to add 4!/2!=12.
Total=360-120+12=252
The right answer is C
As apple is repeated, 6!/2!=360 is the total of permutations without additional conditions.
But we have to eliminate rabbit-mango (5!/2!=60) or parrot-banana (5!/2!=60).
As we have eliminated twice rabbit-mango and parrot-banana, it's necessary to add 4!/2!=12.
Total=360-120+12=252
The right answer is C
