If x and y are the positive integers, Is xy?

Question

GMATBusters’ Quant Quiz Question -3  
If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
2) y is a multiple of 9

chetan2u · Accepted Answer

All have answered C or E and that shows we miss out on finer details at some time..

If x and y are the positive integers, Is x>y?
1)  x^2 +12 = 13......x^2=1....x=1.. or.. x=-1 
x is positive, so x=1...
 Nothing about y -- of course there is something and that is ' y is a positive integer', so  y\geq{1} .
Also as x is 1, the lowest possible positive integer, it will never be GREATER than any other number..
Is x>y?......NO for sure
Suff

2) y is a multiple of 9
So y=9a...But nothing about x.
Say x=4....NO
But if x=20, then yes
Insuff

A

GMATBusters · Answer

Official solution

If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
x^2 = 1
x = +/-1 but as per the question, x and y are positive integers, hence x = 1
 1 is the smallest positive integer, hence 1 can never be greater than any other positive integer 
Hence, we can say than x is NOT greater than y.
 
SUFFICIENT

2) y is a multiple of 9
y can be 9, 18, 27...
x is NOT known. 
 NOT SUFFICIENT. 
 
Answer A

Kinshook · Answer

Asked: If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
x^2 = 1
x = 1 or x = -1
Since x is a positive integer x = -1 is not possible
x = 1
Since y is unknown
NOT SUFFICIENT

2) y is a multiple of 9
y = 9k; where k is a positive integer
Since x is unknown
NOT SUFFICIENT

(1) + (2)
1) x^2 +12 = 13
x^2 = 1
x = 1 or x = -1
Since x is a positive integer x = -1 is not possible
x = 1
2) y is a multiple of 9
y = 9k; where k is a positive integer
Smallest value of y = 9
x=1<9<=y
x is NOT > y
SUFFICIENT

IMO C

ashwini2k6jha · Answer

is x>y?
St-1 , Not suff
x2+12=13 only value of x=1 satisfy
nothing given about y
St-2. Not suff.
y=9,18,27 etc
Nothing given about x
1+2:sufficient Answer C
all value of x(=1 )< y ie x<y

Raxit85 · Answer

x>y?
1) x^2 +12 = 13
x^2 = 1
x = 1 or -1 (-1 not possible as its positive integer). So,x=1.
We don't know about y. So insufficient.

2) y is a multiple of 9.

y= 9/18/27....
We don't know about x. So insufficient.

1) +2) x=1 and y=9/18/27 etc.
So, x>y. Sufficient

Ans. C

techwave · Answer

If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
2) y is a multiple of 9

Ans: C both combined are sufficient

1) Solving one gives X = +-1

As the prompt says X is a pisitve integer 
X=1 however there is no information on Y hence not sufficient

2)
Y is a multiple of 9. Meaning

9*1=9
9*2=18
9*3=27.. etc

But no information on X so not sufficient

Combine one and two together. No X is not greater than Y.

adonouis · Answer

The correct answer is C.

1. Statement 1: We have, x^2 +12 = 13
 by solving this we get, x^2 = 13 - 12
 x^2 = 1
thus, x = 1.
but it does not tell anything about y.

2. Statement 2: y is a multiple of 9
thus y can be: 9; 18; 27; so on.

so we can infer from this, y>9
but this statement does not tell anything about x.

3. Considering both statement 1 and statement 2.
we get that, from statement 1; x = 1
 from statement 2; y > 9

we can conclude, y > 9 > x = 1.
thus, y > x, making the initial statement false i.e. is x>y.

both the statements together are sufficient.

gurmukh · Answer

From first statement 
X=1
Nothing about y so insufficient
From second statement
Y=9,18...
Nothing about x so insufficient
Combining they are sufficient
Hence answer is option C

Posted from my mobile device

Archit3110 · Answer

If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
2) y is a multiple of 9

#1
x^2= 1 ; x = +1
so x>y is NO always ; sufficient
#2
y is a multiple of 9 
y=1,9,18...
insufficient as x not know
OPTION A

gmatway · Answer

If x and y are the positive integers, Is x>y?
1) x^2 +12 = 13
2) y is a multiple of 9

1)from 1st we get value of X = 1 (given x,y are positive integers) . so now Y could either be EQUAL TO 1 or greater than 1 .But in both cases ans is definite NO . X isn't greater than Y . hence SUFF .
2)We have Y but we don't know value of X . if x is 3 then ans is yes . if x is 10 ans is no . insuff

IMO only A

AnirudhaS · Answer

If x and y are the positive integers

1) x^2 +12 = 13, x= 1, since x is positive integer
y can be 1 (NO), y can be 2 (YES)
Insufficient
2) y is a multiple of 9, y =9, 18, 27, 
x can be 1 (YES), and x can be 10 (NO) if y is 9

(1) + (2) x=1, y is always greater than x. 
Answer: C

Mo2men · Answer

If x and y are positive integers, Is x>y?

1) x^2 +12 = 13

x^2 +12 = 13

x^2 =1.......x is positive then only one answer that x =1

the least positive integer of y =1 .............Answer is No

if y =2.............Answer is No......ans so on

Always answer is No

Sufficient

2) y is a multiple of 9

Y =9 & x =10.............Answer is Yes

Y =9 & x =1.............Answer is No

Insufficient

Answer: A

shameekv1989 · Answer

i) x = 1; y is a positive integer so it can be 1 or greater than 1. - Insufficient