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If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

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If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 14 Oct 2015, 21:34
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x=3, y=1, so x+y/3=4/3

Ans:B
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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Bunuel wrote:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

(A) 1
(B) 4/3
(C) 17/5
(D) 18/5
(E) 4


Kudos for a correct solution.


We have two equations:
2x + y = 7
x + 2y = 5

Notice that something nice happens when we ADD them. We get:
3x + 3y = 12
Divide both sides by 3 to get: x + y = 4

So, (x + y)/3 = 4/3

Answer: B

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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 14 Oct 2015, 22:09
2x+y = 7 --1
x +2y= 5 --2
Adding equations 1 and 2 , we get
3x+3y=12
=>x+y=4

(x+y)/3 = 4/3
Answer B
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 15 Oct 2015, 11:11
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3x + 3y = 12
Divide both sides by 9 to get: 4/3

Ans B
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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2*(x+2y = 5) equals 2x+4y=10
2x+4y=10
- 2x + y= 7
= 3y=3
Therefore Y = 1

Plug and solve...

2x + 1 = 7
2x=6
x=3

(3+1)/3= 4/3
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 15 Oct 2015, 20:51
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Bunuel wrote:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

(A) 1
(B) 4/3
(C) 17/5
(D) 18/5
(E) 4


Kudos for a correct solution.

Adding the 2 equations
3x + 3y= 12
Dividing both sides by 3
X+y=12/3
Again dividing both sides by 3
(X+y)/3=4/3
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If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 16 Oct 2015, 03:07
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Bunuel wrote:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

(A) 1
(B) 4/3
(C) 17/5
(D) 18/5
(E) 4


Kudos for a correct solution.


My Solution:

2x+y=7 ----- (1) and x+2y=5 ------>(2)

Solving eqn. (1) & (2) we get x = 3 and y = 1,

Therefore, x+y/3 will be (3+1)/ 3

Answer = 4/3 Option B

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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 28 Dec 2016, 10:07
Multiply 2nd equation with 2, on solving
-3y = -3
y =1
Substitute, x = 3
\(\frac{4}{3}\)
B
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 18 Mar 2018, 07:09
Bunuel wrote:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

(A) 1
(B) 4/3
(C) 17/5
(D) 18/5
(E) 4


Kudos for a correct solution.


Add both equations:

3x + 3y = 12

3 (x + y) = 12

x + y = 4

(x + y)/3

4/3

(B)
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Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 = [#permalink]

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New post 18 Mar 2018, 08:10
Bunuel wrote:
If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =

(A) 1
(B) 4/3
(C) 17/5
(D) 18/5
(E) 4


Kudos for a correct solution.


2x + y = 7.............1

x + 2y = 5.............2
-----------------------------Sum the 2 eqautions

3x +3 y = 12 .................Divide by 3

x + y =4........................ divide by 3

(x + y)/3 =4/3

Answer: B
Re: If 2x + y = 7 and x + 2y = 5, then (x + y)/3 =   [#permalink] 18 Mar 2018, 08:10
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