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Math Expert V
Joined: 02 Sep 2009
Posts: 56302
If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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Difficulty:   15% (low)

Question Stats: 68% (00:43) correct 32% (00:50) wrong based on 48 sessions

### HideShow timer Statistics If $$L = (a - b)- c$$ and $$R = a - (b - c)$$, then $$L - R =$$

(A) 2b

(B) 2c

(C) 0

(D) -2b

(E) -2c

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Manager  S
Joined: 22 Jun 2017
Posts: 71
Location: Brazil
GMAT 1: 600 Q48 V25 GPA: 3.5
WE: Engineering (Energy and Utilities)
Re: If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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L = a - b - c
R = a - b + c
-R = -a + b - c

Hence, L - R = a - b - c - a + b - c = -2c

Option E
Intern  Joined: 07 Aug 2018
Posts: 1
Re: If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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L-R= a-b-c-a+b-c=-2c

So correct answer is option E.

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Retired Moderator D
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Concentration: Operations, Marketing
GPA: 3.5
Re: If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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L = (a - b)- c = a - b - c
R = a - (b - c) = a - b + c

L - R = a - b - c - (a - b + c) = a - b - c - a + b - c = -2c

Hence, E.
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If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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Bunuel wrote:
If $$L = (a - b)- c$$ and $$R = a - (b - c)$$, then $$L - R =$$

(A) 2b

(B) 2c

(C) 0

(D) -2b

(E) -2c

$$L = a - b - c$$

$$R = a - b + c$$

So, $$L - R = (a - b - c ) - ( a - b + c )$$

Or, $$L - R = a - b - c - a + b - c$$

Or, $$L - R = - 2c$$, Answer must be (E)
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Re: If L = (a - b) - c and R = a - (b - c), then L - R =  [#permalink]

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L=a−b−c

R=a−b+c

So,
L−R=(a−b−c)−(a−b+c)

Or,
L−R=a−b−c−a+b−c

Or,
L−R=−2c
Senior Manager  P
Status: Manager
Joined: 02 Nov 2018
Posts: 283
If L=(a-b)-c and R=a-(b-c), then L - R =  [#permalink]

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Given that,
L=(a-b)-c or a-b+c
R=a-(b-c) or a-b+c
So L-R = 0
because both value are same
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Give a kudos if u find my post helpful. kudos motivates active discussions Manager  B
Joined: 09 Mar 2018
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Location: India
Schools: CBS Deferred "24
Re: If L=(a-b)-c and R=a-(b-c), then L - R =  [#permalink]

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L=(a-b)-c
we can write this as a-b-c ( removing the bracket won't alter the sign)

R=a-(b-c)
we can write this as a-b+c

L-R= a-b-c-(a-b+c)
which equals : a-b-c-a+b-c

so we get : -2C
Intern  B
Joined: 10 Feb 2019
Posts: 1
Re: If L=(a-b)-c and R=a-(b-c), then L - R =  [#permalink]

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L-R=a-b-c-a+b-c
i.e. -2c
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2943
Re: If L=(a-b)-c and R=a-(b-c), then L - R =  [#permalink]

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Solution

Given:
• L = (a – b) – c = a – b – c
• R = a – (b – c) = a – b + c

To find:
• The value of L – R

Approach and Working:
As we already have the simplified expressions of both L and R, we can get the value of L – R as follows:
• L – R = (a – b – c) – (a – b + c) = a – b – c – a + b – c = a – a – b + b – c – c = - 2c

Hence, the correct answer is option E.

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Target Test Prep Representative D
Status: Founder & CEO
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Joined: 14 Oct 2015
Posts: 6925
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Re: If L=(a-b)-c and R=a-(b-c), then L - R =  [#permalink]

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Bunuel wrote:
If L=(a-b)-c and R=a-(b-c), then L - R =

A. 2b
B. 2c
C. 0
D. -2b
E. -2c

L - R is:

(a - b) - c - [a - (b - c)]

a - b - c - [a - b + c]

a - b - c - a + b - c = -2c

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If you find one of my posts helpful, please take a moment to click on the "Kudos" button. Re: If L=(a-b)-c and R=a-(b-c), then L - R =   [#permalink] 14 Mar 2019, 07:22
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