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If |p−6|+p=6, which of the following must be true?

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Re: If |p−6|+p=6, which of the following must be true?  [#permalink]

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New post 16 Jun 2015, 07:44
Bunuel wrote:
arshu27 wrote:
Hi Bunuel,

if we substitute p=0 then the answer must be 6. There can be no other answer right?


Not sure I understand what you mean...

p = 0, as well as any other value of p less than or equal 6 satisfies |p − 6| + p = 6.



thanks Bunuel..i have got it now... i wasn't seeing it the right way!!
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Re: If |p−6|+p=6, which of the following must be true?  [#permalink]

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New post 16 Jun 2015, 08:58
arshu27 wrote:
Hi Bunuel,

if we substitute p=0 then the answer must be 6. There can be no other answer right?



You are wrong here Ashu,

There can be infinite many answers for this equation and the answer will fall in the range 0<p<6

I hope it answers your query!
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Re: If |p−6|+p=6, which of the following must be true?  [#permalink]

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New post 16 Sep 2017, 16:28
It's simple property of Absolute Value: if \(|x| = y\), then \(y>= 0\);

Here the given equation can be rearranged as, \(|p-6| = 6-p\)
which implies, \(6-p >=0\)
or \(p<=6\). Hence E.

I hope this clarifies some doubts.
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Re: If |p−6|+p=6, which of the following must be true?  [#permalink]

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New post 24 Oct 2018, 02:15
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Re: If |p−6|+p=6, which of the following must be true?   [#permalink] 24 Oct 2018, 02:15

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