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arshu27
Joined: 25 Jan 2014
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Concentration: Technology, General Management
Schools: Anderson '17 Booth '17 Duke '17 Georgia Tech '17 Haas '17 ISB '17 Kellogg '17 Kenan-Flagler '17 LBS '17 Marshall '17 Merage '17 NUS '17 NTU '17 Ross '17 Stern '17 Oxford Urbana-Champaign '17 Schulich '17 SPJ GMBA '17 Tepper '17
16 Jun 2015, 07:44
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Bunuel
thanks Bunuel..i have got it now... i wasn't seeing it the right way!!
16 Jun 2015, 08:58
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arshu27
You are wrong here Ashu,
There can be infinite many answers for this equation and the answer will fall in the range 0<p<6
I hope it answers your query!
TheMechanic
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Schools: Anderson '16 Tepper '16 Kelley '16 Jones '16 (S) Carlson '16 ISB '18 (II) Duke '20 (S) McCombs '20 (II)
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16 Sep 2017, 16:28
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It's simple property of Absolute Value: if \(|x| = y\), then \(y>= 0\);
Here the given equation can be rearranged as, \(|p-6| = 6-p\)
which implies, \(6-p >=0\)
or \(p<=6\). Hence E.
I hope this clarifies some doubts.
Here the given equation can be rearranged as, \(|p-6| = 6-p\)
which implies, \(6-p >=0\)
or \(p<=6\). Hence E.
I hope this clarifies some doubts.
26 Apr 2022, 10:23
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|a-b| = |b-a| = the DISTANCE between b and a
b-a = the DIFFERENCE between b and a
Rule:
The distance between two values will be equal to the difference between the two values as long as the difference is NONNEGATIVE.
|p−6|+p=6
|6-p| = 6-p
In words:
The distance between 6 and p is equal to the difference between 6 and p.
Since distance = difference as long as the difference is nonnegative, we get:
6-p ≥ 0
6 ≥ p
b-a = the DIFFERENCE between b and a
Rule:
The distance between two values will be equal to the difference between the two values as long as the difference is NONNEGATIVE.
bagdbmba
|p−6|+p=6
|6-p| = 6-p
In words:
The distance between 6 and p is equal to the difference between 6 and p.
Since distance = difference as long as the difference is nonnegative, we get:
6-p ≥ 0
6 ≥ p
