Bunuel
S1: q is a digit that is the product of two other distinct digits [Insufficient]1. The key point to note here is that \(q\) is the product of two other distinct digits hence \(2 * 1 = 2\) is not a valid solution
2. Since this problem concerns with digits (0 to 9), there are only very few possibilities hence lets list them out i.e. \(6 = 2 * 3\) and \(8 = 4 * 2\)
3. In both cases \(q > 1\) and both are products of two other distinct digits
4. We can mark this statement as insufficient since we cannot get a definitive answer
S2: q has only one odd factor [Insufficient]1. Digits \(8\)
(1, 2, 4, 8), \(2\)
(1, 2) and \(4\)
(1, 2, 4) have only one odd factor \(1\)
2. We can mark this statement as insufficient since we cannot get a definitive answer
S1 + S2 [Sufficient]1. \(2\) - Passes S2 but fails the condition given in S1
2. \(4\) - Passes S2 but fails the condition given in S1
3. \(6\) - Passes S1 but fails the condition given in S2

4. \(8\) - Passes S1 and S2 conditions
Ans. C