Method 1: Profit (\(P\)) \(=\) Sales price (\(S\)) \(-\) Cost price (\(C\))

Given, Profit \((P)\) is \(20\)% of Revenue from sales (ie; sales price) \(= \frac{20}{100}*S = \frac{1}{5}S\)

Substituting value of \(P\) in Profit equation we get;

\(\frac{1}{5}S = S - C\)

\(C = S - \frac{1}{5}S = \frac{5S-1S}{5} = \frac{4}{5}S\)
Required Percentage \(= (\frac{P}{C}) * 100 = (\frac{\frac{1}{5}S}{\frac{4}{5}S}) * 100 = \frac{100}{4} = 25\)%

Method 2: Profit (\(P\)) \(=\) Sales price (\(S\)) \(-\) Cost price (\(C\))

Let \(S = 100\)

Given \(P\) is \(20\)% of \(S = \frac{20}{100} * 100 = 20\)

\(P = S - C\)

\(20 = 100 - C\)

\(C = 100 - 20 = 80\)

Required percentage \(= (\frac{P}{C}) * 100 = \frac{20}{80} * 100 = \frac{100}{4} = 25\)%

Answer (B)...

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Hi..

Be careful in such Q about the Cost, SP and on what will be the profit..
Profit =p
SP=s
Cost price=c
So s=p+c.... But p=20% of s=0.2s..
Substitute in equation
So s=0.2s+c.........c=s-0.2s=0.8s..
Profit/cost = 100*0.2s/0.8s=100/4=25%

B
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Let S-Sale, C=Cost
Profit P=\(\frac{20}{100}\)S
therefore S - C = \(\frac{20}{100}\) S
\(\frac{S}{C}= \frac{10}{8}\)
Profit % = \(\frac{(S-C)}{C}\) x 100 =(\(\frac{10}{8}\)-1) x 100= 25% (B)

=>
Let R be the revenue of the company. The profit is 0.2*R and the cost is 0.8*R.
The answer is (0.2*R) / (0.8*R) * 100 = 0.25 * 100 = 25(%).

Ans: B
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say sales price = 100
profit = 20
cost = 80

% = 20/80 x 100
25 %

hope this helps ..
cheers ..

Let Profit P, revenue R and Cost C
So as Profit= Revenue -Cost
P=R-C

Given P= 20% of R = 20/100 * R =R/5 => R=5P

Putting in above equation => P =5P-C => C=4P => P=C/4
=> P= 25/100 * C
=> P = 25% of C

Answer: B

Recall that profit = revenue - cost. Letting r = revenue and c = cost, we can create the following equation:

Profit = 0.2r

r - c = 0.2r

0.8r = c

Thus, gross profit is 0.2r/0.8r = 1/4 = 25% of cost.

Answer: B
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It helps to know
Revenue 100%
less: cost 80%
---------
Gross Profit 20%

Question what is Gross Profit as a % of cost = 20% /80% = 1/4 = 25%

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