Divisibility rule of 9 "If the sum of digits of the given number is divisible by 9 then the number itself is divisible by 9."
2*10^x+11y
Stmt 1: x = 6
Whatever the value of x (x is a positive integer) sum of digits of 2*10^x is always 2. (Eg: when 20, 200, 2000 etc)
Depending on the value of y the sum of digits may or may not leave a remainder.
(For eg : if y = 4, 2*10^x+11y = 2000044, sum of digits = 10; not divisible by 9; if y = 8, 2*10^x+11y = 2000088, sum of digits = 18; divisible by 9;
As long as we don't know the value of y we cant say if the expression will leave a remainder or not.
Not suffStmt 2: y = 8
11y = 88 and sum of digits = 16. Whatever the value of x (x is a positive integer) sum of digits of 2*10^x is always 2.
So sum of digits of 2*10^x+11y is always 18 when y =8. Remainder will be zero.
SuffAnswer :
BAmbarish
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