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705-805 Level|   Graphs|   Math Related|      
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gmatt1476
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In 2012, there were 5 internet companies selling widgets worldwide. Updated on: 09 Nov 2025, 01:31
Originally posted by gmatt1476 on 05 Mar 2020, 00:57.
Last edited by Bunuel on 09 Nov 2025, 01:31, edited 4 times in total.
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Dropdown 1: True Dropdown 2: 116
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67% (02:34) correct 33% (02:35) wrong based on 1123 sessions

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In 2012, there were 5 internet companies selling widgets worldwide. The graphic shows the monthly sales data for 2012 for two of those merchants as well as the worldwide average for widgets for those months.

Based on the given information, use the drop-down menus to most accurately complete the following statements.

WidgetMania and WidgetExpress accounted for more widgets sold than the other 3 internet companies for at least 1 month in 2012:

In August 2012, the three widget merchants not specified on the graph sold a total of exactly widgets.


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rocky620
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In 2012, there were 5 internet companies selling widgets worldwide. 19 Oct 2021, 08:48
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1) WidgetMania and WidgetExpress accounted for more widgets sold than the other 3 internet companies for at least 1 month in 2012. _____________

In the month of Feb, the worldwide average was ~30. So, all the companies put together would have sold 150 widgets. Of these 150, WM & WE sold approx 45 & 48 widgets respectively. So, the remaining three (put together) sold 57 widgets. Hence, TRUE.

A. True
B. False
C. Cannot determine

2) In August 2012, the three widget merchants not specified on the graph sold a total of exactly_______________widgets.

In Aug 2012, the worldwide average was ~50. So, all companies sold 250 widgets. Of these WM & WE sold approx 130 widgets. So, the remaining three sold ~120 widgets. Hence, Option B
A. 54
B. 116
C. 129
D. 147
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Apt0810
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In 2012, there were 5 internet companies selling widgets worldwide. 05 Mar 2020, 01:22
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1)A,Since for April & May both were higher than world average
2)since world total is 250 for August so for remaining three it would be 250-(70+59)= 121 which is close to option B,116

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In 2012, there were 5 internet companies selling widgets worldwide. 21 Jun 2024, 10:28
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Here, in part A, As the remaining put together is 57, there is a possibility that one of the 3 companies sold 50 and the other two sold 3 and 4 respectively? [I believe the answer should be 'C' Cannot Determine]
rocky620
1) WidgetMania and WidgetExpress accounted for more widgets sold than the other 3 internet companies for at least 1 month in 2012. _____________

In the month of Feb, the worldwide average was ~30. So, all the companies put together would have sold 150 widgets. Of these 150, WM & WE sold approx 45 & 48 widgets respectively. So, the remaining three (put together) sold 57 widgets. Hence, TRUE.

A. True
B. False
C. Cannot determine

2) In August 2012, the three widget merchants not specified on the graph sold a total of exactly_______________widgets.

In Aug 2012, the worldwide average was ~50. So, all companies sold 250 widgets. Of these WM & WE sold approx 130 widgets. So, the remaining three sold ~120 widgets. Hence, Option B
A. 54
B. 116
C. 129
D. 147
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­
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samarpan.g28
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In 2012, there were 5 internet companies selling widgets worldwide. 23 Jun 2024, 09:27
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nonameleftxxx
Here, in part A, As the remaining put together is 57, there is a possibility that one of the 3 companies sold 50 and the other two sold 3 and 4 respectively? [I believe the answer should be 'C' Cannot Determine]
rocky620
1) WidgetMania and WidgetExpress accounted for more widgets sold than the other 3 internet companies for at least 1 month in 2012. _____________

In the month of Feb, the worldwide average was ~30. So, all the companies put together would have sold 150 widgets. Of these 150, WM & WE sold approx 45 & 48 widgets respectively. So, the remaining three (put together) sold 57 widgets. Hence, TRUE.

A. True
B. False
C. Cannot determine

2) In August 2012, the three widget merchants not specified on the graph sold a total of exactly_______________widgets.

In Aug 2012, the worldwide average was ~50. So, all companies sold 250 widgets. Of these WM & WE sold approx 130 widgets. So, the remaining three sold ~120 widgets. Hence, Option B
A. 54
B. 116
C. 129
D. 147
­
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­Hi nonameleftxxx, I understood what you tried to mention for part A. Actually, we need to see if the sum of WidgetMania and WidgetExpress is greater than the sum of the remaining 3. We are not looking for which merchant has the highest. Therefore, for the month of February, WE+WM~45+48=93 and the total of the five was ~30*5=150. So, 150-93=57 and 93>57. Thus, it is true.

Hope it helps.
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In 2012, there were 5 internet companies selling widgets worldwide. 29 Jul 2025, 22:46
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But 57 would still be less than the 2 companies put together (~90). it doesnt matter one of the 3 might be individually greater than one of the 2, the sum of 3 is definitely less than sum of 2
nonameleftxxx
Here, in part A, As the remaining put together is 57, there is a possibility that one of the 3 companies sold 50 and the other two sold 3 and 4 respectively? [I believe the answer should be 'C' Cannot Determine]
rocky620
1) WidgetMania and WidgetExpress accounted for more widgets sold than the other 3 internet companies for at least 1 month in 2012. _____________

In the month of Feb, the worldwide average was ~30. So, all the companies put together would have sold 150 widgets. Of these 150, WM & WE sold approx 45 & 48 widgets respectively. So, the remaining three (put together) sold 57 widgets. Hence, TRUE.

A. True
B. False
C. Cannot determine

2) In August 2012, the three widget merchants not specified on the graph sold a total of exactly_______________widgets.

In Aug 2012, the worldwide average was ~50. So, all companies sold 250 widgets. Of these WM & WE sold approx 130 widgets. So, the remaining three sold ~120 widgets. Hence, Option B
A. 54
B. 116
C. 129
D. 147
­
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In 2012, there were 5 internet companies selling widgets worldwide. 06 Nov 2025, 03:56
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If anyone want a quant style approach to make things simpler.

a+b+c+d+e = 5*avg

c + d + e = 5*avg - (a+b)

Q1 a + b > c + d + e ?
a + b > 5*avg - (a+b)
a+b > 2.5*avg

look for values in graph where a and b are high and avg is less in comparison, Feb seems like it substitute a,b, avg
45 + 48 > 2.5 * 30 ?
Yes. So choose True

Q2
c + d + e = 5*avg - (a+b)
5*50 - (60+70)
250 - 130 = 120 (if u observe graph, avg is slightly less than 50)
So 116 makes sense for this
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In 2012, there were 5 internet companies selling widgets worldwide. 08 Nov 2025, 22:19
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I feel like question 1 should mention that its more than the other 3 *combined*, or else it can cause someone to maybe assume that each of the three company separately all did worse than WidgetMania and WidgetExpress. But I guess, it is implied in the question to combine WidgetMania and WidgetExpress, so the other three should be combined too. Ugh, if I saw this in a real test the wording would really give me a pretty massive anxiety attack. lol.
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