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Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
07 Oct 2014, 09:13
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D
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Tough and Tricky questions: Ratios
In a certain solution consisting of only two chemicals, for every 3 milliliters of Chemical A, there are 7 milliliters of Chemical B. After 10 milliliters of Chemical C are added to this solution, what is the ratio of the quantities of Chemical A to Chemical C?
(1) Before Chemical C was added, there were 50 milliliters of solution.
(2) After Chemical C was added, there were 60 milliliters of solution.
07 Oct 2014, 09:22
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Bunuel
Oh well...I have been dying to get some time to come back to GC...
We need to find ration of qty of Chemical A and Chemical B..
Given Chemical A : Chemical B::3:7
So to find ratio of qty of Chem A to Chem C we need to have some relation between the A and C
St 1 says: Before C added, There was 50 milliters of soln...We can find A and B and then find A:C. Sufficient..Don't go about solving for real qty ratio.
Option B,C and E ruled out
St 2 says : After C is added..total soln is of 60 millilitres..It is same information as St 1 so this is also sufficinet
Ans is D.
07 Oct 2014, 09:25
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The information given, states that the ratio of chemical A to B is 3 to 7 mL, we can rewrite as 3:7 or 3x:7x. We added 10 mL of solution C.
To find the ratio of chemical A to chemical C, we need to find the total volume of the solution before C was added.
(1) Before Chemical C was added, there were 50 milliliters of solution.
We have the total volume of the solution before C was added.
since the proportion is 3 mL to 7 mL or 3x and 7x, we need to solve for x in order to find the total volume for chemical A.
10x = 50
x = 5
The volume of chemical A is 3*5 and is equal to 15 mL.
Therefore the proportion of chemical A to chemical C is 15 mL to 10 mL, or 3:2. sufficient.
(2) After Chemical C was added, there were 60 milliliters of solution.
From this statement, we can solve for the total volume of the solution before C was added.
We can use the same method used for statement 1 to find the answer to the question. sufficient.
the answer is D.
time needed to figure out the answer - 7 seconds.
To find the ratio of chemical A to chemical C, we need to find the total volume of the solution before C was added.
(1) Before Chemical C was added, there were 50 milliliters of solution.
We have the total volume of the solution before C was added.
since the proportion is 3 mL to 7 mL or 3x and 7x, we need to solve for x in order to find the total volume for chemical A.
10x = 50
x = 5
The volume of chemical A is 3*5 and is equal to 15 mL.
Therefore the proportion of chemical A to chemical C is 15 mL to 10 mL, or 3:2. sufficient.
(2) After Chemical C was added, there were 60 milliliters of solution.
From this statement, we can solve for the total volume of the solution before C was added.
We can use the same method used for statement 1 to find the answer to the question. sufficient.
the answer is D.
time needed to figure out the answer - 7 seconds.
