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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # In the decimal notation of number (2/23)^3. What is the thir

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Director  Joined: 14 Jan 2007
Posts: 574
In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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2
32 00:00

Difficulty:   45% (medium)

Question Stats: 65% (01:37) correct 35% (02:03) wrong based on 539 sessions

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In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

Originally posted by vshaunak@gmail.com on 30 Jun 2007, 08:49.
Last edited by Bunuel on 31 Dec 2012, 04:31, edited 1 time in total.
Renamed the topic and edited the question.
Math Expert V
Joined: 02 Sep 2009
Posts: 58954
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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25
18
vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

Notice that $$(\frac{2}{23})^3<(\frac{2}{20})^3$$.

Now, $$(\frac{2}{20})^3=(\frac{1}{10})^3=0.001$$.

Finally, since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.

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Intern  Joined: 05 Jun 2011
Posts: 12
Schools: Kellog, Stern, Stanford, Booth,HBS, Wharton
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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Is there a recommended spot to conceptually study how to approach problems like this?

How to notice these situations and to approximate as Bunuel did, ya know? Is Bunuel's approach the preferred method or is there a "book" approach to these styles of questions?
Manager  Status: How easy it is?
Joined: 09 Nov 2012
Posts: 85
Location: India
Concentration: Operations, General Management
GMAT 1: 650 Q50 V27 GMAT 2: 710 Q49 V37 GPA: 3.5
WE: Operations (Other)
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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2
IvanW wrote:
Is there a recommended spot to conceptually study how to approach problems like this?

How to notice these situations and to approximate as Bunuel did, ya know? Is Bunuel's approach the preferred method or is there a "book" approach to these styles of questions?

There can be numerous ways to solve such questions. IMO, Bunuel approach is the best and you should follow that. But, end of the day what strikes you under timed conditions is the what matters. I suggest, to develop acumen for such questions, follow Bunuel and understand his approach for every question he responds to. 90% of times you will find that he has solved the questions in a much easier way. Initially, you will find his approach too hard to digest, but when you keep on seeing his methods, you will probably start thinking on the same lines.

Hope it helps!
Senior Manager  Joined: 08 Apr 2012
Posts: 324
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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1
Bunuel wrote:
vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

Notice that $$(\frac{2}{23})^3<(\frac{2}{20})^3$$.

Now, $$(\frac{2}{20})^3=(\frac{1}{10})^3=0.001$$.

Finally, since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.

Hi Bunuel,
Can you give another way to solve this?
I get stuck on questions such as this....
I wasn't able to see the approximation that you saw....
SVP  Joined: 06 Sep 2013
Posts: 1553
Concentration: Finance
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

(2/23)^3 = (2^3)* (1/23)^3 = 8 * (0.05^3). Third digit will be 0.
Cheers!
J Intern  Joined: 16 Jul 2014
Posts: 35
In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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I got stuck and just couldn't find the shortcut to this question so I just tried the dumb method of doing long division. 23^3 took me 10 seconds, 2^3 was memorized. As soon as I tried long division of 8/12167, I figured out the trick. There were a lot of zeros before I could reach a number large enough to be divided by 12167 even once.

For anyone who still don't get it, just try solving the problem the dumb way by finding the numerator, denominator, and then doing long division. This question is one of those questions that you just have to start doing to understand what the "trick" is.
Manager  S
Joined: 03 Aug 2015
Posts: 51
Concentration: Strategy, Technology
Schools: ISB '18, SPJ GMBA '17
GMAT 1: 680 Q48 V35 Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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sumande wrote:
vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

a. 0
b. 1
c. 2
d. 4
e. 8

Is there any quick approach without solving it completely?

The first digit after the decimal point in (2/23) is 0. That is something like 0.0x, which is equal to 0.x * (10^-1). Therefore, the third power will be (0.x)^3 * (10^-3). And, hence, the third digit to the right of the decimal point is 0. Choice A.

Bunel,

Even i have used this sort of method to calculate.

But is it reliable on all the cases?

Pls help

Thanks,
A Intern  S
Joined: 06 Aug 2017
Posts: 22
Location: India
GMAT 1: 660 Q47 V34 Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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3
1
Simple and quickest approach:

(2/23) - > (0.0x..) no need to calculate after x

(0.0x..)^3 -> (0.000z....) (one 0 will multiply 3 times when cubed)

Therefore the third digit after the decimal point is 0.
Intern  B
Joined: 07 Jul 2018
Posts: 44
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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Bunuel wrote:
vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

Notice that $$(\frac{2}{23})^3<(\frac{2}{20})^3$$.

Now, $$(\frac{2}{20})^3=(\frac{1}{10})^3=0.001$$.

Finally, since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.

Didn't get this at all:
"since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.
"

How can you say that just because it is 1 in another case, it will be 0 in another number which is shorter? I am missing something.
Can you please explain in detail? Thanks.
Math Expert V
Joined: 02 Sep 2009
Posts: 58954
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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1
Akshit03 wrote:
Bunuel wrote:
vshaunak@gmail.com wrote:
In the decimal notation of number (2/23)^3. What is the third digit to the right of the decimal point?

A. 0
B. 1
C. 2
D. 4
E. 8

Notice that $$(\frac{2}{23})^3<(\frac{2}{20})^3$$.

Now, $$(\frac{2}{20})^3=(\frac{1}{10})^3=0.001$$.

Finally, since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.

Didn't get this at all:
"since $$(\frac{2}{23})^3<0.001$$, then the third digit to the right of the decimal point of $$(\frac{2}{23})^3$$ is 0.
"

How can you say that just because it is 1 in another case, it will be 0 in another number which is shorter? I am missing something.
Can you please explain in detail? Thanks.

Check any positive number less than 0.001. You'll see that the third digit to the right of the decimal point will be 0.
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Intern  B
Joined: 25 May 2019
Posts: 5
Location: United States
Concentration: Finance
Re: In the decimal notation of number (2/23)^3. What is the thir  [#permalink]

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1
Hi,

Is there any other way to solve this question? Re: In the decimal notation of number (2/23)^3. What is the thir   [#permalink] 13 Jun 2019, 11:25
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