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In the figure above, (a + b + c)/(s + t + u) =

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In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 03:10
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In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

[Reveal] Spoiler:
Attachment:
2017-08-12_1405.png
2017-08-12_1405.png [ 7.15 KiB | Viewed 412 times ]
[Reveal] Spoiler: OA

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Kudos [?]: 128621 [0], given: 12180

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In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 03:55
Bunuel wrote:
Image
In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

[Reveal] Spoiler:
Attachment:
2017-08-12_1405.png

Interior angles sum to 180
a + b + c = 180
Exterior angles sum to 360
s + t + u = 360

(a + b + c)/(s + t + u) = 180/380

\(\frac{180}{360}\) = \(\frac{1}{2}\)

OR (exterior angle = sum of two non-adjacent angles)

b + c = s
a + c = t
a + b = u

b + c + a + c + a + b = s + t + u

2(a + b + c) = (s + t + u)

2(a + b + c)/(s + t + u) = 1

(a + b + c)/(s + t + u) = 1/2

Answer B

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In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 04:02
Bunuel wrote:
Image
In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

[Reveal] Spoiler:
Attachment:
2017-08-12_1405.png

Can be solved Using the properties of exterior angles of triangle.

Exterior angle of a triangle is equal to the sum of the two non-adjacent interior angles of the triangle.

\(s = b + c\)
\(t = a + c\)
\(u = a + b\)

\(s + t + u = b + c + a + c + a + b => 2a + 2b + 2c\)

\(s + t + u = 2 (a + b + c)\)

\(\frac{(a + b + c)}{(s + t + u)} = \frac{(a + b + c)}{2(a + b + c)} = \frac{1}{2}\)

Answer (B)...

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Re: In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 04:16
Top Contributor
Bunuel wrote:
Image
In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

[Reveal] Spoiler:
Attachment:
2017-08-12_1405.png



\(\frac{(a + b + c)}{(s + t + u)}\)=\(\frac{180}{(180-a+180-b+180-c)}\)=\(\frac{180}{3*180-(a+b+c)}\)=\(\frac{180}{3*180-180}\)=\(\frac{180}{2*180}\)=\(\frac{1}{2}\)

Correct Answer B
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Re: In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 04:30
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take any random value for a,b and c say a30, b120, c 30. and sum of a,b,c is 180
accordingly s ,t, u will be 180-30, 180-120, 180- 30 i.e. 150,60 and 150 and thoer sum will be 360
(a+b+c)/ (r+s+t) = 180/360 =1/2 which is option B
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Re: In the figure above, (a + b + c)/(s + t + u) = [#permalink]

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New post 12 Aug 2017, 08:32
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In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

s=b+c
t=c+a
u=b+a
a+b+c =180

therefore, a+b+c / s+t+u = (a+b+c) / 2 (a+b+c) = 1/2

Kudos [?]: 1 [1], given: 1

Re: In the figure above, (a + b + c)/(s + t + u) =   [#permalink] 12 Aug 2017, 08:32
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In the figure above, (a + b + c)/(s + t + u) =

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