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Bunuel

In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

Attachment:
2017-08-12_1405.png


\(\frac{(a + b + c)}{(s + t + u)}\)=\(\frac{180}{(180-a+180-b+180-c)}\)=\(\frac{180}{3*180-(a+b+c)}\)=\(\frac{180}{3*180-180}\)=\(\frac{180}{2*180}\)=\(\frac{1}{2}\)

Correct Answer B
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take any random value for a,b and c say a30, b120, c 30. and sum of a,b,c is 180
accordingly s ,t, u will be 180-30, 180-120, 180- 30 i.e. 150,60 and 150 and thoer sum will be 360
(a+b+c)/ (r+s+t) = 180/360 =1/2 which is option B
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In the figure above, (a + b + c)/(s + t + u) =

(A) 1/3
(B) 1/2
(C) 2/3
(D) 1
(E) 3/2

s=b+c
t=c+a
u=b+a
a+b+c =180

therefore, a+b+c / s+t+u = (a+b+c) / 2 (a+b+c) = 1/2
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Hello from the GMAT Club BumpBot!

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