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In the figure above, l1||l2. What is the area of ADC?

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In the figure above, l1||l2. What is the area of ADC?  [#permalink]

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New post 13 Mar 2018, 07:16
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In the figure above \(l_1||l_2\). What is the area of ADC?

(1) AD = 9

(2) BE*AC = 24

Attachment:
2018-03-13_1813.png
2018-03-13_1813.png [ 9.58 KiB | Viewed 514 times ]

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Re: In the figure above, l1||l2. What is the area of ADC?  [#permalink]

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New post 13 Mar 2018, 07:17
Bunuel wrote:
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In the figure above \(l_1||l_2\). What is the area of ADC?

(1) AD = 9

(2) BE*AC = 24

Attachment:
2018-03-13_1813.png



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Re: In the figure above, l1||l2. What is the area of ADC?  [#permalink]

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New post 13 Mar 2018, 07:29
IMO B

Even for the 'tilted' triangle ADC.
Base is AC and height is BE. ( Draw a perpendicular line from D to line L2 to visualise )

Hence area = 0.5 times base times height.

Hence B.

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Re: In the figure above, l1||l2. What is the area of ADC?  [#permalink]

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New post 13 Mar 2018, 07:32
Area of Triangle = 0.5*b*h
As both triangle ABC and ADC share the same base , and are bounded by two parallel line leading to equal height for each.
Their area would be same.
Statement 1 : AD= 9 , give only information about the one side , so it is insufficient to calculate the area of ADC.
Statement 2 : BE*AC = 24, Area of triangle ABC would be given 0.5* BE*AC so area of triangle of ABC would be 12.
as Area of ABC = ADC, so area of ADC will be also 12.
So statement 2 alone is sufficient so answer would be B
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Re: In the figure above, l1||l2. What is the area of ADC?  [#permalink]

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New post 13 Mar 2018, 10:38
The area of triangles having same base and between same parallel lines are equal.hence,B is the right answer
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Re: In the figure above, l1||l2. What is the area of ADC? &nbs [#permalink] 13 Mar 2018, 10:38
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