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Is x-y+1 greater than x+y-1 ?

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Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 30 Sep 2010, 21:11
4
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A
B
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Question Stats:

75% (01:05) correct 25% (01:22) wrong based on 668 sessions

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Is x-y+1 greater than x+y-1 ?

(1) x > 0
(2) y < 0

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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 30 Apr 2012, 08:58
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 30 Sep 2010, 21:25
1
Michmax3 wrote:
Is x-y+1 greater than x+y-1

1) x>0
2) y<0


Is x-y+1 > x+y-1

1-y > y-1 => This is possible only if y is negative.

Hence B is sufficient.
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 30 Sep 2010, 21:32
2
Michmax3 wrote:
Is x-y+1 greater than x+y-1

1) x>0
2) y<0


x-y+1 > x+y-1
1-y > y-1
2y < 2
y < 1

1) does not talk about x. Insufficient
2) implies y<1.
Sufficient

Answer : b
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 01 Oct 2010, 07:46
shrouded1 wrote:
Michmax3 wrote:
Is x-y+1 greater than x+y-1

1) x>0
2) y<0


x-y+1 > x+y-1
1-y > y-1
2y < 2
y < 1

1) does not talk about x. Insufficient
2) implies y<1.
Sufficient

Answer : b


Morning!

I'm just beginning to study for the GMAT and have a very weak quant background. I answered this question correctly but it took me 5 minutes to do so. I need to find ways to save time, could you explain to me why you noted that "1) does not talk about x. Insufficient" ? It seems like you removed choice A quickly.

This is probably a terribly novice question but I'm a novice so, I hope you don't mind!

Cheers,
f
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 01 Oct 2010, 08:10
1
fronds wrote:
shrouded1 wrote:
Michmax3 wrote:
Is x-y+1 greater than x+y-1

1) x>0
2) y<0


x-y+1 > x+y-1
1-y > y-1
2y < 2
y < 1

1) does not talk about x. Insufficient
2) implies y<1.
Sufficient

Answer : b


Morning!

I'm just beginning to study for the GMAT and have a very weak quant background. I answered this question correctly but it took me 5 minutes to do so. I need to find ways to save time, could you explain to me why you noted that "1) does not talk about x. Insufficient" ? It seems like you removed choice A quickly.

This is probably a terribly novice question but I'm a novice so, I hope you don't mind!

Cheers,
f


After manipulating the question stem (subtracting x on both sides) we are only left with y to determine...since Statement 1 gives x but says nothing about y, which is what we are looking for it is immediately insufficient
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x – y + 1 greater than x + y – 1  [#permalink]

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New post 17 Mar 2012, 23:13
1
Is x – y + 1 greater than x + y – 1?
(1) x > 0
(2) y < 0

I saw a reply somewhere that simplifies the given equation as:
x – y + 1 > x + y – 1 (Canceling xon both sides)
y < 1

But my question is how we can cancel x as we don't know whether x is positive or negative?
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Re: x – y + 1 greater than x + y – 1  [#permalink]

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New post 17 Mar 2012, 23:23
Two things :

1) I think you're thinking on lines of multiplying/dividing by x for inequalities, which can be done without flipping inequality sign only when we know whether the number is positive.

2) Even if the sign of x is not given, you know that on both sides of inequality the sign of x is same so you can cancel that out.
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Re: x – y + 1 greater than x + y – 1  [#permalink]

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New post 17 Mar 2012, 23:37
subhashghosh wrote:
Two things :

1) I think you're thinking on lines of multiplying/dividing by x for inequalities, which can be done without flipping inequality sign only when we know whether the number is positive.

2) Even if the sign of x is not given, you know that on both sides of inequality the sign of x is same so you can cancel that out.


Subhash .. thanks for your reply .. Does this mean that we need to consider the positive/negative scenario ONLY in case we are multiplying/dividing the equation by a variable? So in this case, we dont need to consider the positive/negative scenario.
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Re: x – y + 1 greater than x + y – 1  [#permalink]

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New post 17 Mar 2012, 23:40
Subhash .. thanks for your reply .. Does this mean that we need to consider the positive/negative scenario ONLY in case we are multiplying/dividing the equation by a variable? Yes, in case of inequalities, for equalities it doesn't matter.

So in this case, we dont need to consider the positive/negative scenario. No
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 01 Sep 2014, 09:52
Hi Bunuel,

y<1 can also mean y=0 right.. how can we assume y<1 is equal to y<0?
please clarify if i am missing some point..
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 01 Sep 2014, 09:55
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janani28 wrote:
Hi Bunuel,

y<1 can also mean y=0 right.. how can we assume y<1 is equal to y<0?
please clarify if i am missing some point..


The question asks whether y is less than 1. The second statement says that y is a negative number, so it must be less than 1.

Does this make sense?
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 28 Oct 2015, 19:58
3
Is x-y+1>x+y-1?

On rearranging the variables,
we get 2>2y? or simply y<1?

Hence our new question stem becomes: Is y less than 1?

Statement 1: x > 0. No information about y. NOT SUFFICIENT
Statement 2: y < 0. From this, we can safely say that y will be less than 1
SUFFICIENT

Option B
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 14 Jul 2016, 04:53
Where can I practice more of these qsn types??I was not able to think of simplifying the qsn stem ,really need to work on Inequalities
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 14 Jul 2016, 05:02
1
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bhamini1 wrote:
Where can I practice more of these qsn types??I was not able to think of simplifying the qsn stem ,really need to work on Inequalities


Check below links:

Inequalities Made Easy!

Solving Quadratic Inequalities - Graphic Approach
Inequality tips

DS Inequalities Problems
PS Inequalities Problems

700+ Inequalities problems

inequalities-trick-91482.html
data-suff-inequalities-109078.html
range-for-variable-x-in-a-given-inequality-109468.html
everything-is-less-than-zero-108884.html
graphic-approach-to-problems-with-inequalities-68037.html

Hope it helps.
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 14 Jul 2016, 05:21
Michmax3 wrote:
Is x-y+1 greater than x+y-1 ?

(1) x > 0
(2) y < 0


x-y+1>x+y-1

-y>y-2
-2y>-2
y<1 ??

For all values of y<1 x-y+1 greater than x+y-1.

In option B if y<0, it will be less than 1 and hence sufficient to answer the question
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 25 Oct 2017, 18:09
what if the value of Y is in between 1 and 0? then second statement does not hold? please clarify
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 28 Mar 2018, 03:05
What is the difficulty level of this question?
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Re: Is x-y+1 greater than x+y-1 ?  [#permalink]

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New post 28 Mar 2018, 03:11
kritikalal wrote:
What is the difficulty level of this question?


You can check difficulty level of a question along with the stats on it in the first post. The difficulty level of a question is calculated automatically based on the timer stats from the users which attempted the question. For this particular question it's sub-700 level.
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Re: Is x-y+1 greater than x+y-1 ? &nbs [#permalink] 28 Mar 2018, 03:11
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