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05 Sep 2011, 20:48
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
62% (01:53) correct
38%
(02:05)
wrong
based on 271
sessions
History
Date
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Not Attempted Yet
13 Jan 2012, 14:34
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shashankp27
Is y - x > 1/(x-y)?
(1) ┃x - y┃ > 1
(2) y > x
(1) ┃x - y┃ > 1
(2) y > x
Is y-x>1/(x-y)?
(1) |x-y|>1 --> well this one is clearly insufficient, try x-y=2 to get a NO answer and x-y=-2 to get an YES answer (notice that both examples satisfy┃x-y|>1). Not sufficient.
(2) y>x --> this can be rewritten as y-x>0 or 0>x-y, which means that LHS=y-x=positive and RHS=1/(x-y)=negative, thus y-x>1/(x-y). Sufficient.
Answer: B.
General Discussion
07 Sep 2011, 12:02
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\(y-x > \frac{1}{-(y-x)}?\)
\(3 > \frac{1}{-3} ... true\)
\(-3 > \frac{1}{3} .... false\)
(1) |x-y| = |y-x| .... this is a fact i.e. |3| = |-3|
\(|y-x| > 1\)
insufficient because the value of "y-x" can be 3 or -3, so we can't answer the question.
(2) \(y > x\)
so "y-x" will always be +ve. this is also a fact because the difference between a bigger term and a smaller term is always +ve.
e.g. 3-2=1 (+ve) ... likewise ... -2-(-3)=1 (+ve)
\(y-x > \frac{1}{-(y-x) ?}\)
the above expression will always be true because LHS is always +ve and RHS is always -ve. sufficient.
B is the ans.
\(3 > \frac{1}{-3} ... true\)
\(-3 > \frac{1}{3} .... false\)
(1) |x-y| = |y-x| .... this is a fact i.e. |3| = |-3|
\(|y-x| > 1\)
insufficient because the value of "y-x" can be 3 or -3, so we can't answer the question.
(2) \(y > x\)
so "y-x" will always be +ve. this is also a fact because the difference between a bigger term and a smaller term is always +ve.
e.g. 3-2=1 (+ve) ... likewise ... -2-(-3)=1 (+ve)
\(y-x > \frac{1}{-(y-x) ?}\)
the above expression will always be true because LHS is always +ve and RHS is always -ve. sufficient.
B is the ans.
