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Wow!! Thanks guys!
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WOW. I got my first KUDOS!!!! Need many to get free tests.
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.

Dear Bunuel,

And the first factor of any number(>=0) is 1. am I right?

thanks
Sid
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.

Dear Bunuel,

And the first factor of any number(>=0) is 1. am I right?

thanks
Sid

Yes, the smallest factor, the smallest positive divisor of any positive integer is 1.
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.
Hi,
Then why LCM of two numbers not zero?
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.
Hi,
Then why LCM of two numbers not zero?

By definition the lowest common multiple of two integers a and b is the smallest positive integer that is a multiple both of a and of b.
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Quote:
By definition the lowest common multiple of two integers a and b is the smallest positive integer that is a multiple both of a and of b.
Thanks Bunuel
One more doubt: Can LCM, HCF be stated for -ve numbers: for eg. what is the LCM of -36,-12 or HCF of -12,+36 ?
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.

Dear Bunuel, Does zero (0) consider as consecutive even integers? (0)(2)(4)(6)(8)
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Bunuel
siyer
I just got a question on a practice test wrong because I didn't consider 0 (zero) to be a multiple of 5 (or any integer for that matter). So, what's the rule on the GMAT?

Do we consider 0 to be a multiple of every number?

An integer \(a\) is a multiple of an integer \(b\) means that \(\frac{a}{b}=integer\): so, as 0 divided by any integer (except zero itself) yields an integer then yes, zero is a multiple of every integer.

Also on GMAT when we are told that \(a\) is divisible by \(b\) (or which is the same: "\(a\) is multiple of \(b\)", or "\(b\) is a factor of \(a\)"), we can say that:
1. \(a\) is an integer;
2. \(b\) is an integer;
3. \(\frac{a}{b}=integer\).

Hope it helps.

Dear Bunuel, Does zero (0) consider as consecutive even integers? (0)(2)(4)(6)(8)

0 is an even integer, so it can be a part of the sequence of even numbers.
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Hi Bunuel ,

A quick one.

Suppose a=4.5, b=1.5; a/b would still be an integer.
So unless mentioned in the question about the nature of "a" and "b", shouldn't we consider fractions as well for Data Sufficiency questions?

Really appreciate your time!

Cheers,
Sushil
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Sushil_Sali15
Hi Bunuel ,

A quick one.

Suppose a=4.5, b=1.5; a/b would still be an integer.
So unless mentioned in the question about the nature of "a" and "b", shouldn't we consider fractions as well for Data Sufficiency questions?

Really appreciate your time!

Cheers,
Sushil

Every GMAT divisibility question will tell you in advance that any unknowns represent positive integers (ALL GMAT divisibility questions are limited to positive integers only).

So, a proper GMAT question won't tell you that a is divisible by b without saying that a and b are positive integers.
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Zero can not be counted as a multiple of all numbers.
Simple explanation is here:

Consider 0 as a multiple of 5 and a multiple of 7.
Then LCM(5,7)=0
Which is obviously wrong.

I have another explanation too.
But I guess this is enough.
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