GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Nov 2018, 00:55

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
  • FREE Quant Workshop by e-GMAT!

     November 18, 2018

     November 18, 2018

     07:00 AM PST

     09:00 AM PST

    Get personalized insights on how to achieve your Target Quant Score. November 18th, 7 AM PST
  • How to QUICKLY Solve GMAT Questions - GMAT Club Chat

     November 20, 2018

     November 20, 2018

     09:00 AM PST

     10:00 AM PST

    The reward for signing up with the registration form and attending the chat is: 6 free examPAL quizzes to practice your new skills after the chat.

M08-07

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 50621
M08-07  [#permalink]

Show Tags

New post 15 Sep 2014, 23:36
3
10
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

66% (03:14) correct 34% (01:45) wrong based on 164 sessions

HideShow timer Statistics

Among 200 people, 56% like strawberry jam, 44% like apple jam, and 40% like raspberry jam. If 30% of the people like both strawberry and apple jam, what is the largest possible number of people who like raspberry jam but do not like either strawberry or apple jam?

A. 20
B. 60
C. 80
D. 86
E. 92

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 50621
Re M08-07  [#permalink]

Show Tags

New post 15 Sep 2014, 23:36
2
3
Official Solution:

Among 200 people, 56% like strawberry jam, 44% like apple jam, and 40% like raspberry jam. If 30% of the people like both strawberry and apple jam, what is the largest possible number of people who like raspberry jam but do not like either strawberry or apple jam?

A. 20
B. 60
C. 80
D. 86
E. 92


Look at the diagram below:

Image

Notice that "30% of the people like both strawberry and apple jam" doesn't mean that among these 30% (60) cannot be some people who like raspberry as well. Both strawberry and apple jam is the intersection of these two groups, if we refer to the diagram it's the yellow segment in it.

Next, no formula is needed to solve this question: 112 like strawberry jam, 88 like apple jam, 60 people like both strawberry and apple jam. So the # of people who like either strawberry or apple (or both) is \(112+88-60=140\) (on the diagram it the area covered by Strawberry and Apple). So there are TOTAL of \(200-140=60\) people left who "do not like either strawberry or apple jam". Can ALL these 60 people like raspberry? As \(\text{Raspberry}=80 \ge 60\), then why not! So, maximum # of people who like raspberry and don't like either strawberry or apple jam is 60 (grey segment on the diagram). Notice here that in this case the # of people who like none of the 3 jams (area outside three circles) will be zero.

Side note: minimum # of people who like raspberry and don't like either strawberry or apple jam would be zero (consider Raspberry circle inside Strawberry and/or Apples circles). In this case those 60 people (who "do not like either strawberry or apple jam") will be those who like none of the 3 jams.


Answer: B
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Manager
Manager
avatar
Joined: 14 Jul 2014
Posts: 93
Re: M08-07  [#permalink]

Show Tags

New post 11 Mar 2015, 21:08
Hi Bunuel

I marked B

Can you pls advise if my method mentioned below is correct?

Total = R + A + S - (Sum of Exactly 2 group overlap) - 2 (All 3 )
200 = 80 + 88 + 112 - 60 - 2 (All 3 )

Solving we get: (All 3) = 10

Since R = 80 and (All 3 ) = 10, then Max Raspberry can have = 70
But since 70 is not mentioned in the options, the next best answer would be 60

Is this method correct?

Thanks
Intern
Intern
avatar
Joined: 28 Jan 2015
Posts: 15
GMAT 1: 710 Q49 V38
GPA: 3.35
WE: Marketing (Education)
M08-07  [#permalink]

Show Tags

New post 21 Apr 2015, 00:55
2
Hi buddyisraelgmat,
If you don't mind, let me try to answer why your solution is wrong.

Your equation:
Total = R + A + S - (Sum of Exactly 2 group overlap) - 2 (All 3 )

As Bunuel stated, "Notice that "30% of the people like both strawberry and apple jam" doesn't mean that among these 30% (60) cannot be some people who like raspberry as well."

Key Error: It was wrong for you to put the value 60 as "exactly those who like apple and strawberry only". The sixty could include those who like Strawberry, Apple, AND Raspberry. This error led you to multiply the number of those who like all (All 3) by 2.

Your equation should have been,
Total =R + A + S - (Sum of 2 groups) - (All 3)
200 = 112 + 88 + 80 - 60 - x
x = 20. This means that of the 60 who like both apple and strawberry, 20 like raspberry too.

Therefore number of people who like raspberry only is 80-20 =60

I'm no GMAT expert but I hope my explanation makes sense to you and is right. lol
Manager
Manager
avatar
Joined: 17 Mar 2015
Posts: 116
Re: M08-07  [#permalink]

Show Tags

New post 03 May 2015, 02:00
3
1
I like your way of doing it bunuel but its much easier to keep with the formulas :P
In case everyone in this group likes at least one jam (the case of max)
Image
112+88+80-(60-x)-z-y-2*x = 200
x+y+z = 20
So the resulting amount of people is 80-20 = 60 who could like raspberry jam but not any other.
Current Student
avatar
Joined: 29 Apr 2014
Posts: 120
Location: Viet Nam
Concentration: Finance, Technology
GMAT 1: 640 Q50 V26
GMAT 2: 660 Q51 V27
GMAT 3: 680 Q50 V31
GMAT 4: 710 Q50 V35
GMAT 5: 760 Q50 V42
Reviews Badge
M08-07  [#permalink]

Show Tags

New post 29 Jul 2015, 15:27
1
I do not quite understand the bolded phrase "number of ppl who like Ras, but do not like either Straw or App". Does it mean that we count the number of ppl who like only Ras, or we count the number of ppl who like Ras but do not like both Straw and App.

If the former is the case, then I agree that maximum number should be 60.

But if the latter is the case, then the correct answer should be 80, right?


P/s: I think the former is the case. But why the question did not use " the number of ppl who like only Ras". It would be much easier to understand. I was confused about "do not like either Straw or App" and chose the incorrect answer :(.
Intern
Intern
avatar
Joined: 22 Jan 2014
Posts: 6
Premium Member
Re M08-07  [#permalink]

Show Tags

New post 12 Sep 2015, 07:26
I think this is a poor-quality question and I don't agree with the explanation. Largest possible number of people who like Raspberry only, would contain 0 people who like Raspberry & Strawberry; Raspberry & Apple and Raspberry, Stawberry and Apple. So maximum number is 40% of 200=80. I do not agree with the explanation.
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 50621
Re: M08-07  [#permalink]

Show Tags

New post 13 Sep 2015, 03:40
sidney123 wrote:
I think this is a poor-quality question and I don't agree with the explanation. Largest possible number of people who like Raspberry only, would contain 0 people who like Raspberry & Strawberry; Raspberry & Apple and Raspberry, Stawberry and Apple. So maximum number is 40% of 200=80. I do not agree with the explanation.


That's not correct. Check alternative solutions here: among-200-people-56-like-strawberry-jam-44-like-apple-66692.html

Hope it helps.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Senior Manager
Senior Manager
User avatar
S
Joined: 08 Jun 2015
Posts: 435
Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
GPA: 3.33
Premium Member
Re: M08-07  [#permalink]

Show Tags

New post 21 Oct 2015, 22:19
Dear bunuel,

Thanks for the detailed reply. I have one doubt however, is it assumed that at least one person likes all three types of jams ? In case no , then can we not have a situation where 80 people like only Raspberry jam and 60 like both apple and strawberry jams ? The answer in such case would be 80 and not 60 ?

Looking forward to a reply. Thanks in advance
_________________

" The few , the fearless "

Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 50621
Re: M08-07  [#permalink]

Show Tags

New post 21 Oct 2015, 22:30
spetznaz wrote:
Dear bunuel,

Thanks for the detailed reply. I have one doubt however, is it assumed that at least one person likes all three types of jams ? In case no , then can we not have a situation where 80 people like only Raspberry jam and 60 like both apple and strawberry jams ? The answer in such case would be 80 and not 60 ?

Looking forward to a reply. Thanks in advance


It's not possible 80 people to like raspberry jam but do not like either strawberry or apple jam because in this case the total number of people would be 80 + 140 = 220 > 200.

Hope it's clear.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Intern
Intern
avatar
B
Joined: 25 Nov 2015
Posts: 7
Location: United States (CA)
GMAT 1: 660 Q39 V41
GMAT 2: 670 Q39 V42
GMAT 3: 690 Q41 V42
GMAT 4: 700 Q49 V37
GMAT 5: 720 Q47 V41
GPA: 2.92
WE: Corporate Finance (Real Estate)
Re: M08-07  [#permalink]

Show Tags

New post 26 Nov 2015, 14:41
tronghieu1987 wrote:
I do not quite understand the bolded phrase "number of ppl who like Ras, but do not like either Straw or App". Does it mean that we count the number of ppl who like only Ras, or we count the number of ppl who like Ras but do not like both Straw and App.

If the former is the case, then I agree that maximum number should be 60.

But if the latter is the case, then the correct answer should be 80, right?


P/s: I think the former is the case. But why the question did not use " the number of ppl who like only Ras". It would be much easier to understand. I was confused about "do not like either Straw or App" and chose the incorrect answer :(.



This was my exact thought too. I thought the question was asking for the # of people who like Rasberry only, # of people who like Rasberry & Strawberry and # of people who like Rasberry & Apple.
Manager
Manager
User avatar
Joined: 11 Oct 2013
Posts: 106
Concentration: Marketing, General Management
GMAT 1: 600 Q41 V31
GMAT ToolKit User
Re: M08-07  [#permalink]

Show Tags

New post 18 Dec 2015, 09:20
1
Zhenek wrote:
I like your way of doing it bunuel but its much easier to keep with the formulas :P
In case everyone in this group likes at least one jam (the case of max)
Image
112+88+80-(60-x)-z-y-2*x = 200
x+y+z = 20
So the resulting amount of people is 80-20 = 60 who could like raspberry jam but not any other.


We wouldn't need y and z. Since we are trying to find teh largest possible value, assume x and y to be 0.

Assume total to be 100
100 = 56 + 44 + 40 - (30 - x) - 2x
100 = 110 - x
x = 10.

Double the total and value of x.
Total = 2*100 = 200
x = 10*2 = 20.
Final answer - 40*2-20 = 60 :)
_________________

Its not over..

Intern
Intern
User avatar
Joined: 22 Aug 2014
Posts: 43
GMAT ToolKit User
Re: M08-07  [#permalink]

Show Tags

New post 13 Jan 2016, 06:46
First, assume that Rasberry is isolated circle not having any combined portion. If so, answer would be 40% of 200=80. But is it?
Lets check. If so, (112+88-60)+80=220, but you can't exceed 200,that is total number. So, rasberry must have combined portion by 20. Since we need only such people who like rasberry but don't like others, we must deduct 20 from 80. 80-20=60.
Alternatively,
112 +88-60=140
But we have 200 people in total. So, 200-140=60 gives us our desired portion.
Manager
Manager
User avatar
B
Status: Remember to Always Think Twice
Joined: 04 Nov 2014
Posts: 54
Location: India
GMAT 1: 740 Q49 V40
GPA: 3.51
GMAT ToolKit User Premium Member
Re: M08-07  [#permalink]

Show Tags

New post 20 Feb 2016, 04:06
This is a good question and like always, a good question has an easier solution. (without Venn diagrams)
First let's consider that there are 100 people in sample space as we are processing percentage data.
So draw a line, write 0 at left end and 100 at the right extreme end (baseline)
56 people like strawberry, so draw a line above the baseline starting from the left end (0) to a point more than half of the original line and write 56 at the right end of this line.
As per the question we need to maximize the number of raspberry liking fellows who do not like strawberry and apple.
So we will try to maximize the people who like both strawberry and apple.
Now apple is liked by 44 people and 30 percent like both apple and strawberry.
So draw another line on top of the raspberry line starting from left end and draw till value 30.
Now the remaining 14 apple lovers will be drawn after 56 (previous extent of raspberry lovers)
so from 56, draw a line til 70. (70 - 56 = 14)
So now we have fitted apple and raspberry as per the question.
Now from 70 to 100 we have an open space of 30, where 30 of the 40 raspberry lovers can find peace.
So in 100 people, 30 is the maximum number of required raspberry lovers and hence in 200 they will double to 60.
Thats the answer.
_________________

breathe in.. and breathe out!

Manager
Manager
User avatar
Joined: 12 Jan 2015
Posts: 200
Re: M08-07  [#permalink]

Show Tags

New post 18 May 2016, 23:47
Zhenek wrote:
I like your way of doing it bunuel but its much easier to keep with the formulas :P
In case everyone in this group likes at least one jam (the case of max)
Image
112+88+80-(60-x)-z-y-2*x = 200
x+y+z = 20
So the resulting amount of people is 80-20 = 60 who could like raspberry jam but not any other.


Hi chetan2u,

I am wondering, why can't we take X, Y and z as 0
the question asks- LARGEST possible number of people who like raspberry jam but do not like either strawberry or apple jam?

If we take X, Y and z as 0 then the largest no can be 80 as well.. :roll:

What I am missing..?
_________________

Thanks and Regards,
Prakhar

Math Expert
User avatar
V
Joined: 02 Aug 2009
Posts: 7035
Re: M08-07  [#permalink]

Show Tags

New post 19 May 2016, 00:30
PrakharGMAT wrote:
Zhenek wrote:
I like your way of doing it bunuel but its much easier to keep with the formulas :P
In case everyone in this group likes at least one jam (the case of max)
Image
112+88+80-(60-x)-z-y-2*x = 200
x+y+z = 20
So the resulting amount of people is 80-20 = 60 who could like raspberry jam but not any other.


Hi chetan2u,

I am wondering, why can't we take X, Y and z as 0
the question asks- LARGEST possible number of people who like raspberry jam but do not like either strawberry or apple jam?

If we take X, Y and z as 0 then the largest no can be 80 as well.. :roll:

What I am missing..?


Yes, you can do that, BUT there is a restriction on TOTAL, which is 200...
If you make all these x, y and z as 0...
this means 60 are COMMON only to S and A..
so total number of S and A = 112 + 88 - 60 = 140..
Now this leaves 200-140 = 60 for R, but that number is 80..


so the numbers do not match..
Therefore you will have to find the OVERLAP, as it has to be there to fit in all our quantities
_________________

1) Absolute modulus : http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


GMAT online Tutor

Intern
Intern
avatar
Joined: 10 Oct 2016
Posts: 3
Re: M08-07  [#permalink]

Show Tags

New post 12 Dec 2016, 08:42
Why cant we have Raspberry completely as a separate circle (max value 80)
It is not told in the question that all 3 circles need to intersect.
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 50621
Re: M08-07  [#permalink]

Show Tags

New post 12 Dec 2016, 10:09
maitysourav wrote:
Why cant we have Raspberry completely as a separate circle (max value 80)
It is not told in the question that all 3 circles need to intersect.


It's not possible 80 people to like raspberry jam but do not like either strawberry or apple jam because in this case the total number of people would be 80 + 140 = 220 > 200.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Intern
Intern
avatar
B
Joined: 22 Apr 2018
Posts: 4
Premium Member
Re: M08-07  [#permalink]

Show Tags

New post 11 Sep 2018, 08:35
Absolutely!! I felt the same.

tronghieu1987 wrote:
I do not quite understand the bolded phrase "number of ppl who like Ras, but do not like either Straw or App". Does it mean that we count the number of ppl who like only Ras, or we count the number of ppl who like Ras but do not like both Straw and App.

If the former is the case, then I agree that maximum number should be 60.

But if the latter is the case, then the correct answer should be 80, right?


P/s: I think the former is the case. But why the question did not use " the number of ppl who like only Ras". It would be much easier to understand. I was confused about "do not like either Straw or App" and chose the incorrect answer :(.
GMAT Club Bot
Re: M08-07 &nbs [#permalink] 11 Sep 2018, 08:35
Display posts from previous: Sort by

M08-07

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel



Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.