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# M60-07

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 8017
GMAT 1: 760 Q51 V42
GPA: 3.82
M60-07  [#permalink]

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11 Jun 2018, 02:55
00:00

Difficulty:

55% (hard)

Question Stats:

47% (01:42) correct 53% (01:32) wrong based on 17 sessions

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If $$x > y > 0$$, is $$y < 2?$$

1) $$1/x = 1/2$$

2) $$(1/x)+(1/y) =1$$

_________________
MathRevolution: Finish GMAT Quant Section with 10 minutes to spare
The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy.
"Only $79 for 1 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 8017 GMAT 1: 760 Q51 V42 GPA: 3.82 Re M60-07 [#permalink] ### Show Tags 11 Jun 2018, 02:55 Official Solution: Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Since we have 2 variables ($$x$$ and $$y$$) and 1 equation $$( x > y$$), D is most likely to be the answer. Condition 1) $$1/x = 1/2$$ implies that $$x = 2$$. Since $$x > y$$, we must have $$y < 2$$. Condition 1) is sufficient. Condition 2) The original condition $$x > y > 0$$ implies that $$1/x < 1/y$$. Using $$1/x + 1/y = 1$$ and $$1/x < 1/y$$ together, we can see that $$1/y > 1/2$$. Thus, $$0 < y < 2$$. Condition 2) is sufficient. Therefore, the answer is D. Answer: D _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 1 month Online Course"
"Free Resources-30 day online access & Diagnostic Test"
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Joined: 18 Nov 2014
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Re M60-07  [#permalink]

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18 Jan 2019, 02:30
I think this is a high-quality question and I agree with explanation. good explanation
Intern
Joined: 24 Nov 2017
Posts: 2
Re: M60-07  [#permalink]

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19 Feb 2019, 18:04
1
MathRevolution wrote:
Official Solution:

Using $$1/x + 1/y = 1$$ and $$1/x < 1/y$$ together, we can see that $$1/y > 1/2$$.

Thus, $$0 < y < 2$$.

Condition 2) is sufficient.

Therefore, the answer is D.

Answer: D

Hi, could you please expand on how the two equations result in the inequality 1/y>1/2?

Thank you
Intern
Joined: 03 Feb 2019
Posts: 2
Re: M60-07  [#permalink]

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06 Mar 2019, 05:19
awjpca wrote:
MathRevolution wrote:
Official Solution:

Using $$1/x + 1/y = 1$$ and $$1/x < 1/y$$ together, we can see that $$1/y > 1/2$$.

Thus, $$0 < y < 2$$.

Condition 2) is sufficient.

Therefore, the answer is D.

Answer: D

Hi, could you please expand on how the two equations result in the inequality 1/y>1/2?

Thank you

I would also be grateful if you could expand on this!
Intern
Joined: 08 Jul 2018
Posts: 2
GMAT 1: 580 Q44 V26
GMAT 2: 640 Q45 V33
M60-07  [#permalink]

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09 Apr 2019, 02:47
2
Caroline1606 wrote:
awjpca wrote:
MathRevolution wrote:
Official Solution:

Using $$1/x + 1/y = 1$$ and $$1/x < 1/y$$ together, we can see that $$1/y > 1/2$$.

Thus, $$0 < y < 2$$.

Condition 2) is sufficient.

Therefore, the answer is D.

Answer: D

Hi, could you please expand on how the two equations result in the inequality 1/y>1/2?

Thank you

I would also be grateful if you could expand on this!

1/X +1/Y =1. And 1/X<1/Y. One of the 2 numbers has got to be greater than 1/2 right for both the equations to be possible? Now since 1/X<1/Y, 1/Y is the number that is greater than 1/2. That's how you get 1/Y>1/2. So the second equation is also SUFFICIENT
Intern
Joined: 23 Apr 2019
Posts: 1
Re M60-07  [#permalink]

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03 May 2019, 06:23
I think this is a poor-quality question and I don't agree with the explanation. I believe that this question is flawed as both statements can be true at the same time in order to get the same solution. As I understand, statements can not contradict in GMAT, please check.
Intern
Joined: 23 May 2019
Posts: 3
Re M60-07  [#permalink]

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24 May 2019, 02:27
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. Please elaborate on how statement 2 is sufficient by itself.
Thanks in advance.
Intern
Joined: 25 Sep 2018
Posts: 2
Re: M60-07  [#permalink]

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31 Jul 2019, 00:34
the statement 1 is sufficient.

But for Statement 2 i dont agree with the solution.
If we solve the statement 2 we get (x+y)/xy=1 ---> (x+y)-xy=0 this tells us that x=y=2 or x=y=0 and neither of it holds true as in the question it is given as x>y>0 and not x≥y. So the 2nd statement contradicts the info given in the question fact itself.

please correct me if I am wrong
Re: M60-07   [#permalink] 31 Jul 2019, 00:34
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# M60-07

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