|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
30 Jun 2015, 04:43
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:57) correct
10%
(02:06)
wrong
based on 138
sessions
History
Date
Time
Result
Not Attempted Yet
Martin buys a pencil and a notebook for 80 cents. At the same store, Gloria buys a notebook and an eraser for $1.20, and Zachary buys a pencil and an eraser for 70 cents. How much would it cost to buy three pencils, three notebooks, and three erasers? (Assume that there is no volume discount.)
A. 135
B. 240
C. 270
D. 405
E. 540
Kudos for a correct solution.
A. 135
B. 240
C. 270
D. 405
E. 540
Kudos for a correct solution.
30 Jun 2015, 04:58
Kudos
Bookmarks
Martin buys a pencil and a notebook for 80 cents. At the same store, Gloria buys a notebook and an eraser for $1.20, and Zachary buys a pencil and an eraser for 70 cents. How much would it cost to buy three pencils, three notebooks, and three erasers? (Assume that there is no volume discount.)
A. 135
B. 240
C. 270
D. 405
E. 540
Solution -
Martin buys -> Pencil+Note=80 ------1
Gloria buys -> Note+Eraser=120 ----2
Zachary buys->Pencil+Eraser=70 ----3
1+2+3, 2Pencil+2Note+2Eraser=270 --> 1Pencil+1Note+1Eraser=135
3Pencil+3Note+3Eraser=405 cents . ANS D
A. 135
B. 240
C. 270
D. 405
E. 540
Solution -
Martin buys -> Pencil+Note=80 ------1
Gloria buys -> Note+Eraser=120 ----2
Zachary buys->Pencil+Eraser=70 ----3
1+2+3, 2Pencil+2Note+2Eraser=270 --> 1Pencil+1Note+1Eraser=135
3Pencil+3Note+3Eraser=405 cents . ANS D
kvazar
Joined: 13 May 2011
Last visit: 28 Dec 2018
Posts: 170
Given Kudos: 93
Concentration: Strategy, Technology
Schools: Kellogg '18 (A) Booth '18 (M$) Stanford '18 (D) Wharton '18 (D) Haas '18 (D) Duke '18 (WD) Tuck '18 (A) Sloan '18 (D) Anderson '18 (A)
GMAT 1: 750 Q49 V42
GPA: 3.2
WE:Accounting (Consulting)
Products:
Schools: Kellogg '18 (A) Booth '18 (M$) Stanford '18 (D) Wharton '18 (D) Haas '18 (D) Duke '18 (WD) Tuck '18 (A) Sloan '18 (D) Anderson '18 (A)
GMAT 1: 750 Q49 V42
Posts: 170
Algebraic solution:
(p+n)+(e+n)+(p+e) = 80 + 120 + 70
2p+2n+2e = 270
2(p+n+e)=270
(p+n+e) = 135
3(p+n+e) = 405
Answer
Table solution:
(p+n)+(e+n)+(p+e) = 80 + 120 + 70
2p+2n+2e = 270
2(p+n+e)=270
(p+n+e) = 135
3(p+n+e) = 405
Answer
Table solution:
Attachments
2p+2e+2n.png [ 6.08 KiB | Viewed 5155 times ]
