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Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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26 Mar 2013, 07:14
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Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N? (1) If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint. (2) If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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26 Mar 2013, 10:06
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mun23 wrote: Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N?
(1)If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint.
(2)If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
Need help The number of Peppermint candies = x, Of Spearmint= Nx. From F.S 1 , we have (N1)/5 = (x1) or 5x  N = 4. Insufficient. From F.S 2, we have (N2)/4 = x or N  4x = 2. Insufficient. Taken together, we can get a particular value for N. Sufficient. C.
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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16 May 2013, 10:52
mun23 wrote: Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N?
(1)If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint.
(2)If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
Need help Stmt1: 2 unknowns one equation stmt2 : 2 unknowns and one equation combine both 2 equations and 2 unknowns so C



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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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16 Aug 2013, 05:22
mun23 wrote: Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N?
(1)If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint.
(2)If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
Need help can any body help me here, may be I am missing something but even with using both the statements I am not able to get the value of N P +S= N 1) \(\frac{1(N1)}{5}= P1 \rightarrow N= 5P4\) 2) \(\frac{1(N2)}{4} = S2 \rightarrow N= 4S6\) Now can anybody show me how to get N ? Appreciate your help Thanks
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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16 Aug 2013, 05:27
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stne wrote: mun23 wrote: Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N?
(1)If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint.
(2)If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
Need help can any body help me here, may be I am missing something but even with using both the statements I am not able to get the value of N P +S= N 1) \(\frac{1(N1)}{5}= P1 \rightarrow N= 5P4\) 2) \(\frac{1(N2)}{4} = S2 \rightarrow N= 4S6\) Now can anybody show me how to get N ? Appreciate your help Thanks The correct equation for the second fact statement would be: \(\frac{1(N2)}{4} = P\) Hope this helps
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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16 Aug 2013, 05:51
mau5 wrote: stne wrote: mun23 wrote: Of the N candies in a bag, some are peppermint and the rest are spearmint.What is the value of N?
(1)If 1 peppermint candy were removed from the N candies,1/5 of the remaining candies would be peppermint.
(2)If 2 spearmint candies were removed from the N candies, 1/4 of the remaining candies would be peppermint.
Need help can any body help me here, may be I am missing something but even with using both the statements I am not able to get the value of N P +S= N 1) \(\frac{1(N1)}{5}= P1 \rightarrow N= 5P4\) 2) \(\frac{1(N2)}{4} = S2 \rightarrow N= 4S6\) Now can anybody show me how to get N ? Appreciate your help Thanks The above part involves peppermints, not spearmints. Hope this helps Thundering Typhoons! Cue for me to take a break. Thank you +1 1) \(\frac{1(N1)}{5}= P1 \rightarrow N= 5P 4\) ..1 2) \(\frac{1(N2)}{4} =P \hs{15} \rightarrow N= 4P+2\) ..2 4P+2 =5P4 p=6 ( Put in 1 or 2 ) Then N= 26
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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18 Jun 2015, 06:46
I put E for this question because I mismanaged to translate the word problem into math.
in (2) I couldnt get all the variables to match into one equation. Why is "S" never part of the equation?



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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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15 Oct 2016, 16:17
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This problem can easily be solved by following the rule that states that to solve for a variable we need the same number of distinct, linear equations as variables. I hope you find my approach "elegant" Question (Given)N = p + s N = ? We have 3 variables and 1 equation Statement 1(p  1)/s = 1/4 When we combine this statement with the given info, we yield 3 variables and 2 equations. Insufficient Statement 2(s  2)/p = 3/1 When we combine this statement with the given info, we yield 3 variables and 2 equations. Insufficient Therefore, we need to combine both statements to get 3 variables and 3 equations. Of course, no need to do the actual calculation. Correct Answer = CBonus Track: In case you REALLY want to know the value of variables: p = 6 and s = 20, thereby N = 26.
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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13 Nov 2017, 05:56
I am having an issue translating Statement 2 for some reason. I am fine on S1 On Statement 2, could I not do \(\frac{(s2)}{(n2)}\) = \(\frac{3}{4}\) (in that 3/4 of remaining candies are Spearmint)?
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Re: Of the N candies in a bag, some are peppermint and the rest are [#permalink]
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13 Nov 2017, 06:17
okay wrote: I am having an issue translating Statement 2 for some reason. I am fine on S1
On Statement 2, could I not do \(\frac{(s2)}{(n2)}\) = \(\frac{3}{4}\) (in that 3/4 of remaining candies are Spearmint)? yes you can.. it also leads to same.. \(\frac{(s2)}{(n2)}\) = \(\frac{3}{4}\).. now s2=(n2)p.. substitute \(\frac{(s2)}{(n2)}=\frac{(n2)p}{n2}=\frac{n2}{n2}\frac{p}{n2}=1\frac{p}{n2}=\frac{3}{4}\)... \(\frac{p}{n2}=1\frac{3}{4}=\frac{1}{4}\) now these is same as the statement II
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