adkikani wrote:
sachinpoovannaQuote:
Used a visual scan technique.
1. In cases where value drop from previous day, % change is going to be -ve so ignoring them. E.g. Day 1 to 2.
2. we have only 2 candidates, Day 2 to 3 and Day 4 to 5., Visual observation says both have same increment over previous day.
But Day 4 to 5 has changed value on a smaller denominator then the Day 2 to 3 ...so it wins.
if someone is not from data analytics field then better calculate to verify.
Quote:
You need to be a little careful here. The question states - percent change in the number of computers assembled has the greatest in magnitude. So your 1st point could get you into trouble but not in this question though!
Can you elaborate your point? We do not care about positive or negative change, just change of magnitude here. Much as a modulus.
What is incorrect about highlighted text?
niks18 chetan2u BunuelCan I not simply look at the bar graph difference ignoring the denominator (earlier value) here? Is there any
efficient way than to calculate step by step % changes for each option ?
Hi...
1) first point about change in %..
You are correct , it has to be taken for all choices. Increase/ decrease does not matter..
The member has been lucky to get away with this flaw and get Correct answer.
2) Do you have to go for each choice..
NO
Just look at the down ones.. 1-2, 3-4, 5-6..
Each day the drop is 4 boxes...
So 4 boxes on the least boxes previous day will win..
Nothing but we have same numerator and we are looking for SMALLEST denominator.. visually the lowest is on 5 day so % on that day = 4/8 *100=50%
Now look for the same in increasing days...increase is of 3 boxes..
On 4-5 day it is lowest so 3/5*100=60%
Our Ans
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