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The marks scored by 50 students of a class are m1, m2, m3 …m50 where m

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raj44
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The marks scored by 50 students of a class are m1, m2, m3 …m50 where m [#permalink] New post   Updated on: 12 Dec 2014, 07:43
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53% (02:06) correct 47% (02:11) wrong based on 146 sessions
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The marks scored by 50 students of a class are m1, m2, m3 …m50 where m1<m2<….m50. Student 1 scored 40 and student 50 scored 90. What is the average score of the class?

(1) No two students scored the same marks and m25=62
(2) The marks of the students follow an arithmetic progression.
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B

Originally posted by raj44 on 12 Dec 2014, 07:11.
Last edited by Bunuel on 12 Dec 2014, 07:43, edited 1 time in total.
Renamed the topic and edited the question.
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Re: The marks scored by 50 students of a class are m1, m2, m3 …m50 where m [#permalink] New post   12 Dec 2014, 09:43
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STAT1 is not sufficient as there can be many possibilities
m1=40, m2 = 41,...m24 = 61, m25=62
or m1 = 40, m2=40.5 and so on

STAT2
m1 = 40 and m50 = 90 and these are in AP so using
Avg of marks of all students = avg of 1st term and last term = (40+90)/2 = 65

So, Answer will be B

hope it helps!


raj44 wrote:
The marks scored by 50 students of a class are m1, m2, m3 …m50 where m1<m2<….m50. Student 1 scored 40 and student 50 scored 90. What is the average score of the class?

(1) No two students scored the same marks and m25=62
(2) The marks of the students follow an arithmetic progression.
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The marks scored by 50 students of a class are m1, m2, m3 …m50 where m [#permalink] New post   06 May 2019, 05:01
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raj44 wrote:
The marks scored by 50 students of a class are m1, m2, m3 …m50 where m1<m2<….m50. Student 1 scored 40 and student 50 scored 90. What is the average score of the class?

(1) No two students scored the same marks and m25=62
(2) The marks of the students follow an arithmetic progression.



Statement 1:
Since marks m₂...m₂₄ and m₂₆...m₄₉ are not known, the average of the 50 marks cannot be determined.
INSUFFICIENT.

Statement 2:
In an arithmetic progression, the distance between successive terms is a CONSTANT.
The result is that the values are EVENLY SPACED.
For any evenly spaced set, average = (biggest term + smallest term)/2.
Thus, the average of the 50 marks = (90+40)/2 = 65.
SUFFICIENT.

The correct answer is B.
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The marks scored by 50 students of a class are m1, m2, m3 …m50 where m [#permalink]
06 May 2019, 05:01
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Bunuel
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