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B
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Difficulty:
65%
(hard)
Question Stats:
56% (02:07) correct
44%
(02:14)
wrong
based on 183
sessions
History
Date
Time
Result
Not Attempted Yet
The marks scored by 50 students of a class are m1, m2, m3 …m50 where m1<m2<….m50. Student 1 scored 40 and student 50 scored 90. What is the average score of the class?
(1) No two students scored the same marks and m25=62
(2) The marks of the students follow an arithmetic progression.
(1) No two students scored the same marks and m25=62
(2) The marks of the students follow an arithmetic progression.
12 Dec 2014, 09:43
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STAT1 is not sufficient as there can be many possibilities
m1=40, m2 = 41,...m24 = 61, m25=62
or m1 = 40, m2=40.5 and so on
STAT2
m1 = 40 and m50 = 90 and these are in AP so using
Avg of marks of all students = avg of 1st term and last term = (40+90)/2 = 65
So, Answer will be B
hope it helps!
m1=40, m2 = 41,...m24 = 61, m25=62
or m1 = 40, m2=40.5 and so on
STAT2
m1 = 40 and m50 = 90 and these are in AP so using
Avg of marks of all students = avg of 1st term and last term = (40+90)/2 = 65
So, Answer will be B
hope it helps!
raj44
udaypratapsingh99
Joined: 12 Jan 2019
Last visit: 11 Nov 2025
Posts: 399
Given Kudos: 372
Location: India
Concentration: Strategy, Leadership
Schools: Fuqua '24 Harvard '24 LBS '24 NTU NUS Said '23 Ross '24 Sloan '24 Stanford '24 Tepper '24 Tuck '24 Wharton '24 Yale '24
GMAT 1: 660 Q47 V34
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Schools: Fuqua '24 Harvard '24 LBS '24 NTU NUS Said '23 Ross '24 Sloan '24 Stanford '24 Tepper '24 Tuck '24 Wharton '24 Yale '24
GMAT 1: 660 Q47 V34
Posts: 399
06 May 2019, 05:01
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raj44
Statement 1:
Since marks m₂...m₂₄ and m₂₆...m₄₉ are not known, the average of the 50 marks cannot be determined.
INSUFFICIENT.
Statement 2:
In an arithmetic progression, the distance between successive terms is a CONSTANT.
The result is that the values are EVENLY SPACED.
For any evenly spaced set, average = (biggest term + smallest term)/2.
Thus, the average of the 50 marks = (90+40)/2 = 65.
SUFFICIENT.
The correct answer is B.
